@DumMeister If you wish to switch the order of integration then you really need to find those parallel lines (in Cartesian co-ords). The switching of integration isn't always necessary, so you might be able to solve the problem directly.
You know I've always hated math since I was young. Considering that this was uploaded 10 years ago, I can't believe I'm taking an Engineering course now! Anyways, thanks for the video! Even if I'm a decade late to say thanks.
@DrChrisTisdell Okay but my homework requires me to do so anyways. Just another question if you don't mind. If for example, I have a limit of y=x and x=a, am I allowed to infer that I have a limit of y=a as well? I will also like to commend you for being a true educator, helping students that you do not know. Thanks!
Redescription of the variable limit of integration seems from this first example to be in terms of the inverse of the function (within the bounds of the double integration). Aren't you thereby relying on that function being one-to-one within those two-dimensional bounds? And what happens if it's not?
Thanx Sir !!! It really helped a lot. Your Explanation is best and it has made me more interested in this topic of which I used to shudder off. Well again , thanx a lot ☺
to be more clear, in order to integrate sqrt(1+y^3), we could rewrite as the derivative with respect to y of the integral from 0 to y of the integral from sqrt(x) to 1 of sqrt(1+y^3) with respect to y, with respect to x, then swap the order and differentiate?
It also means that you're experienced enough at these sorts of integrations to recognise the form when you see it (like little kids memorising sight-words), but it drives newcomers to integral calculus absolutely spare with frustration when the lecturer takes a look at something like this and says "the answer is obviously..." And woe betide you if you solve by inspection and get it wrong! When I was in high school, we got marks for showing all our steps, so if we slipped and made a silly error of transcription we would still get some credit for following on with the correct method and showing that we at least understood the process we were being asked to demonstrate.
The way you described how to use parallel lines to find a new way to bound the equation really helped clear things out, thanks!
@DumMeister If you wish to switch the order of integration then you really need to find those parallel lines (in Cartesian co-ords). The switching of integration isn't always necessary, so you might be able to solve the problem directly.
You know I've always hated math since I was young. Considering that this was uploaded 10 years ago, I can't believe I'm taking an Engineering course now! Anyways, thanks for the video! Even if I'm a decade late to say thanks.
Thanks a lot! You`re saving a year of my life!
Thank you so much! I didn't understand it when my teacher was lecturing this. I can now do my homework now ~
Thank you sir. It helps me a lot to increase the concept. But At the end part you did not as much as we expect. once again thank you Sir.
My pleasure. Hope you've found the associated ebook to be of some use too. The free download link is in the description.
@DumMeister No, not necessarily. It depends on the exact nature of the problem under consideration.
Many thanks for your feedback! Hope you find the free ebook useful, too!!
Awesome! Very well explained. I really appreciate you making tutorial videos to help us. Thanks!
Banging video, helped a lot, thanks!
banging mate
@DrChrisTisdell Okay but my homework requires me to do so anyways. Just another question if you don't mind. If for example, I have a limit of y=x and x=a, am I allowed to infer that I have a limit of y=a as well? I will also like to commend you for being a true educator, helping students that you do not know. Thanks!
Redescription of the variable limit of integration seems from this first example to be in terms of the inverse of the function (within the bounds of the double integration). Aren't you thereby relying on that function being one-to-one within those two-dimensional bounds? And what happens if it's not?
Thanx Sir !!! It really helped a lot. Your Explanation is best and it has made me more interested in this topic of which I used to shudder off. Well again , thanx a lot ☺
My pleasure.
Thank you for making it so lucid.
thankyou sir ..now no confusion over this topic
You absolute Don! Thanks for helping me!!!
Thank you is never a cliche :)
@DrChrisTisdell Hey sorry to bother you, but what happens if I can't find the reverse of the parallel lines?
You are welcome.
Since the PDF is not available anymore, solution for the second equation is 1/6 * [-cos(144) + 1] + cst for those who tried to find it
ruclips.net/video/vFDMaHQ4kW8/видео.html
This was super helpful. Thank you!! :)
thank you sir i need ro see some more problems..
excellent explanation, very cool voice though :) thanks a lot..
Thank you so much , I do understand better now :)
could this be used to simplify single integrals by applying the fundamental theorem of calculus?
to be more clear, in order to integrate sqrt(1+y^3), we could rewrite as the derivative with respect to y of the integral from 0 to y of the integral from sqrt(x) to 1 of sqrt(1+y^3) with respect to y, with respect to x, then swap the order and differentiate?
after reconsideration, I realize this would give it to me in terms of y, which is just some arbitrary variable for the convenience of integration
after reconsideration, I realize this would give it to me in terms of y, which is just some arbitrary variable for the convenience of integration
very clear thanks
What is with the picture-in-picture at the bottom right? It doesn't seem to be in sync in any of your videos!
mjallan123 Yep, that doesn't quite correspond, does it? If it annoys you then try to ignore.
Thanks a lot :x
Excellent.
ruclips.net/video/vFDMaHQ4kW8/видео.html
isn't it better to use the substitution rule to compute the integral?? my answer is then 1/2
whats the answer to the last question that was left for us to do?
so we can check if we got it right. thanks.
Hi - the answers are in my free ebook tinyurl.com/EngMathYT
Dr Chris Tisdell
Hi, so if I got it right, after the change 0
thnks bro
what is by inspection means???
+Eslam Eshmawy It means that you just write down the answer - no working needed.
It also means that you're experienced enough at these sorts of integrations to recognise the form when you see it (like little kids memorising sight-words), but it drives newcomers to integral calculus absolutely spare with frustration when the lecturer takes a look at something like this and says "the answer is obviously..."
And woe betide you if you solve by inspection and get it wrong! When I was in high school, we got marks for showing all our steps, so if we slipped and made a silly error of transcription we would still get some credit for following on with the correct method and showing that we at least understood the process we were being asked to demonstrate.
Thank you.
I solved the Naiver Stokes equations by inspection but no one believed me 🥇 200iq
Thnks
ruclips.net/video/vFDMaHQ4kW8/видео.html
thank you sooo much !!!!!!!
Xuxa Kasandimedjo What's your substitution?
tnxs
Thanks Mann...keep up the good work... I think youtube should now offer online degrees. lol
thank u
Thanks a lot man! :)
what in the world is integration by inspection
ruclips.net/video/vFDMaHQ4kW8/видео.html
Haha - I am half man, half wookie.
What the hell is on the bottom right?
That's me. If you find it distracting then please ignore.
Dr Chris Tisdell Kinda out of sync isn't it?
Simas A. Yes, it is out of sync. Long story, but different frame rates on two separate video tracks.
i know it's cliche. but thank you.
i hate maths, i got no hope trying to learn double and triple integrals day before test :(, damn engineering
british english is pouring :)
Talha Bedir this sounds australian to me
Qlimakz maybe you are right
I dont have nice accent ear :)
Definitely mate, professor T’s an Aussie
lol
My pleasure.