Sir, 2n-1 is correct representation of odd numbers starting from 1. 2n+1 starts counting of odd numbers from 3 and loops end at 11th because total no. of loops or n is set as 5 after 2n loop (as list is total of 10 items and styling must have been already applied to tenth also in 2n loop, provided no other pseudo loops are after like 2n+1 we had). System now unable to understand whose rule to apply for 10th 2n for being even or 2n+1 ending the loop after 2n+1 for odd rule is applied for styling. So, it would have been better put the equation as 2n-1 which is correct representation of odd numbers starting from 1. Most likely , this will solve the problem. Also, now 2n-1 elements must be declared first in css and then 2n as first odd number 1 comes before first even no. 2. It will appropriately solve 10th no. not getting proper styling problem. There are though several other ways too to solve, like adding an extra and make it 11 instead of 10th.
Bro, we can go 10n directly But I think is problem me hame ye assume krna h ki "we don't know how many childs there are".. Baki agar pta h to 10n is straight forward easy
I don't know why iss video pe itna kam like-comments hai. Even it's most satisfactory video and having helthy content with lovely explanation Love you bro😍
Sir, 2n-1 is correct representation of odd numbers starting from 1. 2n+1 starts counting of odd numbers from 3 and loops end at 11th because total no. of loops or n is set as 5 after 2n loop (as list is total of 10 items and styling must have been already applied to tenth also in 2n loop, provided no other pseudo loops are after like 2n+1 we had). System now unable to understand whose rule to apply for 10th 2n for being even or 2n+1 ending the loop after 2n+1 for odd rule is applied for styling. So, it would have been better put the equation as 2n-1 which is correct representation of odd numbers starting from 1. Most likely , this will solve the problem. Also, now 2n-1 elements must be declared first in css and then 2n as first odd number 1 comes before first even no. 2. It will appropriately solve 10th no. not getting proper styling problem. There are though several other ways too to solve, like adding an extra and make it 11 instead of 10th.
Bro, logic is correct if n is natural number. Here n is whole number, starting from 0 So first odd will be 2n+1 i.e. 1 2n-1 will be -1, ispr alag alag browser alag alag react krenge
Awesome sir.. sir your all tutorial vedios are amazing. Thanks you sir.. Sir main ek courier company me work kr rahi hun par usme muje track id add krna hai.. usko kaise add krun.. location kaise bta chalegi.. coding?? Please sir guide me
Bro I seen your many videos. Nice efforts.Your way of teaching is very good. Can you make one video a comparison between flex box, display -inline block, grid , float: left . Which one is best to use. Or any like. No such comparison done by any youtuber. And newbies get confused in that. That may be one of the most watched video possible. Think if you feel fit then make such video.
Thapa sir, you are rocking. really helpful all the tutorials. I wish your all wishes complete. One question: Could you please tell me which software are you using for your video editing???
![I.N "HALLUCINATION" | [Stray Kids : SKZ-PLAYER]](http://i.ytimg.com/vi/n5B5q1Hwt_U/mqdefault.jpg)
Guys, believe me it's awesome.. matlb all selectors ek property me. Plz share with your friends and classmates too ☺️
Sir, 2n-1 is correct representation of odd numbers starting from 1. 2n+1 starts counting of odd numbers from 3 and loops end at 11th because total no. of loops or n is set as 5 after 2n loop (as list is total of 10 items and styling must have been already applied to tenth also in 2n loop, provided no other pseudo loops are after like 2n+1 we had). System now unable to understand whose rule to apply for 10th 2n for being even or 2n+1 ending the loop after 2n+1 for odd rule is applied for styling.
So, it would have been better put the equation as 2n-1 which is correct representation of odd numbers starting from 1. Most likely , this will solve the problem.
Also, now 2n-1 elements must be declared first in css and then 2n as first odd number 1 comes before first even no. 2. It will appropriately solve 10th no. not getting proper styling problem.
There are though several other ways too to solve, like adding an extra and make it 11 instead of 10th.
Bhai thanku so much ♥️ mujhe yeh nhi ata tha master series bhott achi banayi hai aapne once again thanku so much
11:35 li:nth-child(10n){
}
nth-last-child(1) pseudo class to catch the last element
And your teaching style awesome
From Bangladesh
You're are my teacher
You're are god
You're are my beloved....
apkse video main se daily kuch naya sikhne ko milta hai thanks thapa technical like and share kijiye is video
Nice sir 👍 Thanks
its really amazing...your way of explanation is very good😊..
.thank you sir....
You are awesome 🤩🤩🤩
Thanks 🙏🏻 for today's video sanday ka video ka wait kr rhe h is series ko continue kre ....
This method of thenth child highLight using nth-child Property
li:nth-child(2n+10){
color: red;
}
And Thank You 👍 For This Video.
Bro, we can go 10n directly
But I think is problem me hame ye assume krna h ki "we don't know how many childs there are"..
Baki agar pta h to 10n is straight forward easy
bhai tussi great ho
I don't know why iss video pe itna kam like-comments hai.
Even it's most satisfactory video and having helthy content with lovely explanation
Love you bro😍
agree
Good bro👍.
Q1. 12:54
Ans..
li:nth-child(10){
color: crimson;
}
Your video is always awsome👌👌
Yes it was helpful me and my friends......
Awesome
Sir, 2n-1 is correct representation of odd numbers starting from 1. 2n+1 starts counting of odd numbers from 3 and loops end at 11th because total no. of loops or n is set as 5 after 2n loop (as list is total of 10 items and styling must have been already applied to tenth also in 2n loop, provided no other pseudo loops are after like 2n+1 we had). System now unable to understand whose rule to apply for 10th 2n for being even or 2n+1 ending the loop after 2n+1 for odd rule is applied for styling.
So, it would have been better put the equation as 2n-1 which is correct representation of odd numbers starting from 1. Most likely , this will solve the problem.
Also, now 2n-1 elements must be declared first in css and then 2n as first odd number 1 comes before first even no. 2. It will appropriately solve 10th no. not getting proper styling problem.
There are though several other ways too to solve, like adding an extra and make it 11 instead of 10th.
Bro, logic is correct if n is natural number. Here n is whole number, starting from 0
So first odd will be 2n+1 i.e. 1
2n-1 will be -1, ispr alag alag browser alag alag react krenge
Sir you are great 👌😊
AWESOME ❤️
Awesome 😄
11:38 sir mujhe para hai nth child likna hai phir last of type
thank you for nice explanation
Great 😊👍
Nice video
Its well explained
great
App k sawal ka jawab hai 11:05
li:nth-last-child(1){
color: #0a3d62;}
This meaning is
backward counting
Thapa bhai, if we have a dynamic list and we want to style only last 5, how can we do using pseudo classes
Thanks your for your efforts
9n+1 is for last
Please tell which is that website from where you take colors
sir 1,3,6,10,15 is series mai nth-child kese use karenge
How to apply color to middle child without JS for dynamic number of elements?
Thankyou sir
Super bro
Awesome sir.. sir your all tutorial vedios are amazing. Thanks you sir..
Sir main ek courier company me work kr rahi hun par usme muje track id add krna hai.. usko kaise add krun.. location kaise bta chalegi.. coding?? Please sir guide me
Nice
hello sir can you make a series of html css projects?like 10 or 20 videos together by creating paylist?
Can you make a video on prototypal inheritance
Thank you so much ☺️
Nth-child(10n)
Nth-child(10)
nth-child(5n+5n)
nth-child(5n+5):not(nth-child(5))
It can be 2n+3 for odd elements without first.
Ki:nth-child(10){
Color: orange;
}
Nth-last-child(1) se last ka color change ho jayega
Sir aap jo code run karate ho uska PDF de diya kariye bahut achha rahega
🎉🎉🎉🎉
Bro I seen your many videos. Nice efforts.Your way of teaching is very good. Can you make one video a comparison between flex box, display -inline block, grid , float: left . Which one is best to use. Or any like. No such comparison done by any youtuber. And newbies get confused in that. That may be one of the most watched video possible. Think if you feel fit then make such video.
Thapa sir, you are rocking. really helpful all the tutorials. I wish your all wishes complete. One question: Could you please tell me which software are you using for your video editing???
Filmora
Thanks for these awesome tutorials. Make a tutorial on - How to make a slider.
Thankuuuuu
i want to learn ES6, i watched all your video, please sir guide kro kahan se start kro, mujeh basic se start karna hai
Sunday kab he aur kitna wait karna padega
Thanks, Very useful video sir, i have request please create video on bitbucket with and how to host website on bitbucket
hey bro please make Restaurant Website using html css and react or bootstrap .
Using :nth-last-child(2) you can select last child element of parent
Not working
Nth-child (2n + 10)
{
Color: red;
}
Hi,
Consider below code,
Div 1
Div 2
Div 3
Div 4
Div 5
How to select 2nd div under parentDiv??
li:nth-child(odd)
li:nth-child(even)
with the help of 10n we can change the line of tenth
li:Last-childi{color:skyblue;}
🥰
2n-1 chalega
1st comment
Sorry got late
React se tiktok application kaise banaye
Nth child ke liye n-1+1
Abe lgane ki zaroort nhi iske liye