How to calculate "Empirical Formula" || Super Trick Method with Q&A | Mole concept || NEET JEE

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[@sellermahi2172]

If you really want to know the trick to how to find emprical formula when percentage is given then start from 12:35

[@mayday1457]

thanks really time is very precious

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Thankx

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[@cdt.parveshjoshi2780]

Why didn't I see your comment . 😞😞

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Thxx

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[@anandshete9170]

%composition of H in H2O is 11.11 not 11.79
and %composition of O is 88.88 not 88.21 according to your calculations

[@alphaofficial914]

Yes man I am also confused

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Mera bhi 🙋🙋

[@shivdeepsalaria1137]

Itna hi pta ah too yaha kyu aaya ha

[@crazzysidd]

You are right Bro
😇

[@shyamsarkar7994]

Sir
In C2H5OH
% of carbon =52.17
% of hydrogen =13.04
% of oxygen = 34.78

[@ankitachaturvedi5994]

Kse smjh ni aaya 24 carbon or 6 hydrogen kse kha se aaya??

[@Jethalalsigma231]

@@ankitachaturvedi5994 Isme carbon ke 2 atom hai 1 atom ka mass 12 two atom = 12×2 = 24
Hydrogen ke 6 atom
1 atom ka mass = 1 U 1U × 6 = 6u

[@Ruhi1919]

C℅=52.17
%H=14.60
%O=34.7
These are % composition of C2H5OH

[@physicschemistry7448]

Percentage of hydrogen is wrong

[@physicschemistry7448]

Its 13.04

[@sumanasharma7251]

Sir, your way of teaching is extremely amazing

[@anjleenkaur65]

Good evening sir. 😊 🙏
Thanks for the lecture.. you are the best

[@dhruvdhruv9496]

sir please tell me how to solve the question " determine the emperical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass

[@sanjuverma2539]

Its an Example in Book

[@FunTime-tg7ki]

Take notes

[@unknownxyz2353]

Bhai Tera ans aayega fe2o3

[@unknownxyz2353]

Phele 69.9 ko approx 70 g = given mass man then divide by the atomic mass of fe that's 56 u will get 70 /56 = 20/16 or 5/4 . Now take 30.1 as given mass for oxygen / divide this by 16 g which is the atomic mass for oxygen . So u will get 30 /16 here I have approxed 30.1 to 30 now since 20 /16 is smaller divide 30 /16 by it and u will get 3 :2 = moles of o :moles of fe . Compare and get the formula Fe2O3 and also mf = ef ( Here the simplest ratio is 2:3 itself )

[@mousam8719]

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[@cyborggaming2021]

Hi

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Thanks allot sir and made ejee team going to complete this....

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Sir Aapke jaisa na to koi padha sakta hai aur na hi koi padhayega....👌🏻👍🏻👍🏻👍🏻
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[@humzashaikh4041]

Thank u Sir ur the best teacher of chemistry. ....😊
Answer c=52.1%
H=13.4%
O=34.7%👍👍👍

[@poojarajput4481]

H 13.04 hoga

[@anjalimishra4192]

13.04%

[@manavthevar2132]

Yes H is 13.04 but still good you tried and succeeded

[@dheerajsahu518]

Thanks sir ji & All Madee jee Chemistry team & Our All MadeejeeChemistry family 🙏 🙏 🙏 🙏 🙏

[@naziyamalik3871]

Hello Good evening sir. 😄😄🌹🌹🌷🌷🌺🌺🌺
Lecture completed 👍👍

[@sirvilive2935]

Completed......
Thankyou so much Sir ji

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[@prakharupadhyay4755]

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[@SWETAKUMARI-xr8ox]

C-52;17
H-13;04
O-34 present

[@akanshasingh2299]

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[@neetaiims139]

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[@b_44_ramaiyameeta84]

Good evening sir Thank-you for lecture👍👍👍C=52.17% H=13.04% O=34.78%

[@thanglenkhupmate2799]

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[@pareihanbasagapam6500]

How about rounding up to their simplest whole number in case of decimal.. Plz explain

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Yes plz make a video on this. Its creating a big problem for us 🙏

[@madhavharish2575]

Thank you so much Sir, You make our concepts really EJEE !!!!

[@akankshalakhera3774]

C=52.17% ,H=13.04,O=34.34%
Thank you so much sir 👍👍👍👍👍👍👍👍👍👍👍👍

[@devendrashetty2266]

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[@acristal243]

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thank you sir apki help se mera chemistry bhut strong ho gya h..

[@anshnamdeo5275]

Thanks for this, which make to understand easy the question with solution

[@anjananirgide4741]

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Your teaching skills are awesome 👍.
Your knowledge is also good

[@rajeshvaid3141]

c-52.17,H-13.04 and o-34.78

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[@AnkitaSingh-2009]

Thanks a lot sir it's very helpful video for me

[@mohammadkaifansari1382]

Sir agar divede krne me bad decimal mi at a hai to kya krna hoga....
Jaise apka toh round figure mi aya 1,4,1 agar mera decimal mi aya toh kya krna hoga. Reply me sir

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[@mannatchhabra9437]

Thank you sir for this video.

[@jealousy....]

Ans is c=52.17 h=13.04 o=34.78 and thanks sir

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A very good class than coaching.

[@romangod7716]

I am gonna share this vdo to all my friends they will also get cleared this concept🔥😄

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Good evening sir😄😄

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Sir ye second video h jo Mene dekhi h ap ne boot ache se samjhaya h 👌👍

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Sir from where U R
Such a Great 👍🏻 Explanation 😃
First time I understand It
Everything 😊

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[@shavnamsharma5650]

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[@riyazmalik6572]

% of carbon = 52.17%
% of hydrogen = 13.04%
% of oxygen = 34.78%

[@ilamdeenmenani8211]

My mole concept is completely clear because of you.Thanks sir😊😊☺️☺️

[@devyanshsharma2116]

Excusme sir , agar moles decimal me na aakar direct aaye jese 2 , 3 , 4...then inme bhi sbse chhote number ko sb m divide karke simplify karna padega ???

[@liyamariambiju8053]

Sir.. ur teaching is superb

[@ruthwik1933]

Sir if molar mass is not given means how should we calculate
Nice explanation sir
Thank you sir

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Ek no explanation❤❤
Katehii jehrrr😘😘

[@Its_beauty_of_nature]

10;53
percent of carbon=24/46x100=52.21percent
percent of hydrogen=6/46x100=12.12percent
percent of oxygen=16/46x100=35.67percent....

[@10mralex]

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Thanks for the solution 🙏👍👍

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Sir bhut ji jayada accha explanation thanks sir or vedios banaye

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In a day two video. Just sufficient. Still want more😍😍

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U explained well

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Thanks sir you are teaching very easily

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[@InDrayanI_Chavhan]

Completed Sir....👍🏻👍🏻👍🏻👍🏻
Ans is...C = 52.17%, H = 13.04%,
O = 34.78%
Thanku Sir...🙏🏻🙏🏻🙏🏻😊

[@darshikakushwaha7644]

Indrayani Chavhan Give me ans....moles concept kha h...NCERT me...

[@InDrayanI_Chavhan]

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Some basic concept of chemisry
In 11th NCERT..👍🏻👍🏻

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good

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Description box

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Osm video Maine bhut jagah dekha par kahi sahi explained nahi kiya but you are best👍👍

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Thank you sir😊

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U have cleared my doubts👌👌👌👌👌

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Thnk u sir .... very nice explaination

[@anayaskitcken]

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[@persever365]

Percent composition of Carbon= 52.1%
Percent composition of Oxygen= 13.3%
Percent composition of Hydrogen= 13.3%

[@HarmandeepKaur-]

Thank u so much Sir ji 😊😊😊😊

[@debasishpaikaray4195]

Thank you Sir.💗💓💕💖🤗✌️🏾✌️🏾❤️❤️🤡🤡💗💗💗🤡💓💓💓💓💓💓💕💕💕💕

[@Sumo877]

Good evening sir and thank-you so much for the video

[@SimranSingh-hl6sj]

Sir woh C2H8O2 wala direct percentage se bhi nikal sakte hai na toh itna lamba way se kyu kiya aapne??
For example. For carbon. 37.5 * 64 / 100 = 24 and carbon ka mass is 12 toh 2 atoms hue...similarly sabka aise nikal sakte hai na???

[@meer-e-karvaan.6070]

ans:) C=52.17
H=13.04
O=34.78

[@nareshmahlinareshmahli8446]

Sir you are real teacher.