HYPERBOLA TRICK/CONICS-SHORTCUT NDA/NA/JEE/CETs/AIRFORCE/BITSAT/BANKING/RAILWAYS/ssc-cgl
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- Опубликовано: 6 фев 2025
- HYPERBOLA TRICKS. Solution under 10 seconds. CONIC SECIONS
TRICK/SHORTCUT FOR NDA/ JEE/ EAMCET/MHCET/CEE/ KCET/GUJCET/ COMEDK/ BITSAT/SSC-CGL
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How to find:-
1) Standard equation of a hyperbola, given its standard form
2) Centre of a hyperbola
3) Vertices of a hyperbola
4) Foci of a hyperbola
5) Transverse and Conjugate axes
6) Latus rectum
7) eccentricity
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Best RUclips channel for Mathematics!!!!!
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Absolutely
Yes mam!!!!
Yo
@@rushilboligarla6955 true🤣😂😂
Loved this ma'am!Center (2,3)
Vertices (6,3) and (-2,3)
Focus (7,3)and(-3,3)
And
the Eccentricity 5/4
I'll cut a lot of questions with this sword method ..... 😁😁 .. Thank you .. Mam 👏👏 👍👍
Nice trick Iam teacher in Narayana educational institutions and Iam teaching from 7 years but I never seen this trick really appreciate your effort
Center (2,3)
Vertices (6,3) and (-2,3)
Focus (7,3)and(-3,3)
And
Ecntricity 5/4
Super answer I like it thanks
That's right
ecenticity me 4 kaise aaya
iska formulla kya hota h
@@StatusKingyt c^2 = a^2+b^2
Therefore c is 5
We know that c = ae
Therefore 5 = 4e
Therefore e = 5/4
Centre (2,3)
Vertices (6,3) n (-2,3)
Foci (7,3) n (-3,3)
Eccentricity = 5/4
This video is really helpful 4 me mam
This question became very easy because of you mam
Thanks
A VERY GOOD AND SIMPLEST MATHS CHANNEL I HAVE EVER SEEN NICE MAAM AND I WISH EVERY ONE LOVE UR CHANNEL
I got my NDA Exam tomorrow.Just watched all your videos.Wish me luck.
Good luck
How did you do?
How was your exam
Kya hua ab 😂
Gaya😂
Ma'am you are really great . Even my coaching institute does not teach me these types of tricks for jee. God bless you ma'am
Wow 😲 😳😳 what a tricks
Sup trick to solve question..thankq
I wish I had a teacher like you at school.
Give complete note about conic section(parabola, ellipse, hyperbola) for NDA examination
Nice mam your explanation and you are my best for preparation
👍👍👍
IF YOU COULD MAKE A VIDEO ON :
How can I find separate equation from pair of straight line? SHORTCUT.....IT WOULD BE OF GREAT HELP......
Thank you ,yes I have fallen in love with these tricks
Center:(2,3)
Eqn:(y-3)²÷9-(x-2)²÷16=1
Vertices:(4,3)or(-2,3)
Foci:(8,3)or(-2,3) mam pleas say me this is correct
Today is my Entry Test and This channel literally saved my future, Thank you so much.
How can u assure that yet , I mean ur future
5:12 is this trick same for elipse?
Thanks mam for your trick , it is so quick and easy !!!
Mathematical inclined is the best mathematics channel in youtube, Excellent mam
Best way to learn concept of maths...very easy very fast and very accurate .....
Centre (2,3)
Vertices (6,3),(-2,3)
Foci (7,3),(-3,3)
Eccentricity 5/4
Superb channel mam and it is very helpful for us. Tnq mam 🙂
Hlo bro what are you doing now.????
Preparing for NDA .....in unlock helped me a lot....thank you mam
DIY ans:-
Centre=(2,3)
Vertices=(6,3)&(-2,3)
Foci=(7,3)&(-3,3)
e=5/4
That was awesome! Really! U got a fan!
U r great
U r a great math teacher
I also want to be a math teacher like u
Hardworker
Centre:(2,3)
Vertices:(6,3) and (-2,3)
Foci:(7,3) and (-3,3)
Eccentricity:5/4
And thanks for the video ma'am.
Center:- (2,3)
Vertices:- (6,3),(-2,3)
Focus:- (7,3),(-3,3)
Eccentricity:- 5/4
Can we use sword method in ellipse also..... @mathematically inclined
Great tricks ma'am..
I think now it's gonna be very easy to solve these confusing questions
Ha yr
Excellent
Wawu sir thanks i am from Ethiopia and now hyperbola is too simple 🎉🎉🎉🎉🎉 center(2,3) vertex(2,6)(2,0) foci(2,3under radical 5 +3) and (2,3under radical 5 _3) eccentricity =under radical 5
hlo mam ...i am fan of u ..i am watching ur all vedioes in lockdown ,,,,those helps me allot ...welldone madam ji
Thanks a lot mam to clear my concepts by such a simple method.....
Thank you so much......
Mam i like ur teaching ,can u explain demoivres theorem also
Thanks mam it helped me a lot ,😀😀🥰
This question became very easy because of you mam
Thanks
Thankyou ma'am for this trick. It's so easy and helpful!😍😍😍❤
I am so happy for its method ... very very simple method
I so needed these videos on Conics..😭😭😭😭😭😭😭 Thank you so much. Conic kichu pari na. 😢
Hii
answer for DIY is
center :- (2,3)
vertices:- (6,3)&(-2,3)
focii:-(7,3)&(-3,3)
eccentricity:- 5/4
THANKS A LOT MAM.
U HELPED SO MUCH IN OUR STUDIES
What is the rule of major axes and minor axes and latus rectum of Conjugate hyperbola
super duper, Sister ji, I am big fan
Madam explanation is excellent pls explain full short cuts ellipse jee mains all questions
excellent
hi mam i am your greatest fan for mathematics tricks
i want from you to make a video on the identification of conic section from given parametric equation please
hi friends if you need this video topic then like here and request this chapter to madam
Mam maine apke lagbhag sare video dekh mujhe samajh bhi aye 😊☺☺☺☺
Mam ur tricks are very very use ful thanks a lot mam👏👏👏👏
Plz give videos for tangent and normal related concept of conic section plz i and many other my friends need it so it will helpful for us
Centre (2,3)
Ver. (6,3) (-2,3)
Foci(7,3) (-3,3)
E (5/4)
I m having my NVS TGT maths exam.. really helpful...neha ma'am
Very much helpful for my entey test... #Love from Pakistan mam.... You are super cool😍😍
Nice.. Mam it's simply quite easy
DIY
Transverse hyperbole
6,3 and -2,3 vertices
5/4 eccentricity
17,3 and -9,3 foci
Thank u ma'am
(7,3) & (-3,3) are the foci
No one can teach maths better than you! Thank you Mam ❤
Msr❤❤❤❤search kr
You are excelent teacher.
Absolutely Brilliant !! Love The Way of teaching May God Bless You Ma am
thank you so much mam for uploading such a wonderful video........
and... HATS OFF FOR YOUR TALENT MAM.... YOU ARE MY SUPER HERO IN MATHS .. YOUR TRICKS ARE AMAZING !!!!!!!!!!
The finest mathematics teachers off all time G.O.A.T
Mam please make video regarding rectangular hyperbola concept... Please mam
Mam your smiley face make question more easy 🙏🏻😇
Beautiful 😁😁
Mam I have a conceptual question
Hyperbola is an unbounded curve then how can be have a center for it?
Wowww ma'am!! Really amazing tricks! Thanks for the best tricks available on RUclips ❤️❤️ Pls upload trick for full class 11 and 12 chapter from JEE point of view 🙏
Ma'am you are doing great work for us.
Thanks a lot
U r fabulous teacher ever I seen 👌👌👍
Rectangular hyperbola & equation of tangent and normal in hyperbola
U r a commander love u mam😘😘😘😘😘
Mam agar esi koi form aai jisme x ka cofficient divide nahi kre constant value ko to Kya trick hogii
hi, i am from Bangladesh
Your video is reallyyyyyyyyy helpful for me, thank u sooooooo much 😘😘😘
Excellent mam.. i am continuous watching your classes... If xy comes in the equation what is the method mam...
Mam you are genius
Ur recap helped a lot mam
Amazing
Mam..... U make difficult maths such beautiful...... Really u are great teacher for competitive exams.... I'm proud that I have find teacher like u
woooow i have nearly watched all
im amazed how she managed to find these tricks..
really........amazing
Mam if eq also has xy term then what to do????
@@varadpawar8242 F
M'am thanks for whatever maths guidance you provide, request you to please upload videos for those who after 10th did not study maths but now at PG level (MA Eco IGNOU) have to cope up with mathematical economics
Mam in previous video of conic in which u have identified that whether it is a parabola or hyperbola etc and the examples in this there is not present xy term whose coefficient is b so that it would be a hyperbola so how this is hyperbola ?? Plz answer
Centre (2,3)
Verices(6,3) &(-2,3)
Foci(7,3) & (-3,3)
Eccentricity 5/4
Your explaining style is awesome....❤💥
Mam really your tricks are being very much helpful to me.I thank you from the bottom of my heart
this is pretty much the best video ever ....helped a lot...
Very high quality videos..God bless you..
Thanks a lot ......neha mam . You helped me a lot in jee examinations!!😊😊
Great
centre: (2,3) vertices: (6,3 )&(-2,3) foci: (7,3)&(-3,3) eccentricity:5/4
Is it applicable for ellipse?
centre::(2,3) vertex(6,-3),(-2,-3)
focus(7,-3),(-3,-3)
ecentric :::5/4 thanku so much mama' to my help for to make easly solve and save my important time for attemp next question in nda exam ....
Very helpful video mam so thx
Very beautiful mam
Came here after three year
Super trick mam it so usefull for me
Ma'am what to do when there's an xy term...can we still apply this?
Ma'am what if the "bxy" term is present?
Mam u r just awesome and from now I can win hyperbola with this sword😁😁 tnq so much.......
thank u i always felt difficult with hyperbola after watching ur video it is very easy thank u
No words🙇
Mam , can u say please it is linear equation how to perform those tricks
superoooo super
you really teaching good