0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong.
@@ECAcademy Could you answer this question please? "0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong?"
Hello sir thank you so much for your explanation. Last week i had exam and because of your explanation i was able to understand the concepts. You have to make more such tutorials which will help juniors. Your explanation is top notch.
Tomorrow is my external oral of DIP. Some concepts are not clearly understood due to online lectures. But in the last few hours I watched this video and all the transformation concepts cleared up. Thank You Sir🙏
0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong.
The finest and easiest explanation.
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Since few minutes I am trying to read text book which was soo bulky ,but this video was short and sweet and pretty much clear Thank you sir
0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong.
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@@ECAcademy Could you answer this question please?
"0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong?"
Thank you... its really helpful to understand difficult parts also
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Superbly explaining the content. Helped me a lot in understanding the basics. Thanks a lot sir! ❤🔥
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very well explained. thank you sir
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Sir thank you so much i understood very well
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Very thank You Sir!!!.....amazing tutorial
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Hello sir thank you so much for your explanation. Last week i had exam and because of your explanation i was able to understand the concepts. You have to make more such tutorials which will help juniors. Your explanation is top notch.
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Tomorrow is my external oral of DIP. Some concepts are not clearly understood due to online lectures. But in the last few hours I watched this video and all the transformation concepts cleared up. Thank You Sir🙏
Best wishes for your exams…
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well explained Sir👍🏻
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Thanks a lot sir🙏. You have explained very well 🙏
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Excellent Explanation!
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0 corresponds to black and 255 to white. In power law, s = cr^y now according to graph if gama value is less than 1, it will result into a brighter pixel. But lets say c = 1 , r = 16 and gama = .5, so output pixel here will be 4 and thats darker right, i dunno where am i going wrong.
Same problem .
solution mila??...mila to bata dena
r value can only be between 0 and 1
Such a nyc explanation sir tq very much
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this video helped a lot thank u sir
Thank you for your feedback…..
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Thank you so much sir...
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شكرا ❤
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Super explanation
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Yes. I will co. operate surely
Tq sir
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awesome, thank you so much.
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Can you please tell me something about gray level difference matrix
Do you mean gray level dependence matrix ?
Thank you!
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Thanks
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What is the base of log in log transformation?
Tqsm❤️✨️
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👍👍👍🔥
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ty sir
S=L-1-r(substituting r=L-1) which gives
S=L-1-L-1(after L and -L get cancelled)
S=-2
Or
S=L-1+(-L+1)
Am I still wrong??
S = L -1 - r.
Substitue r = L -1.
S = L -1 - (L-1)
S= L - 1 - L + 1
S = 0.
super explanation sir .very clear
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