It's amazing 🤩 sir... Tomorrow I have semister exam on optical communication subject today I'm learning from your channel thank you so much sir for sharing 🤗🤗🤗
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us. Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
Your positive comments motivates me. Teachers like me just wants positive comment from student. Love from you guys means a lot to me. My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Components are chosen for a digital optical fiber link of overall length 7 km and operating at a 20 Mbit/s using an RZ code. It is decided that an LED emitting at 0.85 µm with graded index fiber to a p-i-n photodiode is a suitable choice for the system components, giving no dispersion equalization penalty. An LED which is capable of launching an average of 100 W of optical power [including connector loss into a 50 urn core diameter graded index fiber is chosen]. The proposed fiber cable has an attenuation of 2.6 dB/km and requires splicing every km with a loss of 0.5 dB per splice. There is also a connector loss at the receiver of 1.5 dB. The receiver requires mean incident optical power of-41 dBm in order to give the necessary BER of 10-10, and it is predicted that a safety margin of 6 dB will be required. Write down the optical power budget for the system and hence determine its viability.
The conversion of Tx power from mW to dB is not accurate. In optical communication systems, power levels are usually an absolute unit measured relative to 1 milliwatt (mW). So we can just use Ps = -10dBm and Pr = - 46dBm to get same answer but in this case it makes sense in the real-world context in which the calculation is applied.
i have a doubt. how the dBm is converted in to dB? i think the way used here is wrong. we can convert dBW to dBm using this formula P(dBW) = P(dBm) - 30 (The power in dBW (P(dBW)) is equal to 10 raised by the power in dBm (P(dBm)) divided by 10 )
*🔥All Premium Courses Link of Engineering Funda🔥*
docs.google.com/spreadsheets/d/1LeLxZPGiMB_ZDZggbZp3P7fK516pXYhVgZA__djNkWM/edit#gid=0
⬇ *Premium Courses of Engineering Funda* ⬇
✅ *༺🚩ARM Processor 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7nFEozQhZDZDSm09SwqbGP
✅ *༺🚩Microprocessor 8085 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5vHwmowy_kGtjq9Ih0FzwN
✅ *༺🚩Microprocessor 8086 🚩༻* - ruclips.net/p/PLgwJf8NK-2e4oAeDid0hwuiol_RJdscrp
✅ *༺🚩AVR Microcontroller 🚩༻* - ruclips.net/p/PLgwJf8NK-2e55CdbY_WnY6pejPHoojCkJ
✅ *༺🚩8051 Microcontroller 🚩༻* - ruclips.net/p/PLgwJf8NK-2e49i6neo70aGtFLvKeZ3IQD
✅ *༺🚩80386 & Pentium Processor 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7f4yPj6AbrUoburKwX0fFA
✅ *༺🚩Embedded System 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5xvXygtghfi-tzyeACx7CO
✅ *༺🚩VLSI 🚩༻* - ruclips.net/p/PLgwJf8NK-2e6au9bX9P_bA3ywxqigCsaC
✅ *༺🚩Digital Electronics 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7nYSG31YWEUfwgAp2uIOBY
✅ *༺🚩Network Theory 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7AccPu8mUhhsJNol9uIKTJ
✅ *༺🚩Control Engineering 🚩༻* - ruclips.net/p/PLgwJf8NK-2e43et6qbo4IqYSJCv-6kN90
✅ *༺🚩Electromagnetic Theory 🚩༻* - ruclips.net/p/PLgwJf8NK-2e4I_YltJja47CwZJkzNWK89
✅ *༺🚩Power Electronics 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5Hnu82T1CYLZ8kbZs4Jx8x
✅ *༺🚩Basic Electronics 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5G05PTgyTTSVyzTOKRfmTn
✅ *༺🚩Signal and System 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7VdLw7PebRTcZXb_4nKeVh
✅ *༺🚩Optical Communication 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7CDIWsh61eItP9iRw1EIQc
✅ *༺🚩Analog Communication 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7uyUYrpgUUQowmRuKxRdwp
✅ *༺🚩Digital Communication 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5PngHbdEadEun5XPvnn00N
✅ *༺🚩Antennas & wave Propagation 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7tzLIDL4aXUbtRFY3ykmkT
✅ *༺🚩Microwave Engineering 🚩༻* - ruclips.net/p/PLgwJf8NK-2e6A4Mtxud6xPHE1UecxWsHW
✅ *༺🚩RADAR Engineering 🚩༻* - ruclips.net/p/PLgwJf8NK-2e4KmA52Jw3-JhDhFIDQZ9Bv
✅ *༺🚩Audio Video System / TV 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7EJcPI0P_DMw49ufTYfuOz
✅ *༺🚩Engineering Drawing/ Graphics 🚩༻* - ruclips.net/p/PLgwJf8NK-2e79xuABrIQeXYlGuuickEz7
✅ *༺🚩Basic Mechanical Engineering 🚩༻* - ruclips.net/p/PLgwJf8NK-2e7Fe4vAYDaL0bpseGNhc9on
✅ *༺🚩Mechanics of Solid 🚩༻* - ruclips.net/p/PLgwJf8NK-2e53xcLCS7ay2iLRolNxyxFk
✅ *༺🚩Theory of Computation 🚩༻* - ruclips.net/p/PLgwJf8NK-2e6GfXdwqWX5YmszV2KGv-yl
✅ *༺🚩Java Programming 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5BeN1WTXg1ENPtkRR3SfCI
✅ *༺🚩Python Programming 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5pY2eB-Lht2_CerQue0Xo4
✅ *༺🚩Placement Test series on C 🚩༻* - ruclips.net/p/PLgwJf8NK-2e5ovLgoJkv0Pn58UrucrTPt
✅ *༺ Please Share it with your friends to support us. ༻*
👉 *༺ You can also support us by joining us ༻* : ruclips.net/channel/UCdlnqMpRrMcClK2fT6z8EEwjoin
It's amazing 🤩 sir...
Tomorrow I have semister exam on optical communication subject today I'm learning from your channel thank you so much sir for sharing 🤗🤗🤗
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Ps = -10dBm , Pr=-46dBm
Pt=Ps-Pr
=( -10 ) - (- 46)
=36dB..........(when you are subtracting powers in dBm the resultant answer is in dB)
How to get value of ps
Superb sir.... Nice explaination 👌👌👍👍
Very helpful video sir
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
clear nice
All the subjects playlist of Engineering Funda is available in comment section. Share it with your friends to support us.
Your positive comments motivates me and person like me get boosted by my students feedback. Thanks and welcome 🙏
good class
Useful
Your welcome 🙏
@@EngineeringFunda system margin and safety margin both are same or different?
Awsom.... explaination....
Nice
Your positive comments motivates me.
Teachers like me just wants positive comment from student.
Love from you guys means a lot to me.
My goal is to create largest community of engineers in entire globe. Please help me by sharing this playlist with your friends.
Components are chosen for a digital optical fiber link of overall length 7 km and operating at a 20 Mbit/s using an RZ code. It is decided that an LED emitting at 0.85 µm with graded index fiber to a p-i-n photodiode is a suitable choice for the system components, giving no dispersion equalization penalty. An LED which is capable of launching an average of 100 W of optical power [including connector loss into a 50 urn core diameter graded index fiber is chosen]. The proposed fiber cable has an attenuation of 2.6 dB/km and requires splicing every km with a loss of 0.5 dB per splice. There is also a connector loss at the receiver of 1.5 dB. The receiver requires mean incident optical power of-41 dBm in order to give the necessary BER of 10-10, and it is predicted that a safety margin of 6 dB will be required. Write down the optical power budget for the system and hence determine its viability.
Please solve it for us
Hi! I wanted to ask... What would be different if this was for a WDM system?like would the losses be multiplied into the number of channels?? Or not
Sir is this also known as loss margin calculation
👍
Please drop the video in the form of .Pdf on the descriptions
Very helpful video, but your labeling made it a bit difficult to understand at the start.
Connector loss is only at reciever so it should be 1.5 itself
sir please try to reduce the surrounding sound noise in your videos...
The conversion of Tx power from mW to dB is not accurate. In optical communication systems, power levels are usually an absolute unit measured relative to 1 milliwatt (mW). So we can just use Ps = -10dBm and Pr = - 46dBm to get same answer but in this case it makes sense in the real-world context in which the calculation is applied.
dB is a adimensional unit, dBm is unit referred to 1 mW.... You can´t change that unit to other... your dB is dBW no dB
for Pr why did you minus 30 to convert from Db/Km to Db
It is dBm to dB conversation
The connector is only at receiver end it mentioned so connector loss is only 1.5
i have a doubt. how the dBm is converted in to dB? i think the way used here is wrong. we can convert dBW to dBm using this formula P(dBW) = P(dBm) - 30 (The power in dBW (P(dBW)) is equal to 10 raised by the power in dBm (P(dBm)) divided by 10 )
What you are saying is false
@@EngineeringFunda wow.
you are right.
@@EngineeringFunda sir please explain how you have converted dBm to dB
Someone plz tell me how would the calculation be different if this was a WDM system??
7:47 attenuation loss is 2L so it must be 2*25=50db right? Please correct it
That's alpha*L not 2*L
@@vinayakrpatel5029 yes
It's not 2
It's alpha
Alpha value 2.5
Length L value 10
Soo 2.5* 10 then it will be 25
How you convert dBm to dB??
dBm is decible of mili.
dBm = -30 dB
@@EngineeringFunda and please confirm me that losses if are in dm/km we should convert it to dB just or solve it in dB/km