Rectangular and Polar are just two different ways of looking at the same complex number. It is a matter of personal preference and what might be easier given the problem. This problem was about first finding the transfer function
Yes the process is the same. It doesn't matter what the elements are --- the transfer function is Vout/Vin and as long as it is a circuit that you can put in a voltage divider type configuration shown in this example the Vout/Vin = ZOUT/Ztotal.
So amazing...it is after 12 years after my engineering I understood the concept today because of you.
Thank you so much...
Dude you have an amazing talent of explanation skill
I found this video rarely with this much good explanation
Best RLC so far, I am confused as why you did these in rectangular and not polar?
Rectangular and Polar are just two different ways of looking at the same complex number. It is a matter of personal preference and what might be easier given the problem. This problem was about first finding the transfer function
solid refresher
Fantastic Video.
Good night teacher, can this deduction be made by a laplace transform?
Yes, you can. The 'jw' in a transfer function is the same as 's' you would get in the Laplace Domain
The last term of the transfer function magnitude calculation (wL)^2 should be -(wL)^2 (with a minus in front) because you square the j.
Actually the magnitude of a complex number of the form P+jQ is sqrt(P^2 + Q^2). j is the y-axis.
@@ENGRTUTOR Oh dear. You're right!
thanks it helped me.
Can this work for a dc voltage?
DC is just as special case of AC with frequency of 0Hz.
Would the process be the same if the inductor was replaced with a resistor? How much different would it be?
And that both the resistors are of different values?
@@ravioliformuoli520that would turn in to a modified low pass filter, you can see examples of it as low pass filter with a load resistor also
Yes the process is the same. It doesn't matter what the elements are --- the transfer function is Vout/Vin and as long as it is a circuit that you can put in a voltage divider type configuration shown in this example the Vout/Vin = ZOUT/Ztotal.
Would this work for a series RLC circuit?
Yes.
can anyone explain to me how the j is disappearing
j*j = -1 (complex algebra)
Okay i know but i mean the moment we introduce the modulus sign
Infinity squared is infinity and then infinity divided by infinity is undefined
Since we build realistic circuits - think of Infinity as a VERY LARGE frequency value.
Okay. What change does it bring?
@@andrewmutizamhepo1124 that square root infinity on the fourth power is squared infinity