HOMEWORK ANS- l²-1/l²+1= sintheta •first we find sec theta by help of two eqn. •Costheta is found by reciprocal of sectheta •√1-(costheta)²=sintheta we will the values and simplify.
Mr pranav sir I am glad to see your teaching the you explain is so miracle.. sir i always fear from maths but you develop interest in maths keep continuing this session mt lovable pranav sir bahut accha padhahai dil sa ❤❤❤ dhyan waad ❤❤Pandey jeee❤❤
L^2-1/L^2+1 THIS ANSWER HAS CAME AFTER SUBSTITUTING THE VALUE OF SEC THETA IN THE EQUATION 1+TAN^2THETA=SEC^2THETA (AS WE HAVE ALREADY PROVEN THAT SEC THETA =L^2+1/2L WE CAN USE ITS VALUE TO FIND SIN THETA)
HW QUESTION….. ANSWER SIN =l*2-1/l*2+1 FIRST FIND SEC THEETA ,,, THEN BY RECIPROCAL WE GET COS THEETA . NOW BY IDENTITY SIN *2+COS *2=1 WE GET SIN THEETA THANKS A LOT FOR YOUR HARDWORK SIR❤️ ASHWANI
Sir Sec is equal to H/B Find value of P by Pythagoras and Sin is equal to P/H So value of P after solving was (l²-1)² So final ans is (l²-1)²/l²+1 Hope it's correct✅✅ I tried my best And sir kal ke session ka pdf bhi de dena plss
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HOMEWORK ANS-
l²-1/l²+1= sintheta
•first we find sec theta by help of two eqn.
•Costheta is found by reciprocal of sectheta
•√1-(costheta)²=sintheta we will the values and simplify.
Rajat Mehta
Homework=(l²-1)/(l²+1)
Terms of sin theta
Homework answer :
Sintheta = (l²-1)/(l²+1)
l²+1/l²-1
I am the first
Homework answer :
Sintheta = (l²-1)/(l²+1)
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Question me bola hai 60 degrees with wall and ladder apne 60 degrees with ladder and ground liya hai.
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Mr pranav sir I am glad to see your teaching the you explain is so miracle.. sir i always fear from maths but you develop interest in maths keep continuing this session mt lovable pranav sir bahut accha padhahai dil sa ❤❤❤ dhyan waad ❤❤Pandey jeee❤❤
Sir, sin theta = l²-1/l²+1 Name:- Adarsh Damsadekar
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L^2-1/L^2+1
HOMEWORK ANS- l²-1/(l²+1)=sin theta
√{1-(2l/l+1)^2
❤MATHS❤
(L² - 1) / (L²+1)
L^2-1/L^2+1 THIS ANSWER HAS CAME AFTER SUBSTITUTING THE VALUE OF SEC THETA IN THE EQUATION 1+TAN^2THETA=SEC^2THETA (AS WE HAVE ALREADY PROVEN THAT SEC THETA =L^2+1/2L WE CAN USE ITS VALUE TO FIND SIN THETA)
Team is op yr
Sir the answer of homework questions is
Sinø= (l²-1)/(l²+1)
cot (tan-1 α + cot-1 α).
Sin rhetha is equal to l^2-1/l^2+1
HW QUESTION….. ANSWER SIN =l*2-1/l*2+1 FIRST FIND SEC THEETA ,,, THEN BY RECIPROCAL WE GET COS THEETA . NOW BY IDENTITY SIN *2+COS *2=1 WE GET SIN THEETA THANKS A LOT FOR YOUR HARDWORK SIR❤️ ASHWANI
Sin thetha =l²-1/l²+1
Sir
Sec is equal to H/B
Find value of P by Pythagoras and
Sin is equal to P/H
So value of P after solving was (l²-1)²
So final ans is
(l²-1)²/l²+1
Hope it's correct✅✅
I tried my best
And sir kal ke session ka pdf bhi de dena plss
Ans. sin = l²-1/l²+1.
sin ø = (l^2 - 1) / (l^2+1)
SIR THE ANSWER OF THE HOME WORK IS Sin ó = l²-1/l²+1
THANK YOU SIR FOR THIS WONDERFUL SESSION I WAS 18 HRS WITH RESTART WITH MOTION AND I FELT THAT I SEPNT MY DAY VERY EFFECTIVE WAY THANK YOU SO MUCH 🩷🩷🔥🔥
Sin∅=(l²-1) / (l²+1)
Sin∅ = l² +1 - 2l /l² +1
This is after the prove of sec∅
By dental thinking
-Adarsh sahu
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Root under l⁴-2l²+1/l²+1
Sinetheta equal to root under l⁴-2l²+1/l²+1
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L^2-1/L^2+1
sintheta = l²-1/l²+1
l²+1/l²-1
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Sin theta = l²-1/l²+1
Sin theta=l+1/l-1
Sin = l^2-1/l^2+1
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Sin theeta = l²-1/l²+1
Done ✔