Solution for equivalent evaporation is wrong.. As we have to take formula ma(h2-hf1)÷2257 Where ma=ms/mf You have taken directly ms which is wrong So ans comes as 9.11 and not 6106.4... So plz correct that..
Mass of water evaporated =2600kg Mass of fuel used = 305 kg CV of fuel used= 31000 KJ/Kg Pressure of steam generated = 0.96 Feed water temperature = 32°C Calculate actual evaporation, equivalent evaporation and boiler efficiency. Sir please solve it.
Solution for equivalent evaporation is wrong..
As we have to take formula ma(h2-hf1)÷2257
Where ma=ms/mf
You have taken directly ms which is wrong
So ans comes as 9.11 and not 6106.4...
So plz correct that..
Please explain
me=6106 kg/hr , me =9.11 kg/kg of coal
Yes you are right
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Mass of water evaporated =2600kg
Mass of fuel used = 305 kg
CV of fuel used= 31000 KJ/Kg
Pressure of steam generated = 0.96
Feed water temperature = 32°C
Calculate actual evaporation, equivalent evaporation and boiler efficiency.
Sir please solve it.
3:12 , sir how can you say that the steam is in wet region with x2 value??
Sir mass of steam nahi diya hai or water evaporated diya hai to isko kese solve kare
Sir please upload lectures on worm and worm wheel and on bevel gear of machine design 2
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