I think that it is to be related to the time scale at which the elastic scattering process occurs: that is the absoprtion and "instantaneous" re-emission of radiation by the electrons, acting as dipoles at the microscopic level.
Francesco Vitale prof says “Energy can be transfered to matter without absorption”. I think this is a flat out wrong statement. The terms “Energy E” and “Absorption A” in optics can be linked to their mechanical definition with dE = F.dx and A = -dP/dx with P as power defined as time rate of energy exchange between two systems. These two definitions should show the interdependence of absorption and energy. What am i missing? Thnx
I know that this comment in quite old but just to give it a try. I think he just said absorption implying resonant absorption while here he is talking about parametric optics so non resonant absorpion (like scattering). Meaning that he is talking about a transfer of energy to matter that is much lower than the energy necessary to an electronic transition but only to a virtual state.
@@jellyfish1679 The transfer of energy is usually done by absorption and emission where the photon is absorbed or emitted by the electron. There is a set of phenomena called scattering where there is no absorption/emission but an interaction at a distance (mediated by a virtual photon), however that's a more specific case. So, If matter is "a perfect reflector" the energy will not be changed except to change the direction in which it is moving (in fact even for the case of scattering, the electron absorbs the photon and re-emitted another photon with the same frequency with a random direction...)
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at 34:54, is there a typo for the expression of centrosymmetrical potential? The restoring force term should not contain order of even, rigtht?
At about 30:45, the lecturer says that energy can be transferred without absorption. How is this possible?
I think that it is to be related to the time scale at which the elastic scattering process occurs: that is the absoprtion and "instantaneous" re-emission of radiation by the electrons, acting as dipoles at the microscopic level.
Piyush Raj i have same question its very confusing statement!
Francesco Vitale prof says “Energy can be transfered to matter without absorption”. I think this is a flat out wrong statement. The terms “Energy E” and “Absorption A” in optics can be linked to their mechanical definition with dE = F.dx and A = -dP/dx with P as power defined as time rate of energy exchange between two systems. These two definitions should show the interdependence of absorption and energy. What am i missing? Thnx
I know that this comment in quite old but just to give it a try. I think he just said absorption implying resonant absorption while here he is talking about parametric optics so non resonant absorpion (like scattering). Meaning that he is talking about a transfer of energy to matter that is much lower than the energy necessary to an electronic transition but only to a virtual state.
@@jellyfish1679 The transfer of energy is usually done by absorption and emission where the photon is absorbed or emitted by the electron. There is a set of phenomena called scattering where there is no absorption/emission but an interaction at a distance (mediated by a virtual photon), however that's a more specific case. So, If matter is "a perfect reflector" the energy will not be changed except to change the direction in which it is moving (in fact even for the case of scattering, the electron absorbs the photon and re-emitted another photon with the same frequency with a random direction...)
Where can I get these slides?
Do you answer questions here prof Boulanger? Thnx
Very good lecture