Steel Design - Effective lengths of beams - Illustration example - SD424

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  • Опубликовано: 12 дек 2024

Комментарии • 24

  • @me09hha
    @me09hha 4 года назад

    Well explained. Very clear

  • @patocarrasco6266
    @patocarrasco6266 4 года назад

    when you are so left handed that you can horizontally flip the surface you are writing on
    great video!!

  • @pradyumnakulkarni-i4z
    @pradyumnakulkarni-i4z Год назад

    Thank you for this helpful video. I had a question about destabilizing load. In the cantilever portion the load is on the tension flange and bottom flange is having bending compression. Will the load have stabilizing or destabilizing effect being on tension side?

    • @firesun
      @firesun  Год назад

      SANS 10162-1, which is probably the most codes, defines a destabilising load as being on the top/tension flange.

    • @firesun
      @firesun  Год назад

      Specifically in terms of cantilevers

  • @Ash-tp3im
    @Ash-tp3im 4 года назад

    Sir I am from India so I want to know that these values you are talking about are same to India code i.e IS CODE

  • @lwandilembewana5587
    @lwandilembewana5587 Месяц назад

    With the cantilever, if the load is applied on the bottom fledge and no lateral restraint (crawl beam case) is it still normal load even though considering eccentricity, the beam could twist?.

    • @firesun
      @firesun  Месяц назад

      The twisting is accounted for in the boundary conditions. The position of the load is accounted for by it being normal. Hence, correct - bottom flange load would be normal. However, remember that for crawl beams you may need to apply additional dynamic impact effects.

    • @lwandilembewana5587
      @lwandilembewana5587 Месяц назад

      @firesun thank you very much for the insight. The crawl beam is for lifting a pump with a combined load of 100 kg at most. Is there any video about applying dynamic loads based on the code.

    • @firesun
      @firesun  Месяц назад

      @@lwandilembewana5587 You can have a look at SANS 10160 as there is an entire section on crane loads. Older versions of the Red Book also have some approximate details. An additional factor in the order of 1.2 probably needs to be applied. 100kg is quite a light crawl

    • @lwandilembewana5587
      @lwandilembewana5587 Месяц назад

      @@firesun thank you very much. Yes it is. You the best

  • @kyleallan6181
    @kyleallan6181 6 месяцев назад

    Prof, would the K value for section L3 not be 1.2? The section is laterally and torsionally restraint. If i am correct, a value of 2.5 is for only laterally restrained.

    • @firesun
      @firesun  6 месяцев назад

      L3 is a cantilever. On the right side it is free. On the left side it is continuous with lateral and torsional support. If assumed to be a destabilising load then we end up with K = 2.5.

  • @joshvandermeer9138
    @joshvandermeer9138 4 года назад

    Hi Dr Wills, if the cantilever span has a midspan lateral support, how do you deal with the support conditions for each of the spans along the cantilever length?

    • @firesun
      @firesun  4 года назад

      Always design between points of lateral support, with end conditions defined: (Section 1) ?Free tip, with ?only lateral support and continuous, and (Section 2) lateral support at tip and whatever conditions you have at support. Also, make sure you choose carefully between normal and destabilising load as that has a big influence on results.

    • @picajoool
      @picajoool 3 года назад

      @@firesun dr. Wills, can you recommend a good book on this topic with some solved egsamples? Thank you in advance

    • @firesun
      @firesun  3 года назад

      @@picajoool In South Africa there is a textbook on SANS 10162-1 by Mahachi that can assist. However, most good steel design textbooks for university students should assist.

    • @picajoool
      @picajoool 3 года назад

      @@firesun Dr. Wills thank you for your response.
      Problem is that Im Eurocode based, but I love watching you videos.
      It seems that Eurocode doesnt have LTB effective lenghts defined for various conditions.
      It does have coefficient for effective lenght that you input in formula or finding out critical bending moment, but its not very intuitive and it doesnt have any explenation of dividing a beam into multiple segments between lateral supports, and checking each segment with its effective lenghts.....

  • @vats_chauhan
    @vats_chauhan 7 месяцев назад

    Figure in front n person in back which type of screen is it

    • @firesun
      @firesun  7 месяцев назад

      Its a light board. Glass screen with light passing through it, that is picked up when you write with special pens.

  • @chanbormey4499
    @chanbormey4499 3 года назад

    do we not consider the buckling on another axe?

    • @firesun
      @firesun  3 года назад +1

      When considering a beam - it will only experience lateral-torsional buckling when undergoing bending about its strong axis. If bent about its weak axis it will simply yield without buckling occurs. Hence, beams only have one effective length and this is for LTB (except if the top and bottom flange both experience compression and have different effective lengths - but these are still both for LTB). Columns can have multiple effective lengths for buckling about different axes.

    • @chanbormey4499
      @chanbormey4499 3 года назад

      @@firesun thank you .so for a beam has compresion force, we will consider it in interaction LTB and Buckling right ?

    • @firesun
      @firesun  3 года назад +1

      @@chanbormey4499 - It depends on what you mean by compression force. (1) When a beam experiences bending the one flange will be in compression and the other in tension. Compression causes buckling. Hence, we focus on the flange which is in compression and its effective length. (2) If a beam experiences both a compression force and a bending force then refer to our other video which covers the design of such members - ruclips.net/video/WrtuIvoK2Rs/видео.html.