Inequalities 03 | Different types of Problems | Class 11 | JEE | Pace Series
HTML-код
- Опубликовано: 15 сен 2024
- Watch Ad Free Videos ( Completely FREE ) on Physicswallah App(bit.ly/2SHIPW6).
Download the App from Google Play Store.
Download Lecture Notes From Physicswallah App(bit.ly/2SHIPW6)
Notes Available at Home Page of the App(Home--Pace)
PACE - Class 11th :
Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
Duration:-3months (Nov 2020 - Feb 2021)
Free Batch Exclusive on our RUclips Channel:PhysicsWallah-Alakh Pandey
Batch Details
1)Best Faculties across India for different Subject/Topics.
2)Complete & Relevant Syllabus Coverage of Class-11th within 3 Months- Fastrack Nov 20,2020-Feb 20,2021
3)Monday-Sunday : scheduled Classes everyday ( for each Physics, Chemistry,Mthematics & Biology)
4)FREE videos without ad available on app
5)Notes Link on Description
Physics:Tues,Wed,Thur,Fri,Sat : 3:00 pm
Chemistry: Physical & Inorganic Chem: Mon,Tue,Wed,Thur,Fri:7:00 pm|| Organic Chemistry:Sat,Sun : 9:00 pm
Mathematics:Wed,Thur,Fri,Sat,Sun: 5:00 pm
Biology:Wed,Thur,Fri,Sat,Sun: 10:00 am
4)Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
Lakshya Batch-Complete Physics for Class 12th BOARDS/JEE MAIN/NEET
Yakeen Batch-Complete Fastrack Course(11th & 12th) for NEET
Accelerate Batch-Complete Fastrack Course of PCMB for Boards/NEET/JEE Mains
Prayas Batch-Complete Fastrack Course of PCM for JEE Mains &JEE Advanced
For more Details of the Batches visit PhysicsWallah App(bit.ly/2SHIPW6)
New RUclips Channel : PhysicsWallah Foundation-9th & 10th: / @pw-foundation
Physicswallah Instagram Handle : / physicswallah
Physicswallah Facebook Page: / physicswallah
Physicswallah Twitter Account : Ph...
/ rohitgupta.pq
Physicswallah App on Google Play Store : Ad Free Videos ( Completely FREE ) on Physicswallah App(bit.ly/2SHIPW6).
Download the App from Google Play Store.
Download Lecture Notes From Physicswallah App(bit.ly/2SHIPW6)
Notes Available at Home Page of the App(Home--Pace)
PACE - Class 11th :
Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
Duration:-3months (Nov 2020 - Feb 2021)
Free Batch Exclusive on our RUclips Channel:PhysicsWallah-Alakh Pandey
Batch Details
1)Best Faculties across India for different Subject/Topics.
2)Complete & Relevant Syllabus Coverage of Class-11th within 3 Months- Fastrack Nov 20,2020-Feb 20,2021
3)Monday-Sunday : scheduled Classes everyday ( for each Physics, Chemistry,Mthematics & Biology)
4)FREE videos without ad available on app
5)Notes Link on Description
Physics:Tues,Wed,Thur,Fri,Sat : 3:00 pm
Chemistry: Physical & Inorganic Chem: Mon,Tue,Wed,Thur,Fri:7:00 pm|| Organic Chemistry:Sat,Sun : 9:00 pm
Mathematics:Wed,Thur,Fri,Sat,Sun: 5:00 pm
Biology:Wed,Thur,Fri,Sat,Sun: 10:00 am
4)Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App :bit.ly/2SHIPW6
Lakshya Batch-Complete Physics for Class 12th BOARDS/JEE MAIN/NEET
Yakeen Batch-Complete Fastrack Course(11th & 12th) for NEET
Accelerate Batch-Complete Fastrack Course of PCMB for Boards/NEET/JEE Mains
Prayas Batch-Complete Fastrack Course of PCM for JEE Mains &JEE Advanced
For more Details of the Batches visit PhysicsWallah App(bit.ly/2SHIPW6)
New RUclips Channel : PhysicsWallah Foundation-9th & 10th: / @pw-foundation
Physicswallah Instagram Handle : / physicswallah
Physicswallah Facebook Page: / physicswallah
Physicswallah Twitter Account : Ph...
Physicswallah App on Google Play Store : bit.ly/2SHIPW6
@ 36:20 Yes sir, I understood I) Inequality involving quadratic factors
ii) Inequality involving repeated factors
iii) Inequality involving Double inequalities
👍❤❤❤❤❤❤❤❤❤❤❤👍
Thank you so much sir 🥰🤟
we can write (x3 + x2 + x + 1) as (x+1)(x2+1) and
(x4-4) as (x2-2)(x2+2) further,
(x2-2) can be written as (x-root2)(x+root2)
so, (x+1)(x2+1)(x-1) / (x-root2)(x+root2)(x2+2) >= 0
further, (x2+2) and (x2+1) are always +ve
so, (x+1)(x-1) / (x-root2)(x+root2) >= 0
so critical points are -1, +1, -root2, +root2
so the final answer is :
(-infinity, - root2) U [-1,1] U (root2, infinity)
sorry sir number line comment mein nhi bana paya
thanks for the steps:)
wrong answer first of all your roots except (x+1) are wrong as -1/2 & 1 are not the solution to the cubic equation
@@ananyasingh5409 can u explain please?
@@ananyasingh5409 I got the same answer as his
@@ananyasingh5409 to kya answer aaega bhai batade
Sir,
The answer of the homework question is
X = ( - ∞, - √2) U [ -1,1] U (√2, ∞ )
👍
Great jobe ( padhte raho ek daam bhannat)
😂😂😂😂😂
@@utkarsh5230 job hota h wo jobe ni😂😂😂😂😂
..anpadh.
Correct
Can i get the full soln
Sir homework ques solution
(x³+x²+x+1) {taking it separately only to simplify}
x³+x²+2x+1-x
x³-x+x²+2x+1
x(x²-1)+(x+1)²
x(x+1)(x-1)+(x+1)²
[x+1](x²-x+x+1)
[x+1](x²+1)
Now solving ques
(x+1)(x²+1)(x-1)/x⁴-4>=0
Critical pts are -√2,-1,1,√2
Hence solution are x€(-♾️,-√2)U[-1,1]U(√2,♾️)
45:55 H.w. answer:-
=>(x^3+x^2+x+1)(x-1)/(x^2+2)(x^2-2) ≥ 0
=>(x+1)(x^2+x+1)(x-1)/(x^2+2)(x^2-2) ≥ 0
Of which (x^2+x+1) is always positive (a>0 & d(x+1)(x-1)/(x^2-2)≥0
=>(x+1)(x-1)/(x+√2)(x-√2)≥0
Critical points at (-√2,-1,1,√2)
Final answer is:-
x€(-∞,-√2) U [-1,1] U (√2,∞)
bro its wrong answer
@@Progamers-yp4nf what is the ans then??
Answer of given hw question is ;
(-infinity, -√2) u[-1, 1]u(√2, infinity).
Yup
Yahi mera aya
yes it is right
Koi explanation dedo
Jai Jagannath Swami❤️❤️
Jai jagannath swami
Jai jagannath 🙏
Odisha se ho yaar 🙋🏻♂️🙋🏻♂️
@@dibyajeebanprakashrout6051 lagta to he
Odisha se Ho kya Bhi..
46:00 homework
x€ (-infinity,-√2)U[-1,1]U(√2, infinity).
Same to same answer bro
Mine is also same
Answer bhej do yaar
Bro [-1,1] ?
√2⁴=4 or ( -√2)⁴=4
and x⁴-4......
=4-4
=0. 🔥
If denominator is equal to zero. then the equation = Undefined (Shnnata maha Pap🙏)
Solution composites of some of the following steps -
1- x²-1/x⁴-4≥0
2-(x²+1)(x²-1)/(x²+2)(x²-2)≥0
3-(x+1)(x-1)/(x+2½)(x-2½)≥0
4- Solution is x€ (-infinity,-2½)union [-1,1] union(2½,+ infinity).
sahi hai
How did x²-1came in numerator
@@harrshpadhiyar7793 numerator me jo hai usme bracket open karega to (x^4-1) niklega to usse (x^2-1)(x^2+1) factorize hoga....samjha...?
@@19-adanish93 ya tysm
@lalit sandhu tell me time where sir has solve such type of ques
x belongs to (-infinity , -square root 2 ) U [-1,1] U ( square root 2 , infinity ) i hope this is the right ans sir and today's lecture was amazing all understood bhannatly
Sir, I am Anik and my answer for HW question is x€ (-infinity,-√2)U[-1,1]U(√2 , infinity).
Sir I understood everything you taught. But for me wavy curve was more convenient. Thank you 💗
How you got the answer?
I am not getting it 😢
@@Rishabh-xk5oh bro I am in 10th and preparing for a competition and I easily solved what is so difficult about it ?
@@garoutheherohunter8613 so what should I do?
@@garoutheherohunter8613
If cosQ=pi, then what will be the value of Q?
SIR,GRAPH WALA TOPIC KAHA HAI INEQUALITIES KA
Quadratic equation ma hai
@@azharmohammad89 can u give the link
@@arpitrajput5485 nahi😂
ruclips.net/p/PLF_7kfnwLFCFQTjfpSNlkcenoHlFKamrE
ruclips.net/video/aUzfeX3jPq4/видео.html
sir thodi gadbad ho gai thi lekin wapas try krne se ho gaya
homework:
x € (-infinity,-√2) U [-1,1] U (√2, infinity)
Bhai kaise Hoga Mera to ahi nhi rha help me
Are bhai
pahale dekho question me (x3+x2+x+1)ko (x2+1)(x+1)likha sakate he phir dekhana ki (x2+1)always +ve he or denominator me bhi (a2-b2)ki identity lage gi or vaha ban jayega kuch aase (x4-root2ki power4) phir solve kar lena simple way me
@@lifechanging735 bhai tera answer ye aa rha h kya
X€ (-infinity, -√2] U [ -1,1 ] U [√2, infinity)
@@lifechanging735 thank bro
Merea sahi hai✌
Last question
Ans=> x€(-infinity, -√2) U [-1,1] U (√2, infinity).
Answer is = (-infinity,-1]u[1,+infinity)
Answer of homework question :-
x belongs to (-infinity, -√2) U [-1, 1] U (√2, infinity)
Sir sab kuch samajh aa raha hai
Galat
@@jahnabidas108 nahi upar wala sahi hai
@@habunglarin2319 ha, upar wala sahi h
Hw question ans.(-infinity,-root2)union[-1,1]union(root2, infinity) I did it in 4 minutes 43 seconds
Sir hw question ka solution:x:(-infinity,-√2)U[-1,1]U(√2, infinity)
😊
No your answer is wrong because if we put negative or positive values of root 2 so the denominator will be zero and it is crime according to bhannat sir😅😅😁
Ans of hw ques (-infinity,-√2)U[-1,1]U(√2,♾️)
Method
Final factors are
(x+1)(x-1)(x^2+1)/(x^2+2)(x-√2)(x+√2) in which two factors are always positive.. plotting other on number line I got this ans..
Sir aapne Kamal kardiya
Jo cheez mai ek saal se nahi samajh payi use mai theen episode se samajh liya
Thanks a lot sir
47:15 Sir answer of last question is
X~ (-infinity, -root2) union [-1,0) union(0,1] union (root2,infinity)
How? Please explain friend 🙏
Answer of H.W is sir
(-infinity,-Root2) U [-1,1] U[ Root2, +Infinity ]
Yup!
Sir ,answer of homework question is
x€ (-infinity,-root2)union[-1,1]union(root2,infinity)
Last expression was
(x+1)(x-1)/(x+root2)(x-root2)_>0
Ans to ques is
(-∞, -√2) U [-1, 1] U (√2, ∞)
yes that's right!
x belongs to (-infinity,-root2) union [-1,1] union (root2,infinity)
45:55 answer of Homework question is =
X=(-infinity,-2)U[-1,1]U(2,infinity)
Sir ans. Of Hw question is :
(-infinty, -√2) U [-1, +1] U (√2, infinity)
I am first with my 100 friend's
bai kya hum 25:31 me jo question hai usse ase solve kar sacte hai kya
(x(x+6)(x-3))/((x-4)) >0
(slove karke)
ke critical point nikala aur numberline plot kiya then aaage ka process kare.
kyo ki (x+2) always positive hote ai aur (x-4)^3=(x-4)^2*(x-4) hota hai aur (x-4)^2 always positive hota hai
ess method se karne se answer same i aata hai.
kye ye method correct hai or not
ruclips.net/video/c75Uc9UQbvI/видео.html
@@nobeldude bhai nice try
@Ansh Todwal awwww....😂😂
Sir x€ (- ♾️,-root2) union [-1,1] union(root , ♾️)
*Every one is crazy to become first viewer 😂 of the bhannat lecture.*
😁good but Focus on Study.
All the best.
Bhai tujhe aman sir or chem wale sir same dikhte h kya pta ni kyu mujhe lgte h😂
@@darkdevil5960 mujhe bhi.🙂
@@gamingforindianarmy3908 😂😂😂😂😂 shi h
@@tcoregaming1679 yes
Sir, Difference types of inequality is clear to me.
HW solution:-
Ans:- x€ (-infinity, -√2) U [-1,1] U (√2, infinity)
NAME:- ADITYA KUMAR
IMPORTANT MESSAGE FOR PACERS
aaj mein bohot khush hu kyuki jab mein aaj unacademy jee ke live mock test mein Trigo ka Q dekh rahi thi tab ek Q ka ans Ans direct sir ke formula Sin(theta).Sin(60-theta).Sin(60+theta) =1/4 Sin(3theta) se aa raha tha but unacademy ke sir ne yeh formula se nahi kiya and thoda legthy ho gaya woh!!!!! THANK YOU SO MUCH TO PW TEAM FOR SAVING OUR TIME AND TELLING THE TRICKS.
PS- Please reply me about it
THANK YOU
yes sis i know this aman sir ne trigo bhut bhannat samjhaya tha
lekin unacademy wale bhi ache hai but not as good as pw
waise level kaisa tha mock test ka??
@@iit1949 mein bhi 11th mein hi hu meko aise hi live aaya and maths ke Q kara rahr the and randomly trigo ka q aaya which was kind of our trigo so I could relate it
Thnx
@@kavitathakkar9727 ok 😇😇u have taken pcm or pcbm??
Sir sister this is the power of bhannat concept❤️❤️
@@iit1949 pcm
45:00 sir jaab ve question mai greater than ya great than equal to rahta hai taab positive wala area solution hota hai aur jaab smaller Or equal to hoat hai taab negative answer hota hai.....
Homework ka solution - infinity sai + infinity hoga . I think it is right....
Homework hint:-
X⁴ ka critical point -root 2 and root 2
And numerator ka critical point-1 and 1
Thanks for helping bro 🔥
45:55
Ans1: range of x=[-1,+1]
Syad galat h apka answer
Wrong answer
Answer of homework question
(-infinite,-✓2) union [-1,1] union (✓2, infinite)
Homework ans
x€(-infinity,-√2)U[-1,+1]U(+√2,infinity)
very helpful lecture.thanks sir💖
The answer of homework is x€(-infinty,-√2)U[-1,1]U(√2, infinity)
☺pehli baar mujhe maths ke teacher achche lage thank u sir life me ek baar apse milunga ekdam bhannat tarike se
XE [ INFINITE ,-root2 ] U [-1,1] U [root 2 ,INFNITE ] is the answer
Correct brother, only bracket mistake 😊
36:00
Sir solution is:
x belongs to(-infinity,-root2) Union[-1,1] Union(root2,infinity)
Sir it took me quite a lot of time to crack it but I didn't give up. Hope hai ki hamare favourite Bhannat Sir se mujhe bhi Shoutout mile bade sohbhagay ki baat hogi mere liye Thankyou for everything Aman Sir love you 3000
YuP bro you'r first
Congrats!
Can you please explain it?
The answer of HW Question is X € [-1,1]U(√2, infinity)
Ans :- (infinity, -√2]U[-1, 1]U[√2, infinity) 🙏🙏🙏♥️♥️
bro starting me - infinity hoga btw correct answer
bhai root 2 pe open bracket lagne chayie na
Homework answer is (-infinity,-√2)u[-1,1]u(-√2,infinity) where u denotes union
Thank you sir.
Thank you very much for this topic's videos, you have made this chapter so easy
ans of hw question is 46:00 is x belongs to (-INFINITY,- SQUARE ROOT 2) U [-1,1] U (SQUARE ROOT 2 , INFINITY )
Sir Garib logon ki bache keliye ap masiha ho... Kiyon ki sir hum lok bade institute me bada amount deke padh nehi sakte ..... App hum logon ko marg darsa rahe hen.... App ko hriday se mera namaskar.... Agar mere ko IIT milta hai to app ke abdan hoga .... NAMASKAR....
Absolutely right
Sir,The Answer of Homework Question is..
=(-√2,√2)u[1, infinity)
Sir,I take Critical points -√2,√2,1.
My Name is Aayush.
I hope u Check It.
💯💯💯💯💯💯💯💯💯💯💯💯💯
Sir understood everything bhannatally....sir i understand everything you explain from explaination to question solving..... bss sir ek baat smjhado ki aap or amit sir brothers ho??😂😂
wo bhi judwa bhai??
ans of the last question- (-infinity,-root2)U(-1,1)U(root2,infinity)
sir last question ka answer hai
x belongs to (- infinity, - root 2) u [-1,1] u ( root 2, infinity)
Same
Same
bro can you please share the link of ur photo for the question ... plz
SIR THE ANSWER TO THE LAST HOMEWORK QUESTION IS:
(-∞,-√2] U [-1,1] U [√2,∞)
FOUND BY SIMPLIFYING NUMERATOR(bhannnattly)
THEN AFTER USING IDENTITY
USED WAVY CURVE METHOD
Last que
Ans : (-♾️ , -√2) U [-1,1] U (√2 , ♾️)
(-INFINITE root2 )U[0 -1]U(root2 +infinits)
Sir we want teachers like you. You made me love maths.
Sir left pw
Really??.. Why?
@@chhavibhalladz yes
And sir start there own RUclips channel
first time in history that any education lectures starts like as a Hollywood movies.
(-infinity,-root2)union[-1,1] union (root2, infinity)
I just pause the session and attempt the last question of double inequality and my answer is right ....I am really very very happy 😁😁
My also
Can you please tell the solution??
Mera bhi aya 🙄🙄🙄🙄
Ladkiyo ki yehi problem h.thoda ques kya solve hua.ki khush ho gayi🤔😂😂😂😄😄
Homework answer is (- ♾️,-√2] union [-1,1] union [√2, ♾️)
Explanation?
Sir, I understood each and everything thing Bhannaatly.....
Thank You sir 🙏
33.20 answer will be (-infinity,0) U [2,3]
Sir aap bhaut achha padhate ho👍👍👍👍
Sab kuch clear hota hai
Yeah
Answer of H.W. - X belongs to (-infinity, -root2) U [0,1] U (root2, infinity)
Power of physics wallah..
1 minute .. 144 likes 👍👍
and only 13 views.. ❤❤
yes tis is the power of pw
wait what? ye kaise?
@@luckyboigaming6383 this is only a glitch of RUclips it's cannot display the actual viewer at time when video is uploaded
Sir,the answer of your last home work is X belongs to [_1,√2)union[1,infinitive)
Ultimate inspiration..... Of India
Mr alakh sir, ❤❤❤
Anyone fan of alakh Pandey here??? Like then
Sir answer is x€(-infinity,-✓2) union [-1,+1] union (+√2, infinity)
First baar question galat likh liya tha😂😂
Yeh wala chap. bahut asssan hai.
Sir the answer of homework question is x € (-infinity , -√2)U[-1,1]U(√2, infinity)
HW question solution
(-infinity, -√2) U [-1, 1] U ( infinity , √2) ..
Thank you sir. ❣️
Sir hmko phle pta nhi chala ki aap itna achaa pdhate hai, Maine 50000. Rupees mentors coaching Patna me de diye aur kuch samjh me bhi nhi aata hai
x belongs to (-infinty,-√2)U[-1,1]U(√2, infinity)
✌️✌️✌️✌️ Sir plzzz announce my name
Sir ek dum bhannst tarike s smjh m aaa gya h inequality 😌😌
Thankuuu sir❤️💜💜
kese kiya?
pls tell full solution
Sir answer is( -infinity, - root2) union [ - 1,1] union (root2,infinity) sir I have crack it on my first try!!!!! My name is Robin Rana from उत्तराखंड
12:10 Yes Sir , hum pure tameej se notes bana rahe hai 😊
answer of last Homework question - x belongs to (-infinite,root2)U [-1,1]U (root 2 ,infinite)
Bhai bade[ ] aur chhote( ) brocket kis rule se lagate hai plz bataye
sir aapke padhane ka level hi zabardast hai ......you dont stick to syllabus is the best thing in your lectures
Chinju
[-1,1]U(root 2,infinite)
Homework question answer : Simpilfy until ((x+1)(x-1))/((x+√2)(x-√2))
Is left since rest others are always positive ans :
x € (- ♾️,√2)U[-1,1]U(√2,♾️)
Sir last answer
X belongs to.
(-Infinity , -root (2) ) union [-1,1] union (root(2) , infinity)
Where is leacture 04 ?....…....………
Jay hind sir
Sir maine kabhi itne acche se kisi ko bhi linear inequalities padhate nhi dekha
Sir sab kuch samajh aa rha haj
he is teaching us in very cold winter night...salute to u sir...thanks for your videos..😃😃
Bhannat se H.w ho gya solve thanks you sir apne jo sikhaya usi se kiya or ho gya solve 👇👇👇👇👇👇👇
X belongs to (- infinity ,- √2) U [-1, 1] U (√2 , infinity) this is correct 100% because maine bohot bar kiya yahi aa raha hai sir .......😇.........
Sir apne to har question se ham logon ko linear inequality ka ek naya concept sikhaya 👍👍👍👍👍👍👍
36:18 sir sab samajh aa gaya bhannatly
Sir you are our God😭😭😭🙏🙏🙏
Thanks
You are best teacher of maths
Sir, Answer of Homework Question.....
(X3+X2+x+1)(x-1)/x4-4>or equal to zero
On Multiplying...x4+X3+X2+x-x3-x2-1/x2-2)(X2+2)
On simplyfying
x+1)(x-1)X2+1)/x2-2)(X2+2)
Now x2+2,x2+1 is always positive
So on simplyfying 😀
x+1)x-1)/x2-2>equal to zero
On simplyfying 😀
x+1)(x-1)/x+✓2)(x-✓2
Can find Root sign in my mobile so ✓ sign is used
Final Answer --------- x€[-inf,-✓2)U[-1,1]U(✓2,inf.) Wahi +,-,+,-,+,- krke ....Thnkyou 🙏
❤
Range of x =(-infinty,-√2)U(-√2,+√2)U(+√2, infinty)
Sir answer to last question is
( -♾️ , -√2 ) U [ -1 , 1 ] U ( √2 , ♾️ )
sb bhanat samjh aa raha hai
Tune Sachin Pant ka answer copy kiya hai
I knew people would think that, I solved the ans. on my own and put it before seeing the comments
@@kt3942 ohk
Ans of last que.
X € ( infinity , - root 2 ] U [-1,1] U [root 2 , infinity )
Thanku sir
I will try next tym to watch the session as soon as possible 🙂 is baar to ni aayga naam😅😅
Answer is x: (-infinity , -√2] U [ 1, √2 ] . Sir ne bola tha toh cheating se parhez rakha and I now I am very confident for my answer
0:22 our favourite" BHANNAT " 😅🤣🤣
I watched the video right now. so I am late to answer the homework question.
Answer of homework question:
x belongs to (-infinity,-√2)U[-1,1]U(√2,infinity)
Sir Hw question ka answer-
X € (-inf,-√2) U [-1,1] U (√2,inf)
Sir samajh a gya ekdm bhannatly🙂
-1 aur +1 ke agal bagal [ ] ye waala bracket lagega
(-infinity, -√2) U [-1,1] U (√2, infinity).
Not including √2 and -√2 because they are in denominator.
Bio students watching 5mins intro 😁
Ji nhi iitte vale ni hai....and ham par bhi maths hai....I'm also pcmb student 🙄😅
Mehne pcb students ki bat ki not pcmb🤭🤭
Okk 👍👍
@Abhishek Srivastava yes dude.....bio n math sath me karna thoda hard hai😅
X belongs to (-infinity , -√2] U [0,1] U [√2,infinity) will be the answer of last question... ❤️ Is this correct...?
I understand the inequality BHANNATLY. Sir par apka question ke sath itne important concept ko itna easily samjha dena bahut accha lagta hai. Main FIITJEE ka class bunk karke apka lecture dekhta hu
Sir, yeh ques. Mujhse around 30 min. Ma hua
Ans.X belongs to (-infinity,-√2)U[-1,1]U(√2,infinity)
Lekin par ab bhi doubt ho rha h ki answer right ha ya wrong
Sir aap 04 lecture kb upload karoga??????
ye complete nhi hai kya ?
Ans to the homework question is
(-œ , -√2) U [-1,1] U ( √2 , œ)
where œ= infinity.
How friend??? Plz share with me