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x^(3log3) + 3^(2logx) = 363^logx = x^log3 = uu³ + u² = 36u³ - 27 + u² - 9 = 0(u - 3)(u² + 4u + 12) = 0u = 33^logx = 3 => logx = 1 => *x = 10*
(3^3)^(logx)+(3^2)^(logx)=36 , let u=3^logx , u^3+u^2+/-u-36=0 , (u-3)(u^2+4u+12)=0 , 3^logx=3 , logx=log3/log3 , x=10^1 , x=10 , 1 -3 test , 10^(log27)+9^log(10)=27+9 , --> 36 , OK , 4 -12 12 -36
x^(3log3) + 3^(2logx) = 36
3^logx = x^log3 = u
u³ + u² = 36
u³ - 27 + u² - 9 = 0
(u - 3)(u² + 4u + 12) = 0
u = 3
3^logx = 3 => logx = 1 => *x = 10*
(3^3)^(logx)+(3^2)^(logx)=36 , let u=3^logx , u^3+u^2+/-u-36=0 , (u-3)(u^2+4u+12)=0 , 3^logx=3 , logx=log3/log3 , x=10^1 , x=10 ,
1 -3 test , 10^(log27)+9^log(10)=27+9 , --> 36 , OK ,
4 -12
12 -36