I've watched a lot of instructional videos in technical subjects and you are among the clearest teachers I have ever seen. I hope you keep making these videos, because I'm sure you're helping a lot of people.
THANK YOU SO MUCH ... this is really useful and understandable but i have a simple question in the problem question... how would i know if Ay is going up or going down, also Ax how to know if it's to the left or to the right? thank you
It doesn't matter which direction you draw it as long as you include it in your free-body diagram. If you draw it the wrong way originally, your equation will produce a negative number. This tells you your arrow is pointing the wrong direction. Say if you drew Ay pointing up and your equation produced -25 N, you could say that the force Ay is actually 25 N downwards. Hope this helped.
If we sum up Moments about A The equation has the term -(-Tx6) for the cw moment and negative force (down). Is this correct? That's only way T will come out as a negative value (-140).. Subbing this value into sum of forces in y would give a double negative value which would give me the wrong answer for Ay though. Or do I ignore the negative value for T when substituting in the moment equation.. then the answer comes out as +ve but I drew my arrow for T down, would that be correct? Thanks for the video!
Ah okay, thanks i must've missed a digit, your video was great i was just doing some revision for tomorrows tutorial, hopefully i find it a bit easier now. :)
I've watched a lot of instructional videos in technical subjects and you are among the clearest teachers I have ever seen. I hope you keep making these videos, because I'm sure you're helping a lot of people.
I am from Uganda Africa but really enjoying your outstanding lectures pliz keep up.
Please put more videos on the rest of the chapters of Statics. You're explanations are so clear! Thank you.
Wow, you're really good. You hit the points so clearly. Thank you very much!
Thank you very much, I really like how you explained the problems with real life examples. It was very helpful. Thanks again
I hope all the instructor are like you!!!!!!!!!!
Watching from India and you are very good ...
thank you sir for your wonderful lecture
I love engineering; it is so good! thanks, professor, you are an amazing teacher.
Professor, you explain so nice and clear... Well done... God Bless you and enhance your ability.
thank you very much, you really help me a lot
Outstanding lecture.
Hello sir,
Where can I find the entire playlist for engineering mechanics
I really love your short videos but how can I get the clips together for the whole course unit,I really request for an urgent response.thanks.
thank you so much sir!!! that was extremely helpful !
Your so great.. I hope our instructor will be like you sir.
outstanding thank you sir
Thank You! This video is so helpful.
THANK YOU.
Thank you!
I thought we're measuring force here? you should convert that into Newton or any other unit of force.
You are really outstanding.pliz help me on how to get these videos together thanks your student.
You're good.
Thank so much
Very helpful
Thanks alot Dr jawa
sir make more and more videos its really helpful
nice ever sir g
thanks Dr jawa
THANK YOU SO MUCH ... this is really useful and understandable
but i have a simple question
in the problem question... how would i know if Ay is going up or going down, also Ax how to know if it's to the left or to the right?
thank you
It doesn't matter which direction you draw it as long as you include it in your free-body diagram. If you draw it the wrong way originally, your equation will produce a negative number. This tells you your arrow is pointing the wrong direction. Say if you drew Ay pointing up and your equation produced -25 N, you could say that the force Ay is actually 25 N downwards. Hope this helped.
If we sum up Moments about A The equation has the term -(-Tx6) for the cw moment and negative force (down). Is this correct?
That's only way T will come out as a negative value (-140).. Subbing this value into sum of forces in y would give a double negative value which would give me the wrong answer for Ay though.
Or do I ignore the negative value for T when substituting in the moment equation.. then the answer comes out as +ve but I drew my arrow for T down, would that be correct?
Thanks for the video!
amazing
I hop Thank you very much, I really SIR
@Avancini
excellent
what is the value of Ax and Ay @ pin A ?
what's the difference between the roller and rockers
Roller support is the term widely used. Rocker support is kinematically the same. No difference. Just another name.
I got 237.5 lb's for the A.y force, :L not sure how though, 1425 divided by 6 wasn't it?
No. You will get 1470 divided by 6 which is equal to 245.
Check 15*28 + 20*22 + 35*14 + 20* 6 = 1470
Ah okay, thanks i must've missed a digit, your video was great i was just doing some revision for tomorrows tutorial, hopefully i find it a bit easier now. :)
thanks shah rukh khan . hehe
PLEASE DON'T USE A SHARPIE MY EARS
Asian Teachers are really good if you can understand their accent.
In my uni all the lecturers are lazy as f
very bad