First, this solution is groupings of 3, then 1. Variations let you figure out the light turkey with 2 comparisons from 4 to 9 turkeys. Let’s show 9, it contains a little more. So start by grouping the 9 into three groups of 3, call those groups A, B, and C. Balance A against B. If they do not balance, the lighter group contains the skinny turkey. If the balance, group C contains the lighter bird. For the group that contains skinny bird, balance one bird against another, omitting one bird. Similar reasoning gives you the lightweight in those three. Pok Yin has this right, but super concise description, lol…
I got another way. Put all turkeys on the scale at the same time. Then take out one by one. You will find out which one will be slightly less weight. lol
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First, this solution is groupings of 3, then 1. Variations let you figure out the light turkey with 2 comparisons from 4 to 9 turkeys. Let’s show 9, it contains a little more. So start by grouping the 9 into three groups of 3, call those groups A, B, and C. Balance A against B. If they do not balance, the lighter group contains the skinny turkey. If the balance, group C contains the lighter bird. For the group that contains skinny bird, balance one bird against another, omitting one bird. Similar reasoning gives you the lightweight in those three. Pok Yin has this right, but super concise description, lol…
hahah thank you for the detailed explanation Jo. You definitely got it :)
I got another way. Put all turkeys on the scale at the same time. Then take out one by one. You will find out which one will be slightly less weight. lol
3 3 then 1 1?😂😂
yesss you got it! :)