Switching between V_x (in the first part of lecture, also lecture 3) and V_z (in the latter) can be confusing. Probably better to consistently use V_z throughout since flow is in z-direction.
Science students are normally trained to look at height/depth as z direction from very early on, so I agree it is very confusing; another confusion arises because of angle Beta is shown from the verticle direction. If Beta increases (somewhere close to 16:30 min in the video), the angle of inclination (which is from horizontal) actually decreases!
The z component of the weight of the film is balanced by the shear force acting on it and therefore, the thickness of the film must come in the final expression (to calculate the total weight of the liquid film).
Very detailed Examination in marvelous way ! Thanks !
Switching between V_x (in the first part of lecture, also lecture 3) and V_z (in the latter) can be confusing. Probably better to consistently use V_z throughout since flow is in z-direction.
Science students are normally trained to look at height/depth as z direction from very early on, so I agree it is very confusing; another confusion arises because of angle Beta is shown from the verticle direction. If Beta increases (somewhere close to 16:30 min in the video), the angle of inclination (which is from horizontal) actually decreases!
Great lecture sir
20:03 why is there 3 in the denomenter
Thank you sir i liked your lecture
Best
Should there be the delta(thickness) term in the force acting on the solid plate due to the liquid moving on it?
The z component of the weight of the film is balanced by the shear force acting on it and therefore, the thickness of the film must come in the final expression (to calculate the total weight of the liquid film).
Thank you for the helpful clarification.
Thank you sir🙏🙏
Lecture 04
There should be 6 in denominator in place of 3 .... Because 2 is already there in denominator of vz
Not actually true. Inside the right parenthesis there comes 2lambda/3 and 2/3*1/2=1/3
@@mr.mcfife4131 how did we get (2/3)
If you carry through the integration you get (rho*g*d^2*cosB)/mu (1/2 - 1/6), which ends up having the denominator given in the video
hi @@jasonwilkening8036 how do you get the 1/6 in the denominator?