Strength of Materials | Module 5 | TORSION EQUATION | (Lecture 49)

[@aashishkumarchoudhary1738]

I see Ur all lectures like fluid and this som all r awesome and help me to solve even gate previous year questions

[@VivekSingh-sl8iy]

Sir apse acha teacher kahin nahi dekha made easy me bhi nhi

[@mohittickoo5502]

Sir please make a module for Deflection of Beams.

[@debrajdas7436]

+1

[@CGLinformation]

Ha sir

[@jasonbourn29]

Thanks sir for explaining perpendicular axis theorem and parallel axis theorem in a sensible manner(if my memmory is correct you are the 5 th teacher teaching me this now only i understood what it is) ..your series on MoS is super...

[@kartiken4833]

Please continue sir this month complete modules upload...
Sir ho sir ap very clear teach

[@naushadworld000]

Aaj to sir jaldi mein the....
Kha se shuru kiya or kha pahucha diya 🙏🙏🙏❤️❤️

[@dkt_love07]

You are very much helpful for us sir....
God bless you 🙏🏼🙏🏼🙏🏼🙏🏼

[@nancidubey619]

Amazing sir thank you so much for your precious support

[@investolyser]

venu sir awesome awesome 😘😘 thank you so much sir 😘😘😘🙏

[@riteshguptaself-owneddesig7685]

Big daddy of all teachers

[@MahendraKumar-vc8hx]

Thank you so much sir Very helpful vedio

[@tariqueabdullah3021]

Thanks for continuing the som

[@tariqueabdullah3021]

Sir please complete the remaining portion of open channel flow in fluid mechanics

[@amangupta7488]

Thank you🙏💕 sir

[@rishavguptaeducation1732]

Sir please SOM पूरा padha do
और sir plz TOM भी padha देना plz sir

[@r.kmishra515]

Yes sir plz💯

[@mihirsrivastava1113]

Why the sense of Shear stress is in the direction of applied torque?? Please explain me

[@darshanmramoliya4646]

Wow..great content

[@KhushbooSingh-vd8om]

Sir please make module on deflection of beam 🙏👍

[@ultratech0122]

May Allah bless you sir

[@navadarshprakash7534]

Hi sir, Lectures are as wonderful as it always is. I have a doubt in the assumptions given, namely 5th one. shouldn't the torque be uniform through out the shaft? as there is no other way around? so is it necessary to mention it rather than being an obvious case? looking forward to your reply😀

[@soumyadeepghosh5000]

Great

[@backchodinfluencer]

Sir please make video on combined bending and torsion and strain enregy in torsion.

[@kamnisekh6109]

Nice video sir

[@ankushmahaleblogs8980]

Sir u make anyone from zero to hero
Plzz take slope and deflection 🙏

[@abduldexters]

what is the difference between applying torsion only and applying a couple of force
because in both cases we achieve pure torsion and no bending moment, transverse shear ???
Explain Please

[@fw-24s02]

Thank you sir!

[@krishnaghadiyali6301]

THANKS A LOT

[@puspaksinharoy402]

Sir please make a module on 'Deflection of Beams'

[@abhishekpandey8926]

sir deflection of beam bhi padhaa dijiye

[@FutureSDO]

sir what about theories of failure ?

[@kumardakshiitdhanbad4768]

Not clearly visible

[@ghumakkadshastra..ajourney3762]

Too good

[@rutubadkar4622]

Thank you sir

[@VIJAYKUMAR-ic5jb]

Sir I want to request that you are complete som

[@prakashgupta2477]

sir deflection of beam start kijiye ..plzzz sir

[@disastergamingff9464]

are tankq to hame bolna cahiye sir, aap se greetings r good luck ki pray chahiye. thank u

[@deepsinghania6496]

Sir pls make lectures on tom also

[@Bioooo]

Sir baki module kab upload hoge?

[@officenotebook8911]

Sir plz column ka lesson bhi banaiya 🙏🙏

[@pannalalyadav7736]

Please sir deflection of beam ka module bana digiye sir

[@kartiken4833]

Sir please please please please😫🙏🙏💓 all module upload kar dijiye na ap apka padaya bas samjh ata hai

[@kartiken4833]

Please sir this month complete module upload

[@azeemusman3821]

❤️

[@Bioooo]

🙏🙏🙏🙏

[@skyworldlife6913]

Hii sir

[@chauhan-pb1oy]

ring ka area 2pi r. dr kaise aaya ,please help anyone.

[@anshulgupta8287]

@@dajaykumar2463 shi kiya h sir ne

[@ashishsrivastava2920]

Ring ko beech se kaat kar straight krdo to rectangular banjaega..
L = 2pi.r
B= dr
Area = L x B = 2pi.r.dr

[@shubhamwr]

What ashish has said is one valid logic. If u want to go deeper and understand actual functionality, then it's still simple:
U know as ring is circular it's area should be π(ro^2-ri^2) where ro and ri is outer and inner radius of ring.
Now what he has taken is circumference multiplied by thickness:
2πr.dr
Just integrate it to get area with limits.
After integrating: 2*π*(r^2/2)
= π(r^2)
Put ro and ri as limit for r and u will get exactly same answer: π(ro^2-ri^2)
Hope it helped.

[@shubhamwr]

@@anshulgupta8287 he is asking why is it so, and not that sir is wrong.

[@RahulChoudhary-rk4bd]

At last in final equation you wrote "R" instead of "r".....that is wrong.

[@SRK-up4si]

R hi to hoga.. integration limit lgne k baad

[@RahulChoudhary-rk4bd]

@@SRK-up4si in general equation we take tau at radius r. At r=R , tau= tau max

[@altafchowdhary3400]

iska baad padhana ko choti haa

[@Mihir_thakur]

Thank you sir

[@Mihir_thakur]

Thank you sir

[@creatornirmal3742]

Thank u sir 👍🙏