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Nice
Paano po kapag yung type of load is 6Aa/L = 5/32 (wL)^3, paano iyon ma derive for integration?
Can i ask ? why Mc is 0? Can you explain it? thanks ^^
Simple end support (hinge, roller) is always zero. Simple end supports are only capable of resisting forces, not moments.
Can You help me?
Sir, bakit hindi 1 to 3 ang limit ? sa 6Aa/LL
Same question din po .Bat ang 0 to 2 ang boundary at hindi 1 to 3 ??
0 to 2 po dahil ang reference ng x ay ang start sa location ng distributed load. if yung reference ng x ay starting from the leftmost side (point A), 1 - 3 po ang limit ng integration, tapos yung a = x and b = 3 - x. Same lng 14 yung answer
Sir bakit po kaya 0 moment sa c? salamat
Naka Pin/hinge type support po kasi sa Point C
@@pinoyipsum1405 ahh thank you sir!
I hsve ? Any email ?
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Nice
Paano po kapag yung type of load is 6Aa/L = 5/32 (wL)^3, paano iyon ma derive for integration?
Can i ask ? why Mc is 0? Can you explain it? thanks ^^
Simple end support (hinge, roller) is always zero. Simple end supports are only capable of resisting forces, not moments.
Can You help me?
Sir, bakit hindi 1 to 3 ang limit ? sa 6Aa/LL
Same question din po .
Bat ang 0 to 2 ang boundary at hindi 1 to 3 ??
0 to 2 po dahil ang reference ng x ay ang start sa location ng distributed load. if yung reference ng x ay starting from the leftmost side (point A), 1 - 3 po ang limit ng integration, tapos yung a = x and b = 3 - x. Same lng 14 yung answer
Sir bakit po kaya 0 moment sa c? salamat
Naka Pin/hinge type support po kasi sa Point C
@@pinoyipsum1405 ahh thank you sir!
I hsve ? Any email ?