How Does The Anti-Gravity Wheel Work?

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  • Опубликовано: 15 июл 2022
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    In this video I show you how Maxwell's Wheel works and why it weighs less when it is spinning.
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Комментарии • 1,5 тыс.

  • @cleon_teunissen
    @cleon_teunissen Год назад +382

    On why the scale does not show the peak value when the disc bounces at the end of its tether: I assume the processor of the display is programmed to display an *average* over some time interval, probably half a second or so. Without that smoothing the value in the display would jump all over the place, making it unreadable. So the fact that the display does not show the short duration peak value is not due to 'slow refresh rate', I think. I think the processor may even be programmed to discard short duration peaks.

    • @CharlieKellyEsq
      @CharlieKellyEsq Год назад +12

      Then why is it always at - weight. Even if it the scale is taking an average force over time, the average should be around 0, not -6

    • @cleon_teunissen
      @cleon_teunissen Год назад +23

      @@CharlieKellyEsq Let me quote what I wrote an hour ago: "I assume the processor of the display is programmed to display an average over some time interval, probably half a second or so."
      I estimate that it takes the weight 3 seconds or so from release to the end of its tether. That is *several times longer* than what I gave as a guess for the duration of the averaging window.
      Whatever the actual duration of the averating window is, clearly it is short enough so that the scale has opportunity to show a readable value of around -6

    • @CharlieKellyEsq
      @CharlieKellyEsq Год назад

      @@cleon_teunissen I see, you're a nerd

    • @chitlitlah
      @chitlitlah Год назад +15

      I doubt it. A scale like this isn't really intended to weight things that are bouncing around. You're assuming it uses a relatively complex algorithm to average out a lot of samples taken between updates and tosses out short duration peaks which it would have to do for the display not to increase when the weight bounces (but then what's the point of taking an average if you're going to toss out samples?) when it would be a lot simpler just to take a sample before every update. As long as the thing you're weighing isn't bouncing around, there's not much point in averaging multiple samples.

    • @Philociraptor
      @Philociraptor Год назад +10

      At 7:57 he talks about the spike of force when it reaches it at the bottom.

  • @babybirdhome
    @babybirdhome Год назад +170

    You always come up with tons of amazing content for your channel, but this simple demonstration really drove home a fundamental concept that I only now realize at 49 years old that I had never actually understood. That is phenomenal work!

    • @stolearovigor281
      @stolearovigor281 Год назад +2

      Have you realize that gravity doesn't exist?

    • @3DPeter
      @3DPeter Год назад +1

      This is old school science that i already learned when i was 5! Take a bicycle wheel and try to hold it up at one side of the centre axle.
      You won't be able to hold it upright but as soon you spin the wheel, you can hold it up with only the tip of your finger.
      The reason why you can hold it then is because the centrafugal force moves in all directions so the wheel wants to move in all directions.
      there's even a guy that has a large and real heavy metal wheel on an axle and you can't lift that up with one hand, let alone lift it up above your head,
      but as soon the wheel is spun around, the whole thing weighs almost nothing and then you can swing it with ease above your head.

    • @jcmschott1895
      @jcmschott1895 Год назад +2

      @@3DPeter, when you were 120 years old? OMG! How old are you?

    • @3DPeter
      @3DPeter Год назад

      @@jcmschott1895 ????? where do i say that i'm 120 years old?

    • @jerrywiessner
      @jerrywiessner Год назад +2

      @@3DPeter Use of gyroscope action 120yrs ago.

  • @jacobwcrosby
    @jacobwcrosby Год назад +69

    You need an analog scale for this. Or a scale with a much faster update speed.

    • @ExoticAnimation
      @ExoticAnimation Год назад

      maybe

    • @robbiebouchart1551
      @robbiebouchart1551 Год назад +1

      Start building a spaceship

    • @555104068
      @555104068 Год назад +1

      Ye guess there is an Gravity spike when the Disk is at the lowest Point. Digital Skale is just to Slow

    • @stanleybochenek1862
      @stanleybochenek1862 Год назад

      try 2x speed

    • @carsoncraytor9920
      @carsoncraytor9920 Год назад

      It would be cool if it was a faster scale that could output its data into a line graph

  • @fridaycaliforniaa236
    @fridaycaliforniaa236 Год назад +160

    You should show it with an old scale (mechanical). We should see the thing bounce a bit at the bottom =)

    • @two_number_nines
      @two_number_nines Год назад +11

      no, old scales have too much mass and inertia and would filter out any small spikes in force.

    • @adityaparab3677
      @adityaparab3677 Год назад +2

      the wheel bouncing at the bottom will kill the kinetic energy n inertia by the friction depended on the surface just like you spin rear wheel of a cycle in air n drop it causing it to stop completely

    • @wilhelmbeck8498
      @wilhelmbeck8498 Год назад +7

      @@two_number_nines In some cases, an analogue scale will do the job better.

    • @fridaycaliforniaa236
      @fridaycaliforniaa236 Год назад +1

      @@two_number_nines Oh, ok... ^^

    • @emmanuelpil
      @emmanuelpil Год назад +3

      Just a simple calculation. If the effect of lowering the wheel during 3 seconds is -6 grams; in a bouncing spike of let's 1/10 of a second you would feel a 'weight pulse' of 30*6 = 180 grams. Thats a whole lot It should be visible somehow, but even playing the video in slow motion I don't see any movement(shock) of the balance indicating this

  • @mikefochtman7164
    @mikefochtman7164 Год назад +19

    Another little side measurement. If you put a couple of reflective 'dots' on the rim of the disk and use a high speed camera, we could see that the disk rotation is also constantly accelerating. If the system was made taller and 'fins' added to the disk, you could reach a point where its rotation stops accelerating (and therefore it's downward acceleration zeros). At this point, the scale should return to zero even though the disk is still moving upward/downward.
    So you might have a negative weight shown as it starts to fall, weight returning to zero when the disk isn't spinning any faster, and that positive 'spike' at the bottom of travel when the disk 'bounces'.

    • @jcmschott1895
      @jcmschott1895 Год назад +2

      Nice one, dude! I did some calculations here and if I am not wrong, the angular acceleration is, roughly speaking, proportional to the r radius of the rod and inversely proportional to the mass and the square of the disc radius R. So, for a large disc, maybe you can capture the image with a smartphone camera and analyse the footage with a software called Tracker Motion Analysis. It's for free.

    • @Observ45er
      @Observ45er Год назад

      That acceleration is an important clue to what's happening. The mass of the wheel is effectively bouncing under partial gravity - not in free-fall like a ball, or a person on a tramp, but with an additional effect (transfers of energy) that reduced the effect of gravity allowing it to 'bounce' at less that 1 g..
      .
      It's a real brain-burner, but pretty cool and really causes / requires serious thinking and a darn good understanding of physics..

    • @shauryasingh1685
      @shauryasingh1685 6 месяцев назад

      is the same thing used in a YOYO

    • @isaac7984
      @isaac7984 3 месяца назад

      Nope, you're wrong. I checked the math

  • @Chrmel0
    @Chrmel0 Год назад +365

    How about in a vacuum? It would be cool to see how much longer it will last.

    • @mike1024.
      @mike1024. Год назад +61

      The acceleration I believe would be the same, but I wonder if the friction of the wires around the object is what's really slowing it down instead of air resistance? Hard to say until he tries!

    • @aluiziofjr
      @aluiziofjr Год назад +56

      My guess is that it won't be much different. The sound loss is already minimum and so is the air resistance since it's a round object

    • @blazingguyop
      @blazingguyop Год назад +2

      Little bit more

    • @deletedaccount573
      @deletedaccount573 Год назад +12

      You would get the almost same result bcoz friction uses most of energy(not air) here but with out friction it wouldn't spin like that due to no friction in btw wheel and string....!
      And in zero gravity I think it would be different...

    • @30caratteri
      @30caratteri Год назад +1

      Agreed, Mr. Phoenix

  • @MonkeySimius
    @MonkeySimius Год назад +2

    Oh... That makes sense. I kept waiting for it to peak up while it was at the bottom but it makes sense that the scale just didn't refresh fast enough to register that. I would have had thought that it would have shown a greater force while it was traveling upward... But your explanation for why that wasn't the case was really clear. Good video.

  • @alexcothren5103
    @alexcothren5103 Год назад +3

    This one was very interesting. Thank you for sharing.

  • @eb4661
    @eb4661 Год назад +90

    Very cool! (The “missing” grams on the positive side of scale is collected in the knock when direction change at the bottom - just like one feels operating on a yo-yo.)

    • @tactileslut
      @tactileslut Год назад +1

      In the yoyo style this project looks perfect for simulating perpetual motion.

    • @ImYourProblem
      @ImYourProblem Год назад +4

      Those missing grams are collected when the disk is wound and elevated back up to it's starting position lol.

    • @eb4661
      @eb4661 Год назад +10

      @@ImYourProblem
      No.
      The grams are missing both up and down(!) They are in fact collected in a knock at the bottom.

    • @carultch
      @carultch Год назад +1

      @@eb4661 They would be collected in the knock at the bottom, but that knock at the bottom is in a blindspot of the scale's signal processing capabilities.
      If you could measure with infinite precision, you'd get an average force of zero in the scale, between equivalent points in the cycle.

    • @alansmithee419
      @alansmithee419 Год назад +1

      so is it the case that:
      loss of weight in air * time in air = gain in weight at bottom * time spent turning around at the bottom?

  • @therealdebater
    @therealdebater Год назад +10

    I'd love you to now do an energy analysis of this system. Very often an energy analysis can reveal or clarify many of the weird phenomena of physics. The maths is complicated (for the layman), but the principles are straightforward, so it would be really valuable for a video like this to present the concepts in a more approachable way. A big ask, I appreciate.

    • @descendantofgreeksandroman2505
      @descendantofgreeksandroman2505 6 месяцев назад

      You are close to explain it! The rolling of the disk is extrernal energy that he added to the system. The rest I believe are transformatios of energy and momentum/force/mass relations. Its not a miracle, is explainable (but I have to recall my gymnasium physics)

  • @billfranks6805
    @billfranks6805 7 месяцев назад

    Thank you I've learnt something today please keep your videos coming I really enjoy learning this way

  • @itonyg976
    @itonyg976 Год назад +1

    Man, your channel , your videos, your explanation are Fword AMAZING, please keep it up.

  • @freebazar.online
    @freebazar.online Год назад +3

    Really interesting indeed ! I captured a replication of this experiment by making my own maxwell's wheel at home.

  • @nirodha7028
    @nirodha7028 Год назад +6

    I love the explenation that it is excellerating downwards even when it is moving upwards 👌🏻

    • @Atzanteol1
      @Atzanteol1 Год назад

      But it's *always* accelerating downwards. Even when it's stopped.

    • @samedy00
      @samedy00 Год назад +1

      @@Atzanteol1 no, at the very bottom it's accelerating upward.

    • @davidmudry5622
      @davidmudry5622 Год назад

      @@Atzanteol1 NO NO NO..It is always accelerating UP even when it is stopped. Give your head a shake. Accelerating up in a rocket you get more weight right? But before the rocket takes off you already have weight right? RUclips "Why Gravity is not a Force".

  • @charliesk1
    @charliesk1 Год назад +1

    Really great demonstration! Thanks for creating some awesome content

  • @chrstfer2452
    @chrstfer2452 Год назад +1

    You did a good job explaining on this one. Keep it up.

  • @rosone51178
    @rosone51178 Год назад +26

    I would think with really precise measurements all the forces would cancel out, 10 total seconds at -6 would mean 1 total second at +60, or something to that effect. The refresh rate on the scale didn't show the positive wieght spike because it was only for such a short time.

    • @thierryfaquet7405
      @thierryfaquet7405 Год назад +2

      And you would think wrong. Which is ok as long as you understand it being wrong.

    • @eekee6034
      @eekee6034 Год назад +2

      Seems reasonable; we know that impacts increase force at the expense of time. A bouncing ball would impact the scale. The sudden change in the wheel's direction looks like an impact. Maybe it is, maybe the rotation modifies it. It would be interesting to find out how the characteristics of the strings affect it too. A chart-recording scale would be really useful.

    • @ivarangquist9184
      @ivarangquist9184 Год назад

      @@thierryfaquet7405 Would you please elaborate?

    • @thierryfaquet7405
      @thierryfaquet7405 Год назад

      @@ivarangquist9184 just watch the video ???

    • @flipschwipp6572
      @flipschwipp6572 Год назад +4

      Your thought is exacly right, in the bottom the direction of movement is changing,the whole mass of the flywheel has to be accelerated from downwards motion to upwards motion, the cables get a short peak force they transfer through the contraption, which the scale does not show.

  • @sudanamaru
    @sudanamaru Год назад +3

    Fantastic! The wheel is under partial free fall all the time except it momentarily bounces from the bottom.

  • @EskWIRED
    @EskWIRED Год назад

    This is all very simple. But it is also very mind-bending. Thanks.

  • @darrenoak7187
    @darrenoak7187 9 месяцев назад

    This is an excellent demonstration, thank you .

  • @redryder3721
    @redryder3721 Год назад +5

    Amazing demo, thanks! You showed something surprising and new yet again, I keep learning from your vids.

  • @heisag
    @heisag Год назад +4

    I used this concept to accelrate a flywheel horizontally, and made an action drive by having it bounce/crash into the interior wall of an vehicle at the end of its stroke , transfering the
    forward momentum of the flywheel into forward motion of a vehicle. It worked since this method of accelrating a flywheel forward seemed to have very little recoil. In fact, i didn't
    notice any recoil, but that might have been due to friction in the wheel bearings (lego). It wasn't very effective though, in terms of energy input and forward motion.
    I used rack and pinion at first, with no rack at the end of the stroke. After that, i used spring loaded strings through the axle. Though, i didn't go as far as motorize it. That
    was half a year ago , and i haven't really looked too much into it. Was suspecting that accelrating a flywheel would reduce it weight, so it was nice to see a video that confirms it.

    • @thumper88888
      @thumper88888 5 месяцев назад +1

      In a project book from the ‘60s was a similar toy, rolling a BB around in a film can. On a ramp. The impact moved the box forward overcoming the box/table friction but the rear movement was absorbed by internal friction.

    • @heisag
      @heisag 5 месяцев назад

      @@thumper88888 Thank you. I decided to finally release the video i made of it, poor video, but a picture is worth a 1000 words.
      It is not meant as self-promotion, although i could see it technically be just that. This beeing hidden away deep down a youtube comment section anyway.
      Something are just difficult to describe with words alone.

  • @marklefler4007
    @marklefler4007 6 месяцев назад

    Thanks! Keep up the great videos educating people about science in a fun way.

  • @dorAb2003
    @dorAb2003 Год назад +2

    Awesome episode and really good explanation!

  • @What_The_Fuck_Did_I_Just_Watch
    @What_The_Fuck_Did_I_Just_Watch Год назад +13

    if you're not happy with your weight:
    Just start spinning

    • @MrT------5743
      @MrT------5743 Год назад +3

      More like start falling slowly.

    • @Justafeller
      @Justafeller Год назад +1

      I'm going to slowly fall every time I get on the scale. As a matter of fact, I'm going to start slowly falling everywhere I go.
      Two weeks later....
      Me: "I'm trying to weigh less."
      Psychiatrist: "so the monsters don't get you, right?"

  • @cplatter38
    @cplatter38 Год назад +4

    "My wife is my safety inspector" .... brother... that killed me!! That's awesome!!

    • @ooooneeee
      @ooooneeee Год назад +2

      "Due to some undisclosed incidents" 😂

  • @CaptainKirk01
    @CaptainKirk01 Год назад

    Very Nice! I like visuals of concepts like this. Thank You!

  • @barry7608
    @barry7608 Год назад

    Thanks always learn something from your vids and you’ve never hoaxed on any. Awesome

  • @jesseluna4406
    @jesseluna4406 Год назад +42

    Would have been nice to see the extra weight it had as it bounced back up. Maybe even showing a chart of the -6g and the spiked positive weight when it bounces. I wonder if that could be shown well with a mechanical scale.

    • @AlexGeek
      @AlexGeek Год назад +2

      I think it would be an infinite weight during an infinitely small amount of time.

    • @Sonny_McMacsson
      @Sonny_McMacsson Год назад +6

      @@AlexGeek Not in reality

    • @carultch
      @carultch Год назад +10

      @@AlexGeek Only in the oversimplified world of introductory physics, where rigid bodies are truly rigid and inextensible strings exist. The truth is, all strings, cords, cables, etc, will have some degree of stretching, and due to this, the spike at the bottom will not have an infinite force, in an infinitesimal time.
      Ultimately, Hooke's law would govern the behavior of the strings, as if they were springs with a much larger k-constant, and I would expect a sinusoidal profile of the rebound force as a function of time. The frequency would be in kilohertz or megahertz, and we'd only see a a little over half of this sine wave appear on the plot. We'd also see harmonics to this sine wave, that are governed by the natural frequency of the spring-like elements in the scale, be it actual springs or piezoelectrics, and a damping envelope as the sine wave pulse transitions back to the constant -6 gram reading..

    • @carultch
      @carultch Год назад +3

      Indeed it would be interesting to see the details of this spike, but I don't know what kind of scale would have the time resolution to accurately pick it up.
      From the impulse-momentum theorem, you can infer that the time-average change from zero in the reading on the scale should equal zero, across a time interval between equivalent points in the cycle. No change in the momentum of the center of mass, should mean no net impulse on the system from the scale, other than the baseline impulse needed to oppose the steady impulse of gravity.
      The problem is, that there is such an extreme asymmetry between the time when the scale would read -6 grams, and the time of the rebound spike, that the scale doesn't have enough resolution to pick up the rebound spike, and this biases the readout to show the loss of weight, a lot more than the gain of weight. Maybe if you introduced flexible springs at the top of the strings, to slow down the rebound impulse, you could pick it up on the scale.

    • @andremanicke8534
      @andremanicke8534 Год назад +3

      @@carultch If you change the scale to a pressure sensor and connect it to an oscilloscope you would bei able to see it. The sensors themselves are fast enough, it's only the processing which slows it down.

  • @jp-hh9xq
    @jp-hh9xq Год назад +14

    Wow! I would have bet money that this effect would not occur. I guess there is always an opportunity to learn something new about basic physics. Great video!

    • @PeerAdder
      @PeerAdder 8 дней назад +1

      This is why objects in free fall (such as those in a spaceship orbiting the earth) are described as being "weightless"). All that is happening here is that the disc is falling, but not freely, so it's weight (the force between it and the scale) doesn't go to zero.
      The fact that it is spinning is only relevant in the sense that it is the mechanism this setup uses to slow down the rate of falling. You could achieve the same effect by dropping a mass through a column of a viscous liquid. Use a very viscous material such a _solid_ and the mass will sit on the top of the column and the scale will read its weight as expected. Use a very non-viscous material such as a gas and the mass will fall freely so that the scale only registers its weight properly after it has come to rest at the bottom of the column. Any intermediate viscosity will produce a correspondingly intermediate reading for the weight of the object you are dropping through the column.

    • @jp-hh9xq
      @jp-hh9xq 2 дня назад

      @@PeerAdder That makes total sense. Wasn't intuitive with this arrangement.
      The viscous vs non viscous liquids makes perfect sense and seems to be a good analogy.

  • @user-rx5xu4fn8s
    @user-rx5xu4fn8s Год назад

    Wow! Very interesting effect and excellent explanation. Thanks a lot! 🙏

  • @johnniefujita
    @johnniefujita Год назад +1

    one of the most interesting videos about classical gravity

  • @lotsoffreetime8392
    @lotsoffreetime8392 Год назад +12

    When you discover something interesting and you share it is indeed amazing 🤩

  • @ikocheratcr
    @ikocheratcr Год назад +13

    Interesting effect, first to me.
    In case you want a higher sample rate for the scale, there is a very simple option with an arduino ($5), an HX711 ($5) module and a weight sensor ($5~$20). Then on arduino interface you can plot it directly from serial port data. HX711 can sample at 10samples/s or 80samples/s configurable.

    • @jcmschott1895
      @jcmschott1895 Год назад

      Hey, mate! Is it possible to save it to a file?

  • @gregbell2117
    @gregbell2117 Год назад

    Thanks James for so many amazing videos.

  • @feifeishuishui
    @feifeishuishui Год назад

    Intriguing! At the beginning, I was lost, but then I realized it was kind of like when I was jumping on the scale. Most of the time, I would weight zero, but when I was physically touching the scale, my weight goes up a lot.

  • @user-ti4cm1pn6r
    @user-ti4cm1pn6r Год назад +7

    Acceleration is not always downward. Where Wheel reaches the bottom and roll up, there is acceleration acting upward.

    • @eekee6034
      @eekee6034 Год назад +1

      This might be measured if the scale recorded the mass.

    • @Observ45er
      @Observ45er Год назад

      Here's the deal with this wheel:
      The wheel does NOT *weigh less* when it is spinning!.
      ..
      It may be more correct to say that it weighs less when it is "bouncing".
      ..
      I have a problem with the interpretation of the Laithwaite demo. *Precession does not translate the wheel. It does not lift it.*
      Precession causes the axis of rotation to change direction. This is a *ROTATION* about the center-of-mass of the wheel. It is not lifting the whole wheel's mass.
      .
      Precession does not cause the gyro to *move* (translate) sideways, nor upward in Laithwaite 's case or Veritasium's case.
      If the vertical spinning gyro had translation, it would slide along the table, but stay vertical. It does not do that. It tips, or rotates at 90 degrees.
      The fact that the handle is offset and long has significance. If you push the handle in the direction of the precession, that lifts the handle, right?.
      However the interpretation that the spinning wheel is always accelerating downward even while moving upward, is a very good catch. It took me a few seconds to realize that. My quick initial feeling was that the weight would go positive on the way up. . .
      The way to think of it is that is is 'partly falling' due to gravity. When you are in free-fall you are completely 'weightless'. The spin and string-shaft arrangement allow it to fall, but not fully, as when you are in free-fall. So, the frame experiences somewhere between the full weight and weightless ness, but more weight during the bounce time.
      ..
      *The winding and unwinding of the string causes the up and down motion which is what changes the weight.*
      ..
      Stand on a bathroom scale and at a medium speed, move up and down by bending your knees. Try to move faster and faster on the way down and slower and slower on the way up. You will see your weight decrease during those times.
      .. .. ..
      If you watch carefully, you see that it is speeding-up as it drops; this is accelerating, but not at the full 'gravity-rate'.
      Also, it is slowing-down as it rises, again not fully accelerating (decelerating or negative acceleration) due to gravity.
      ..
      On a trampoline you are completely weightless from the time your feet leave the trampoline until they touch again and start the bounce. During this time you are constantly in 'total' free-fall.
      When in contact with the trampoline you are accelerating upward and weigh more than normal.
      If you can add a small upward force to reduce the acceleration due to gravity, you will weigh less. No surprise there.
      This is analogous to only "partway" jumping on a trampoline (or your bouncing ball). On a tramp, you are accelerating *downward* when your feet are not in contact with the tramp. The ball is when it is not in contact with the floor. The spinning wheel only "partly" leaves the support strings. It is "partially bouncing".
      If the tramp accelerated you upward at twice the rate of gravity, your weight would double.
      Therefore, there is also a slight increase in weight at the bottom bounce.
      .
      This would be equivalent to a small jetpack on your back that can't lift you, but only partly reduces your weight. You would be in "Sloe-Fall", not free-fall.
      ..
      This would make a wonderful Dean Drive Scam. . . .
      ..
      It would be nice to have a real-time force load cell so we can see what happens at the bottom of the wheels travel - the positive weight gain during the short 'bounce' time.
      ..
      Also, WHAT HAPPENS to the weight, if the wheel is NOT spinning, but bouncing while being suspended by a *spring,* instead of the winding/unwinding strings?
      Is that equivalent to this "partial bouncing" effect?

  • @qazmatron
    @qazmatron Год назад +5

    Rough numbers: Its acceleration while falling down (or up) is 6g / 720g x G = 0.00833G or 0.266ft/sec². Its fall time is about 3s, so its peak velocity (just before it bounces) = at (acceleration times time) = 0.8ft/s. The distance traveled = 1/2at² = 1.2ft.

  • @ayushchoubey635
    @ayushchoubey635 Год назад

    Thanks for teaching us physics in such a fun way

  • @user-bh6po3bd1w
    @user-bh6po3bd1w 3 месяца назад +1

    Very cool! Always love your videos!

  • @johnschewe6358
    @johnschewe6358 Год назад +26

    Absolutely yes. It's sometimes counterintuitive that force is in the direction of acceleration even if velocity is in the opposite direction, but that's the truth.
    Makes a bit more sense if you think about it as 99% of the weight is passed through the strings instead of focusing on the 1% that is directly affecting the velocity.

    • @johannesdatblue4164
      @johannesdatblue4164 Год назад +1

      the mass is falling down and converts a small amount of the potential energy into kinetic (small movement downwards) thats why less force pulls on the upper rod. and when it moves upwards it converts still a small amount into kinetic energy (that gets lost in any resistances like air, "sound", heat) even though it seems like it would pull it downwards like if a human jumps on a libra or pulls itself upwards on this rod - in this cas etha mass would increase/decrease depending on the acceleration but because the flywheel of his machine doesnt generate a force (like we do biochemical) the force could never exeed 0 (positive) because the enegry is convertet into other forms until it comes to a stop.
      is that right and if not can you tell me my mistkae in this thought - i kept the old one just that you can see where i was coming from, if im stil wrong at some point. maybe its easier to correct a mistake then - like the mathteachers that told us to write any little thing on this damn paper xD
      first thoughts so keep that in mind, i got a bit closer now: but still its kinda hard to get the upward movement cause if you thin k about yourself hanging at a pipe and slowly let yourself sink it makes sense that not all of your mass or in this case force gets applied to the pipe, because you let yourself sink - if i understand it right you convert your potential energy in kinetic but most of it stays potential or no. if you rest its potential if you move kinetic... oh fuck
      its late tbh and its not my native language aswell.
      the point thats hard to imagine is if you convert all your potential energy in kinetic, you are free falling - kinda, lets keep it simple. but to explain what happens there is. does the spinning of the shaft count to potential energy or ist it kinetic because its "on the move"

    • @johnschewe6358
      @johnschewe6358 Год назад +2

      ​@@johannesdatblue4164 Yes, you're right there are 3 forms of energy here. We've got the potential energy which is the height of the object, kinetic energy from falling, and kinetic energy from spinning.
      When it is riding back up the string gravity is slowing it down 1% more than the kinetic rotational energy is transferring back into the string. So both down and up would show negative on the scale.
      But the real question is there an impulse at the very bottom when it is switching directions that is just so fast that the scale can't read it? Or does the force of the spinner on the string always stay less than the weight of the spinner?

  • @kanpurunplugged9970
    @kanpurunplugged9970 Год назад +4

    actually it's the freely suspended slinky spring drop experiment in disguise

  • @davidhawkins7138
    @davidhawkins7138 Год назад

    This is a great one. Thanks!

  • @Markoul11
    @Markoul11 2 месяца назад +1

    Great video and amazing explanation!!

  • @sbfguy7793
    @sbfguy7793 Год назад +3

    I wonder if weight lifting competitions have rules against spinning weights being used?

  • @arsilvyfish11
    @arsilvyfish11 Год назад +19

    This is one of the best channels when it comes to the topics that he discusses. A great plus is the amazing community that come up with engaging discussions in the comments. Glad to be a part of the Action Lab community!

    • @shinronin7312
      @shinronin7312 Год назад +2

      Yeah i love it too.
      Its just that sometimes im like: eh? Srs someone didnt know that? Then i notice yeah not everyone is spending their free time on such shit. 💋💋❤️❤️💔💔💗💗💗💗💔💔❤️❤️💋💋

    • @jimi02468
      @jimi02468 Год назад +1

      What I always wonder about is how does he come up with the topics for his videos. But whatever the topic it's always something interesting

    • @arsilvyfish11
      @arsilvyfish11 Год назад +1

      @@shinronin7312 lmao

    • @arsilvyfish11
      @arsilvyfish11 Год назад

      @@jimi02468 yup!

  • @bromanultra6364
    @bromanultra6364 Год назад

    Absolutely loved this video!!

  • @aclearlight
    @aclearlight Год назад

    Brilliant work, I love your channel!

  • @eypandabear7483
    @eypandabear7483 Год назад +37

    This is actually a great illustration of Einstein’s equivalence principle. In general relativity, gravity is an inertial pseudo-force. That means: the disc’s weight is actually not gravity acting on its mass, but rather the force with which the scale “accelerates” the disc against its free-fall trajectory.
    So when the disc is allowed (partially) to fall, its weight *must* go down, because it is precisely the force which counteracts that fall.

    • @JebFromWarmDays
      @JebFromWarmDays Год назад +5

      Love this explanation! I always enjoy thinking about how I'm actually accelerating (kind of) upwards at my weight right now haha

    • @paulbrooks4395
      @paulbrooks4395 Год назад +1

      Does this mean it changes weight due to the change in acceleration frame of reference?

    • @tomblakley105
      @tomblakley105 Год назад

      @@paulbrooks4395 yep

    • @tomblakley105
      @tomblakley105 Год назад

      @@rebeuhsin6410 the scale zeros out for a fraction of a second,

    • @kindlin
      @kindlin Год назад

      @@JebFromWarmDays I do believe you're actually accelerating downwards, as gravity "pulls." Another way to think about this, is that someone in orbit is in a perpetual free fall, but you just keep missing the ground over and over again. As you stand on the ground, it does resist that falling motion, so you feel a force in your feet against the ground resisting the gravitational acceleration and keeping you as stationary relative to the slow moving tectonic plates.

  • @XploringMyself
    @XploringMyself Год назад +18

    This concept is similar to hydraulic shock absorbers but in this case its "Gravitational Shock Absorber"

    • @clahey
      @clahey Год назад +3

      No, it's a rotational shock absorber

  • @ahmad-murery
    @ahmad-murery Год назад

    Finally somebody explained those videos,
    Thank you and Thanks to the wife for keeping you safe to bring us these interesting videos.

  • @glenhill9884
    @glenhill9884 Год назад +1

    I am pretty good at physics and caught a lot of this, but some of it went over my head. Still, it was very fascinating. Thanks.
    From the thumbnail, I thought you were going to show whether the scale would register weight of the wheel if it was suspended by magnets. Perhaps do that in a future experiment?

  • @colorado841
    @colorado841 Год назад +14

    I wonder if this method could be exploited to move heavy objects across distances with minimal friction do to gravity.

    • @brads9418
      @brads9418 Год назад +7

      Maybe that’s how the Egyptians built the pyramids!

    • @johnnycash4034
      @johnnycash4034 Год назад +2

      @@brads9418 nooooo! Yes! Yes that's it! OMG!

    • @loganthesaint
      @loganthesaint Год назад +1

      @@johnnycash4034 more likely they used vibrations of some sort.

    • @johnnycash4034
      @johnnycash4034 Год назад +2

      @@loganthesaint nooooo! Yes! Yes absolutely! That's it!

    • @DamianReloaded
      @DamianReloaded Год назад +1

      I was thinking about a crane that used this, but the wheel in this video must weight at least 500g (probably more) and it only loses 6g for a relatively short period and you have to use energy to roll it up. The cases where you'd need to move something that is 1% too heavy are probably no worth the complexity of such a crane.

  • @paulbrooks4395
    @paulbrooks4395 Год назад +5

    So the force exerted at the bottom should be a fraction of the mass based on the multiplier of acceleration due to gravity. If it’s moving at half a G of acceleration, the amount of travel time gives the speed in m/s at the bottom. The speed times mass should give its instantaneous maximum force in gm/m/s-gram meters per second.
    I’m not sure how to calculate the fractional weight loss during the rest of its motion period. I think it’s the instantaneous maximum force divided by the travel time. That should give us a constant in gm or possibly gram/meters?

    • @jcmschott1895
      @jcmschott1895 Год назад

      Hey, mate! I did it taking into account the rotational and linear equations of motion. The weight loss read in the scale is a function of the square of the quotient between the rod radius and the disc radius, if I am not mistaken. You may think of the difference in the scale reading as twice the difference in the tension in the strings and there will be some difference as the disc is put in movement.

  • @alexanderweck181
    @alexanderweck181 Год назад

    Great ! And great Explanation. Thanks for that.

  • @jesucristojesus3676
    @jesucristojesus3676 Год назад

    this is very easy to understand.
    I have known about this for years, and the reason why it goes -w its because of the effect on the string.

  • @colorado841
    @colorado841 Год назад +5

    That explains a lot. I always wondered how fly saucers worked!

    • @arjunravi1641
      @arjunravi1641 Год назад +2

      How?

    • @carultch
      @carultch Год назад

      This has nothing to do with how flying saucers work. Flying saucers are all just a big speculation of what an alien spacecraft might look like.

  • @prabhakaran1981
    @prabhakaran1981 Год назад +3

    You may have a scale for each string and then measure the mass. Each scale may show different value due to the gyroscopic effect. When this wheel rotates in a direction one sting may have less tension and the another one may have tension equal to half (or zero) of the (wheel) mass. But due the change in direction for each cycle, string alters.

    • @dilipdas5777
      @dilipdas5777 Год назад

      Great. I think it's correct explanation

    • @Observ45er
      @Observ45er Год назад

      Nope. Both strings will show the same as long as the horizontal distances from string to center-of-mass are equal.
      ..
      Here's the deal with this wheel:
      The wheel does NOT *weigh less* when it is spinning!.
      ..
      It may be more correct to say that it weighs less when it is "bouncing".
      ..
      I have a problem with the interpretation of the Laithwaite demo. *Precession does not translate the wheel. It does not lift it.*
      Precession causes the axis of rotation to change direction. This is a *ROTATION* about the center-of-mass of the wheel. It is not lifting the whole wheel's mass.
      .
      Precession does not cause the gyro to *move* (translate) sideways, nor upward in Laithwaite 's case or Veritasium's case.
      If the vertical spinning gyro had translation, it would slide along the table, but stay vertical. It does not do that. It tips, or rotates at 90 degrees.
      The fact that the handle is offset and long has significance. If you push the handle in the direction of the precession, that lifts the handle, right?.
      However the interpretation that the spinning wheel is always accelerating downward even while moving upward, is a very good catch. It took me a few seconds to realize that. My quick initial feeling was that the weight would go positive on the way up. . .
      The way to think of it is that is is 'partly falling' due to gravity. When you are in free-fall you are completely 'weightless'. The spin and string-shaft arrangement allow it to fall, but not fully, as when you are in free-fall. So, the frame experiences somewhere between the full weight and weightless ness, but more weight during the bounce time.
      ..
      *The winding and unwinding of the string causes the up and down motion which is what changes the weight.*
      ..
      Stand on a bathroom scale and at a medium speed, move up and down by bending your knees. Try to move faster and faster on the way down and slower and slower on the way up. You will see your weight decrease during those times.
      .. .. ..
      If you watch carefully, you see that it is speeding-up as it drops; this is accelerating, but not at the full 'gravity-rate'.
      Also, it is slowing-down as it rises, again not fully accelerating (decelerating or negative acceleration) due to gravity.
      ..
      On a trampoline you are completely weightless from the time your feet leave the trampoline until they touch again and start the bounce. During this time you are constantly in 'total' free-fall.
      When in contact with the trampoline you are accelerating upward and weigh more than normal.
      If you can add a small upward force to reduce the acceleration due to gravity, you will weigh less. No surprise there.
      This is analogous to only "partway" jumping on a trampoline (or your bouncing ball). On a tramp, you are accelerating *downward* when your feet are not in contact with the tramp. The ball is when it is not in contact with the floor. The spinning wheel only "partly" leaves the support strings. It is "partially bouncing".
      If the tramp accelerated you upward at twice the rate of gravity, your weight would double.
      Therefore, there is also a slight increase in weight at the bottom bounce.
      .
      This would be equivalent to a small jetpack on your back that can't lift you, but only partly reduces your weight. You would be in "Sloe-Fall", not free-fall.
      ..
      This would make a wonderful Dean Drive Scam. . . .
      ..
      It would be nice to have a real-time force load cell so we can see what happens at the bottom of the wheels travel - the positive weight gain during the short 'bounce' time.
      ..
      Also, WHAT HAPPENS to the weight, if the wheel is NOT spinning, but bouncing while being suspended by a *spring,* instead of the winding/unwinding strings?
      Is that equivalent to this "partial bouncing" effect?

    • @Observ45er
      @Observ45er Год назад

      @@dilipdas5777 Here's the deal with this wheel:
      The wheel does NOT *weigh less* when it is spinning!.
      ..
      It may be more correct to say that it weighs less when it is "bouncing".
      ..
      I have a problem with the interpretation of the Laithwaite demo. *Precession does not translate the wheel. It does not lift it.*
      Precession causes the axis of rotation to change direction. This is a *ROTATION* about the center-of-mass of the wheel. It is not lifting the whole wheel's mass.
      .
      Precession does not cause the gyro to *move* (translate) sideways, nor upward in Laithwaite 's case or Veritasium's case.
      If the vertical spinning gyro had translation, it would slide along the table, but stay vertical. It does not do that. It tips, or rotates at 90 degrees.
      The fact that the handle is offset and long has significance. If you push the handle in the direction of the precession, that lifts the handle, right?.
      However the interpretation that the spinning wheel is always accelerating downward even while moving upward, is a very good catch. It took me a few seconds to realize that. My quick initial feeling was that the weight would go positive on the way up. . .
      The way to think of it is that is is 'partly falling' due to gravity. When you are in free-fall you are completely 'weightless'. The spin and string-shaft arrangement allow it to fall, but not fully, as when you are in free-fall. So, the frame experiences somewhere between the full weight and weightless ness, but more weight during the bounce time.
      ..
      *The winding and unwinding of the string causes the up and down motion which is what changes the weight.*
      ..
      Stand on a bathroom scale and at a medium speed, move up and down by bending your knees. Try to move faster and faster on the way down and slower and slower on the way up. You will see your weight decrease during those times.
      .. .. ..
      If you watch carefully, you see that it is speeding-up as it drops; this is accelerating, but not at the full 'gravity-rate'.
      Also, it is slowing-down as it rises, again not fully accelerating (decelerating or negative acceleration) due to gravity.
      ..
      On a trampoline you are completely weightless from the time your feet leave the trampoline until they touch again and start the bounce. During this time you are constantly in 'total' free-fall.
      When in contact with the trampoline you are accelerating upward and weigh more than normal.
      If you can add a small upward force to reduce the acceleration due to gravity, you will weigh less. No surprise there.
      This is analogous to only "partway" jumping on a trampoline (or your bouncing ball). On a tramp, you are accelerating *downward* when your feet are not in contact with the tramp. The ball is when it is not in contact with the floor. The spinning wheel only "partly" leaves the support strings. It is "partially bouncing".
      If the tramp accelerated you upward at twice the rate of gravity, your weight would double.
      Therefore, there is also a slight increase in weight at the bottom bounce.
      .
      This would be equivalent to a small jetpack on your back that can't lift you, but only partly reduces your weight. You would be in "Sloe-Fall", not free-fall.
      ..
      This would make a wonderful Dean Drive Scam. . . .
      ..
      It would be nice to have a real-time force load cell so we can see what happens at the bottom of the wheels travel - the positive weight gain during the short 'bounce' time.
      ..
      Also, WHAT HAPPENS to the weight, if the wheel is NOT spinning, but bouncing while being suspended by a *spring,* instead of the winding/unwinding strings?
      Is that equivalent to this "partial bouncing" effect?

  • @JMWexperience
    @JMWexperience Год назад

    That was fascinating. Thanks!

  • @atomicdmt8763
    @atomicdmt8763 Год назад

    excellent- ill need to figure this out - several times

  • @DANGJOS
    @DANGJOS Год назад +3

    The only thing confusing to me was why the weight didn't increase upon hitting the bottom. I guess the refresh rate was the only reason.

  • @peterwhitey4992
    @peterwhitey4992 Год назад +21

    The rotation has nothing to do with the experiment. You could as well have hung it on a spring. It's similar to standing on a scale and throwing on object into the air. While it's in the air, the scale shows less weight than when you're holding it.

    • @VeteranVandal
      @VeteranVandal Год назад

      Or jumping on a scale.

    • @sequoiahughes8536
      @sequoiahughes8536 Год назад +3

      Well put-that’s a great explanation

    • @mbrusyda9437
      @mbrusyda9437 Год назад

      It does, actually, it introduces the asymmetry between the upward and downward accelerations. Springs don't have that property.

    • @nenhard
      @nenhard Год назад

      So called weight loss yo-yo effect

  • @philkuusisto1558
    @philkuusisto1558 Год назад

    Very interesting, usable information.

  • @TheBradfordG
    @TheBradfordG Год назад

    "undisclosed safety incidents". Comedy gold--thanks for teaching us something along the way!

  • @OriginalMorningStar
    @OriginalMorningStar Год назад +4

    I wonder if this effect contributes to the Chain Fountain physics. Seeing as the chain is technically spinning as it form the loop, and weighs less at that point as a result, this could be the dominant force?

    • @AdrianBoyko
      @AdrianBoyko Год назад +2

      This is a really interesting question! I don’t think that “spinning” figures into the weight reduction (its just an energy storage mechanism) but the chain in a chain fountain is definitely accelerating downward as it changes direction from flying up to flying down. And, surprise, surprise, it’s the decelerating portion of the chain that rises! I think you may have discovered the REAL reason for chain fountains!

    • @u1zha
      @u1zha Год назад

      But chain fountain weighs more, not less, while in operation. Steve Mould had series of videos about the kickback

  • @Cretan1000
    @Cretan1000 Год назад +3

    If you plotted it at a high refresh rate, and looked at the area under the curve of the measured weight, would it average out to zero (slight negative most of the time, very positive for a fraction of a second as it bounces up)?

    • @megamaser
      @megamaser Год назад +2

      Yes, actually it would be slightly positive because energy has mass. But it would be very close to zero

    • @my3dviews
      @my3dviews Год назад

      @@megamaser No. Energy does not have mass. Light is energy and massless. Mass can be converted to energy such as in a nuclear reaction, but that does not mean that energy has mass.
      In the experiment in the video, the mass never changes. What changes is the downward force on the scale due to the change in rotational speed of the wheel. The overall downward force over time is equal to the weight of the wheel. So, while it is changing speed the downward force is less, but at the point where it comes to the end of the strings, there would be a surge to equal out the loss over the rest of the time.
      This would be similar to dropping an object on a bungee cord. When it is falling the force on the connection point would be lower than the weight of the falling object. When it hits the bottom there would be a surge, then it would be lower again on the way up. The overall weight times time would be the same as the weight of the object at rest over an equal amount of time.

    • @megamaser
      @megamaser Год назад

      @@my3dviews Einstein showed that mass and energy are equivalent. Mass is basically a confined form of energy. So yes a free photon has no mass. But if you trap a photon in a box of mirrors then it will add mass to that box. The mass of protons and neutrons primarily comes from the kinetic energy of the quarks, which are confined by the strong force. Adding energy to an object by heating, vibrating, or rotating that object increases its mass.

    • @my3dviews
      @my3dviews Год назад

      @@megamaser Quote: "Einstein showed that mass and energy are equivalent." Wrong. E (energy) = m (mass) x c(speed of light) squared. Notice Einstein's equation is not simply E=m.
      Getting back to your first claim that energy has mass. That is incorrect. Mass can be converted to energy and energy can be converted to mass, but energy itself does not have mass.
      Your last comment even admits that. It says that a photon trapped in a box of mirrors will add mass. That is converting energy into mass, since the photon no longer exists. That is not the same as saying "energy has mass". (it doesn't).

    • @megamaser
      @megamaser Год назад

      @@my3dviews Interesting how you're so sure of yourself but obviously not doing any actual research before making these assertions. I'm only stating some indisputed scientific facts that were established 100 years ago. Anyone with even only a bs in physics should know these things. I'll address your points one by one, but you seem pretty hostile to new ways of thinking, so I'm doubtful that it will be very fruitful. Anyway...
      "Einstein's equation is not simply E=m"
      Actually, it is, essentially. c is only a constant. It's an arbitrary scaling factor that's only used due to the choice of units. He included it mainly to illustrate the insanely large amount of energy in small amounts of mass. But it can be left out without impacting the equivalence. If you choose some other units, then you don't need the scaling factor. It's actually quite common to use energy units to measure mass, such as electron volts.
      Trapping the photon in a box of mirrors does not destroy the photon. It continues to exist, reflecting against the mirrors. If you open the box, the photon will escape. It's a commonly used thought experiment to illustrate mass energy equivalence. There are some nice RUclips videos to visualize this example.
      Converting mass to energy means you have released confined energy. Converting energy to mass means you have confined energy.
      For example, endothermic chemical reactions consume energy to bring electrons into a higher energy level. Usually this is thought of as a conversion from kinetic to potential energy. But that potential energy has mass, we know this because endothermic reactions result in products that have greater rest mass than the reactants, so it can also be considered to be a conversion of energy into mass. But if you consider the heat that was absorbed, it was also contributing mass to whatever was hot, so the overall mass of the entire system is unchanged. The energy was always massive, and the mass was always energy.
      Likewise, exothermic reactions, like fire, can be said to convert mass into energy, because the reactants have greater rest mass than the products. However this lost mass was manifested in the potential energy of electrons, and it actually isn't lost since the thermal energy still contributes mass to the entire system.
      It is a little weird to say that energy "has" mass. I think it's more accurate to say that mass *is* energy. Mass is an emergent phenomenon that results from the confinement of energy.

  • @rxotmfrxotmf8208
    @rxotmfrxotmf8208 7 месяцев назад

    Thanks for another thought-provoking video.

  • @amarmail8033
    @amarmail8033 Год назад

    Really interesting and innovative.... Keep it up man...

  • @rayoflight62
    @rayoflight62 Год назад +7

    Very interesting experiment, I knew about the force vector changing but I never seen so well exposed.
    The cheap scale with too long sampling rate spoiled it a bit.
    Thanks,
    Anthony

  • @revealingfacts4all
    @revealingfacts4all Год назад +5

    Looks to me a couple things are going on here.
    1. Scale update rate is slow compare to actual
    2. There is always a counter acting upward force from the converted potential energy which causes the wheel to climb back up the rope. You'd see the same effect with a spring. The stored potential, as it decreases, is always countering the downward force the scale is measuring.
    In a way, your scale is showing force changes as they occur (well, at a refresh rate the scale is keeping up with).

    • @brads9418
      @brads9418 Год назад +1

      I wonder if the same antigravity effect happens with just a spring.

  • @elarcadenoah9000
    @elarcadenoah9000 Год назад

    i love this youtube channel,God bless u bro

  • @Justwantahover
    @Justwantahover 6 месяцев назад +2

    It's accellerating downwards, making it lighter. And it decellrates upwards and that also makes it lighter. Like braking makes stuff go forward inside a car.

  • @howiestillgamez5326
    @howiestillgamez5326 Год назад +4

    Would the same effect be measured from a pendulum swinging back and forth?

    • @NetAndyCz
      @NetAndyCz Год назад +1

      Maybe, but it would be minor because the pendulum lowers its center of mass only my rather small distance. But I think the same principle would work for weight-driven clocks as well.

    • @carultch
      @carultch Год назад

      When the pendulum bob accelerates upward, there is an apparent gain in weight. When the pendulum bob accelerates downward, there is an apparent loss in weight. The centripetal acceleration is from the rod pulling the bob inward, and the tangential acceleration is from the component of gravity that makes it swing. We can calculate when this will happen by finding the net y-component acceleration, and determining the critical angle where it is zero.
      Given an amplitude angle of A, I derived the following formula for the critical angle theta_crit, where the vertical acceleration switches direction.
      theta_crit = 2*(arctan(sqrt((2 - sqrt(cos^2(A) + 3))/(cos(A) + 1))))
      For small amplitudes, this approaches sqrt(2)/2, or 70.7% of the amplitude angle. For a 30 degree amplitude, it's 69%, or at 20.9 degrees. The critical angle becomes a smaller fraction of the amplitude, the higher the amplitude. The extreme case of a 180 degree amplitude has a divide by zero problem, but we can calculate it for angles arbitrary close to 180 degrees and get that it happens at around 39% of the amplitude.
      Also for small amplitudes, where you can approximate the pendulum as simple harmonic motion, this occurs at the half way point in time between its release point at the amplitude, and the neutral point where it passes through the middle. This means that it spends half its time weighing less than it does at rest, and half its time weighing more than it does at rest, when weight refers to the vertical component of the scale's support force.
      a 30 degree amplitude, it's 69%, or at 20.9 degrees. The critical angle becomes a smaller fraction of the amplitude, the higher the amplitude.

    • @axle.australian.patriot
      @axle.australian.patriot Год назад

      You could exemplify this same effect with an old pendulum clock. Not due to the pendulum but the weights that powered the clock. The weights on strings would have a constant acceleration toward earth until such time as the string completely unwound, then it would resume is natural still weight.

    • @carultch
      @carultch Год назад

      @@axle.australian.patriot You'd get that if you took out the escapement mechanism, and put the hanging weights on ideal pulleys, like Atwood's machine.

    • @axle.australian.patriot
      @axle.australian.patriot Год назад

      @@carultch No, just an old pendulum clock (With wind up weights) will produce exactly the same effect :)

  • @zaphodbeeblebrox2817
    @zaphodbeeblebrox2817 Год назад +13

    I remember a theory of how ufo's work where the ship has a big toroid of mercury. The mercury would flow axially and radially through a section of the toroid. The radial flow in a section is actually axial flow around the whole toroid. So if you could magically move/spin/swirl the mercury, you could control its gravity

    • @vaakdemandante8772
      @vaakdemandante8772 Год назад +1

      It either makes no sense or I don't understand what you've wrote.
      Please rephrase that in terms of a picture / sketch, so I can grasp exactly what you mean by axial / radial flow.

    • @zaphodbeeblebrox2817
      @zaphodbeeblebrox2817 Год назад +1

      @@vaakdemandante8772 a liquid flywheel that can spin on two axes simultaneously

    • @tristanbrandt3886
      @tristanbrandt3886 Год назад +3

      I wonder if quarks, electrons, create gravity with their spin? Get enough of a mass together, and the spin of all those atoms creates a higher density, and therefore higher gravitational force.

    • @reagindoerindo4311
      @reagindoerindo4311 Год назад

      But the flywheel acceleration keeps still. How could the ship zero an external body gravitational acceleration? The flywheel went upward because the downward acceleration winded a wire to roll up. How could a ship ignore a planet gravity and just fly upwards effortlessly, not being winded to anything?
      ... This is one of those unintuitive talks, like quantum physics/mechanics.
      I like it, it makes the brain works.

    • @uriahgibson9022
      @uriahgibson9022 Год назад

      @@tristanbrandt3886 or does the gravity create the quarks and electrons? If there is gravity everywhere there is a quark or electron, what if gravity created them to balance itself or something to that effect. Does the electron or gravity come first or at the same time?

  • @N0_UNITY
    @N0_UNITY Год назад

    holy moly this channel is for big brains i can’t rap my head around half this stuff

  • @grazianoturbogas
    @grazianoturbogas Год назад

    That's huge! It will keep me intriguing for months

  • @frogandspanner
    @frogandspanner Год назад +3

    I remember watching this effect in 1974 in _"The Jabberwock" Eric Laithwaite 1974 RI Christmas Lectures, Lecture 4_ . We looked at this in Physics tutorials during my degree. It's an example of conservation of angular momentum. The angular momentum of the rotating wheel is changing owing to the rotation of the Earth.

  • @OmegaZZ111
    @OmegaZZ111 Год назад +4

    Interesting effect, well shown, thank you!
    Would be interesting to know what the phenomenon of gravity really is and how everything is really tied together.

    • @peterwhitey4992
      @peterwhitey4992 Год назад +2

      It's just bouncing on the scale. If you bounce a ball on a scale, while it's in the air, the scale shows less weight. The rotation of the disc has nothing to do with it. He could as well have used an object on a spring.

    • @OmegaZZ111
      @OmegaZZ111 Год назад +1

      @@peterwhitey4992 I don't think that's the same.
      The scale shows a continuous negative weight, you wont get that from bouncing a ball on a scale.

    • @peterwhitey4992
      @peterwhitey4992 Год назад +1

      @@OmegaZZ111 - It is the same. The scale just doesn't update fast enough, to show the force of the bounce.

    • @OmegaZZ111
      @OmegaZZ111 Год назад +1

      @@peterwhitey4992 The rotating mass and the precession along another axis creates a measurable loss in weight.
      This effect is clearly shown in the video with the rotating flywheel with a handle that is easy to lift when the mass is rotating.
      This is not the same effect as a ball bouncing on a scale.
      It is not about the scales refresh rate, the rotating wheel is actually loosing weight.
      While the mass of an object is constant the weight is dependent on many factors.

    • @carultch
      @carultch Год назад

      @@OmegaZZ111 The rotating and precessing mass doesn't create a loss in weight. It is more like a loss in torque that makes it easier to lift, than a loss in weight. If you weigh yourself while lifting that wheel, you will see no weight loss while the wheel rises at a constant speed. Only a weight loss when you slow it down at the top. You will also see a weight gain at the bottom when you initially lift it. The rotating wheel makes it easier to lift, because you only need to lift against its weight, and don't need to lift against the torque due to its weight.
      You only lose weight in a system in motion, when the center of mass of the system being weighed accelerates downward. Or if you go to another location where the value of g is less.

  • @bob456fk6
    @bob456fk6 6 месяцев назад

    This is amazing!!
    I thought the weight would switch back and forth between plus and minus as the wheel went up and down.
    Newton and Maxwell were pretty clever...this proves it. 🙂

  • @stevewhitt9109
    @stevewhitt9109 7 месяцев назад

    Great Video. Best explanation on RUclips.

  • @God_Save_The_King
    @God_Save_The_King Год назад +3

    Would you be able to connect two pieces of metal just by touching them inside your vacuum machine?

    • @float32
      @float32 Год назад

      I know what you mean, but you might need to explain that a bit more.

    • @arifbagusprakoso2308
      @arifbagusprakoso2308 Год назад +1

      Do you mean 'cold soldering'? That require extremely low impurity (oxidation)... which is hard to do in ActionLab environment.

    • @God_Save_The_King
      @God_Save_The_King Год назад +1

      Well I've heard that if you somehow break/cut a piece of metal into pieces, you could simply put it back together because in a vacuum the surfaces of the metal pieces (where you cut them) wouldn't oxidise/interact with any gases, which are the reason that you can't put it back together in the atmosphere. So in vacuum, without any gases, wouldn't it be possible to put two metal pieces back together?

    • @woodhonky3890
      @woodhonky3890 Год назад +1

      @@God_Save_The_King Good question. I assume you mean if a piece of metal was cut/broken in the vacuum also, and assuming no contamination to the ends. The only thing I can think of is the crystalline structure of the metal could be altered by the cut/break as to not allow the molecules to re-bond. On solid metal, I believe temperature is essential to recombine metals. Mercury loves to go back together as long as it is molten, vacuum or no.

  • @peehandshihtzu
    @peehandshihtzu Год назад +5

    So I've noticed a similar "feeling" of lightening using a chainsaw. Not on smaller saws but on large beefed up saws the act of goosing the throttle seems to have a lightening effect. I always thought it was just a sensation of the focus of the weight of the extended bar shifting closer to the powerhead but now I'm wondering if this has more to do with it. :)

    • @admacdo
      @admacdo Год назад +3

      That's torque reaction. You're supporting the bar and when you give it the beans, the chain spins forward and down, making the bar lift upwards and back due to torque reaction. Same way the front wheel lifts on a motorbike when you give it throttle.

    • @peehandshihtzu
      @peehandshihtzu Год назад

      @@admacdo Right, seems you explain it far better than I, LOL. Similar but not the same I guess. :)

  • @sceptic2061
    @sceptic2061 7 месяцев назад

    I was like, what about the digital frequency to show the measurement, and you delivered! TY!

  • @Sarem89
    @Sarem89 Год назад

    Thank you!

  • @ckEagle165
    @ckEagle165 Год назад +5

    I'm curious about something in a perfect vacuum, all other variables such as gravity, elevation, etc being equal. If you have an item like this creating friction, in air the heat from that friction, plus the sound, has air to travel through. In a vacuum, there's no air to take heat away from the heated friction elements. So technically, shouldn't friction cause the items to slow down faster? I hope my question made sense.

    • @areadenial2343
      @areadenial2343 Год назад +3

      No, friction only converts energy to heat, and it doesn't get "more powerful" as temperature increases. If heat isn't allowed to escape, then the mechanism will just keep accumulating heat until it begins to break down. But you may be surprised to learn that heat does escape in a vacuum! All objects steadily lose their heat as electromagnetic radiation, mostly in the far infrared. This can account for around 30% of heat transfer even in a normal atmosphere. So putting this wheel device in a vacuum won't cause it to lose energy faster, but it might be 0.1 of a degree warmer since that heat will dissipate more slowly.

  • @VeggiePower303
    @VeggiePower303 Год назад +11

    To get Anti Gravity, You need to take two high speed powered gyros on a single horizontal shaft spinning in opposite directions.
    And then power spin the whole thing around the vertical center line of the shaft.
    This creates a self intersecting Torsion field.
    This will allow you to climb up the Gravity well.

    • @phumgwatenagala6606
      @phumgwatenagala6606 Год назад +6

      Build us a proof of concept please!!

    • @q.e.d.9112
      @q.e.d.9112 Год назад +6

      I thought this many years ago but I rather doubt it now. I can’t see how intersecting torsions can produce a translation, but I’m not up to date on physics. A proof of concept wouldn’t be too difficult to make and, if successful, would either get you a Nobel or, possibly, an unfortunate accident on a mountain road.😉

    • @The1stDukeDroklar
      @The1stDukeDroklar Год назад

      @@q.e.d.9112 🤣

    • @feifeishuishui
      @feifeishuishui Год назад

      That won't work. You will get the same weight.

  • @josem138
    @josem138 Год назад

    Ey I do use Notion, notion is great. Thanks for showing it, because is very interesting to organize

  • @Spedley_2142
    @Spedley_2142 Год назад +2

    it would be interesting to see the whole rig on one side of a balancing scale. You'd be able to see the whole thing rise slightly but the jolt at the bottom should put it back to the origjnal position.

  • @amitkriit
    @amitkriit Год назад +7

    At zero, the scale accounts for the tension in the string which is less when the wheel starts to spin, reducing the normal force acting downward at the scale.

  • @id104335409
    @id104335409 Год назад +6

    Time to make a box that holds the disk and spins it up really fast.
    So fast that it lifts it to the negative value of its own weight.
    And break the internet.

    • @MrT------5743
      @MrT------5743 Год назад +2

      It isn't the spinning that cause a decrease in weight though. It is the falling that decreases the weight.

    • @carultch
      @carultch Год назад

      Take it on a roller coaster and perform this experiment at the top of an inverted loop. Then it will appear to lift itself from your point of view.

    • @MrT------5743
      @MrT------5743 Год назад +1

      @@carultch it already appears to lift itself when it is going up from the momentum of the spin.

    • @carultch
      @carultch Год назад +1

      @@MrT------5743 It isn't really lifting itself. It's just that the center of mass is accelerating downward, so it doesn't need as much support to keep it from sinking through the floor. But no matter what you do in this setup in a stationary environment on this planet, its acceleration will be less than g, and it will still compress the scale.
      You would have to have its center of mass accelerate downward at a rate greater than g, for it to lose contact with the pan of the scale. One way you could achieve this, is if you spun a heavy ball on a string so fast, tied to the top of that frame, that the tension in the string at the top of its motion exceeded the weight of the stationary framing. You better adhere it to the scale and fasten the scale to the floor, if you don't want it to fly away.

  • @Ddkrew1
    @Ddkrew1 Год назад

    Congratulations! Keep moving forward!

  • @honestopinion6268
    @honestopinion6268 Год назад

    Thanks for finally explaining the Great Pyramids

  • @TVCHLORD
    @TVCHLORD Год назад +2

    congratulations you discovered a yo-yo

  • @CorvanEssen
    @CorvanEssen Год назад +6

    You've probably also dropped a magnet to a copper or aluminum pipe. The magnet drops really slow due to current in the non magnetic metal. But what would a scale say under the pipe?

    • @VeteranVandal
      @VeteranVandal Год назад +1

      Pipe+magnet mass, basically. Wait... That's actually a way to measure mass while it moves... That might be useful for some application.

    • @johnschewe6358
      @johnschewe6358 Год назад +1

      Whatever percentage of force the magnetic field opposes gravity should be seen in scale at the bottom as something has to be equal and opposite to the force of gravity to slow down it's fall.

    • @VeteranVandal
      @VeteranVandal Год назад +1

      @@johnschewe6358 all of the force opposes it for a long enough pipe, when the falling speed gets constant.

    • @johnschewe6358
      @johnschewe6358 Год назад +2

      @@VeteranVandal Much like how you only feel weightless on an elevator while it's speeding up.

  • @mad_like_a_hatter5469
    @mad_like_a_hatter5469 Год назад +1

    Would be interesting to see it with tapered metal edges and see the result on the weight as it winds up on different angles

  • @sitedrm
    @sitedrm Год назад

    Hahaha, the "safety inspector" bit was a real laugh out loud moment for me

  • @Extrify_
    @Extrify_ Год назад +4

    Tomorrow is my math exam
    But I'm more interested in your channel
    ʘ‿ʘ

  • @Bigman74066
    @Bigman74066 Год назад +5

    If you had a perfect scale that would average the measured weight over a period of say, 10s it would indicate 0g again.

    • @aetius31
      @aetius31 Год назад

      I dont think so, the weight oscillate between -5 and -8 during a long time compared to the full weight spike.
      In fact it will depend on the refresh rate of the scale and for a perfect balance with infine resfresh rate the contribution of the full weight spike would be tiny because the negative moving phase last much longer.

    • @MrT------5743
      @MrT------5743 Год назад

      Even if you could average the weight out from releasing it at the top till it stops at the bottom it wouldn't be 0. Because it lost some of its potential energy. For the time it is falling, it weighs less.

    • @TheActionLab
      @TheActionLab  Год назад +2

      Nope, it never goes into the positive the whole time it is bouncing up and down. This is longer than 1 minutes of bounce time. It is definitely a weight decrease, not some scale averaging effect.

    • @peterwhitey4992
      @peterwhitey4992 Год назад +3

      @@TheActionLab - It does go positive during the bounce, but as you said, the refresh rate of the scale isn't fast enough to show that. It weighs less while going up and down, but weighs more during the bounce. The average over enough time it is of course zero.

    • @aetius31
      @aetius31 Год назад

      @@peterwhitey4992 Nope I explained earlier why and The action lab confirmed it, also keep in mind that it is only true while the wheel is spinning of course

  • @alfredcalleja450
    @alfredcalleja450 Год назад

    I love your work: very interesting.

  • @rowinfun
    @rowinfun Год назад +1

    I would have never thought to put that on a scale!