Impedance Transformation

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  • Опубликовано: 7 ноя 2024

Комментарии • 23

  • @prathimar
    @prathimar 13 лет назад +5

    Lecture s extremly useful ....thnks a lot sir...

  • @Tembu
    @Tembu 4 года назад +7

    i hate how we only meet before my exams

  • @poiuwnwang7109
    @poiuwnwang7109 6 лет назад +2

    Very nice redefination of characteristic impedance.

  • @govindsrivastav3594
    @govindsrivastav3594 8 лет назад +5

    Sir u r really great

    • @rahulsingh-el5on
      @rahulsingh-el5on 4 года назад

      nooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo

  • @birtechboy
    @birtechboy 10 лет назад +3

    thanks a bunch dear sir

  • @deltechdiaries5907
    @deltechdiaries5907 3 года назад +2

    why don't we have such professors in college?

  • @rahuladesh4260
    @rahuladesh4260 8 лет назад +5

    I don't know what happen to me but I have fall in love with transmission line.

    • @Bvolts71
      @Bvolts71 6 лет назад

      lol!! same here

    • @poiuwnwang7109
      @poiuwnwang7109 6 лет назад

      Same here. EM was one of the courses I hated in university, but now I am beginning to love it.

  • @cannibol9009
    @cannibol9009 9 лет назад

    I have a doubt! It is said that if R = G = 0, the line is lossless and the whole power is transferred to the load. But even though R = G = 0, L and C exists in the system. This stores the energy somewhere along the line, right? Then how can maximum power transfer occur?

    • @nikhildei91
      @nikhildei91 8 лет назад +2

      +cannibol9009 , Yes you are correct, but keep in mind that pure reactance do not consume any real power. For instance, an inductor element converts the absorbed power in magnetic energy. As per the hysterisis the power consumed by an inductor is oscillatory in nature, thus energy is consumed in 1 cycle and delivers in another. Therefore no power consumed on average. Same for a capacitor.

    • @cannibol9009
      @cannibol9009 8 лет назад

      Yes +Nikhil Sharma, you are absolutely right! Thanks for the clarification!

  • @kuldeep0187
    @kuldeep0187 12 лет назад +2

    thank you sir........

  • @udit9957
    @udit9957 Год назад

    Great!

  • @muramallagayathri7728
    @muramallagayathri7728 4 года назад

    Thank you sir !!!!

  • @bhartkumar4654
    @bhartkumar4654 7 лет назад

    how you get gamma(0)=gamma L . exp(-2yl) at 11:46?

    • @vedantjoshi1487
      @vedantjoshi1487 7 лет назад

      by the help of mathematics...!

    • @rajnarayanshriwas4653
      @rajnarayanshriwas4653 6 лет назад +1

      Gamma (0) is the reflection coefficient when small "l" = 0.
      and gamma_L here: "L" stands for "Load" not the length u might be thinking of.
      So at the location of Load the value of small l is 0. Hence
      Gamma(l=0) = Gamma(0)= Gamma at load= Gamma_L

  • @प्रणव_गुप्ता

    🫡🫡🫡🫡🫡

  • @noshadahmed221
    @noshadahmed221 7 лет назад

    Poor teaching quality