In mass spectrometry, ion which is reaching to the detector in highest % (not necessarily 100% but some other % say like 85% ) then instrument will call it as base peak and will adjust it's % as 100%, we don't require to calculate it's intensity.
Yes u right it is lacking there must be 6 carbon... If there will be 6 Carbon only then propyl radical will eliminate to form acrolein..if 5th membered then ethyl radical will eliminate. To form acrolein.
11: 17 sir it is written in pavia that 1 4 elimination usually lead to formation of cyclic compound but you have drawn straight chain??? Kindly clear my misunderstanding
Sir may I ask, how to do the mechanism of ch2ch2ch2 that have two radical after the removal of h2o and c2h4 so it gets [ch2=chch3]+. at 16:34 because when I tried to do the mechanism I tend to get the structure without the + and radical.
Pls say donot say u are getting any response as the almighty God will give u blessing as there are many students who will watch your video after two or three years when they will do their master so donot let them deprived of best concept 🙏🙏🙏 pls sir your cordination series i have watched all the video from that day I am biggest fan 🙏🙏🙏🙏 so pls help us sir by sharing your knowledge as we cannot afford to take admn in prestigious institution to get such 🙏🙏🙏🙏🙏 concept
@@TETRAHEDRONCHEMISTRYCLASSES tqqq so much even right now I am watching your video I spend my whole day watching video to complete my msc 🙏🙏🙏🙏 so tqqqq so much meri ishwar se bas yhi pray shiv baba apko swasth nirog rkhe aur apke pura parivar ko apni duwaoooo ki sukrakcha kawach praden kre 🙏 be happy and healthy sir 🙏🙏🙏🙏🙏🙏🙏
Based on analysis of base peak only it is difficult to analyse complete structure, you can identify fragment corresponding to base peak only, plz note that single spectroscopy is not enough to decide the structure of the molecule. For complete characterization of the molecule one should analyse mass, IR, Carbon NMR and H NMR atleast.
Sir could u make the mass spectra of non borane by fragmentation and also make the video on mossbauer spectroscopy and which is the best book for it please send the pdf of it I am not getting it
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You teach far better than my college teachers. Saved my examination. Thank you sir
Superb lecture
How to determine the intensities of the peak sir? How do we say this particular peak is the base peak with respect to relative abundance??
In mass spectrometry, ion which is reaching to the detector in highest % (not necessarily 100% but some other % say like 85% ) then instrument will call it as base peak and will adjust it's % as 100%, we don't require to calculate it's intensity.
Great explanation sir, thanks a lot.
35:56 Is there lacking one carbon atom? The system changed from 6 member ring system into 5 member ring system.
No, all 6 carbons are there plz watch carefully, during alpha cleavage one bond of 6 membered ring breaks.
Your drawing is very tiny, please make lager structures to show bond formation & electron exchange more clearly.
Sure
Yes u right it is lacking there must be 6 carbon... If there will be 6 Carbon only then propyl radical will eliminate to form acrolein..if 5th membered then ethyl radical will eliminate. To form acrolein.
Superb sir
Very nice ly explain
sir u r always great
hi sir, how to get 31 peak at at 25:04?
Sir u r best teacher
Thank you very much🙏🙏🙏
Means in second example there must be a peak of 70...due to dehydration of alcohol..isn't it??
Sir why we didn't see the M-18 peak in secondary alcohol??plz Guide me..
Thank u sir very useful
Good method
sir ۔can you have any idea that how i can download the solution manual of pavia۔۔
I have answers but not solution manual.
11: 17 sir it is written in pavia that 1 4 elimination usually lead to formation of cyclic compound but you have drawn straight chain??? Kindly clear my misunderstanding
It is not always the case.
Sir may I ask, how to do the mechanism of ch2ch2ch2 that have two radical after the removal of h2o and c2h4 so it gets [ch2=chch3]+. at 16:34 because when I tried to do the mechanism I tend to get the structure without the + and radical.
Try to understand electronic movement...do practice
why you not explain alkynes fragmentation ??
Will upload very soon.
Pls say donot say u are getting any response as the almighty God will give u blessing as there are many students who will watch your video after two or three years when they will do their master so donot let them deprived of best concept 🙏🙏🙏 pls sir your cordination series i have watched all the video from that day I am biggest fan 🙏🙏🙏🙏 so pls help us sir by sharing your knowledge as we cannot afford to take admn in prestigious institution to get such 🙏🙏🙏🙏🙏 concept
Thank you very much, will continue to upload lectures.
@@TETRAHEDRONCHEMISTRYCLASSES tqqq so much even right now I am watching your video I spend my whole day watching video to complete my msc 🙏🙏🙏🙏 so tqqqq so much meri ishwar se bas yhi pray shiv baba apko swasth nirog rkhe aur apke pura parivar ko apni duwaoooo ki sukrakcha kawach praden kre 🙏 be happy and healthy sir 🙏🙏🙏🙏🙏🙏🙏
🙏🙏🙏🙏
Wat about P S KALASI book sir
Good book, but I like Jagmohan.
Sir if only base peak is given how to determine the structure of molecule in given question
Based on analysis of base peak only it is difficult to analyse complete structure, you can identify fragment corresponding to base peak only, plz note that single spectroscopy is not enough to decide the structure of the molecule. For complete characterization of the molecule one should analyse mass, IR, Carbon NMR and H NMR atleast.
Sir 41 peak dehydration se aayegi ya kese at 25:04
Yes you are right, fragment 59 will loose 18(H2O) mass unit to give low peak at 41
Thanks sir
Sir could u make the mass spectra of non borane by fragmentation and also make the video on mossbauer spectroscopy and which is the best book for it please send the pdf of it I am not getting it
H kaur spectroscopy is good for Mossbauer, esr, raman and various spectroscopic techniques, will do Mossbauer in June.
Sir would you have the pdf of this book
No, will scan that mossbauer chapter and give you.
Ok sir thanks
Sir How to fragment if the Molecules have hydroxy aromatic benzoaate
Will make a video on esters too, plz wait...
Okie sir am.waiting
Sir is the peak at 31 is due to eliminating c2h4 from 59
Plz mention time.
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