Current Electricity full chapter in Oneshot 2024-25 🔥 || Chapter 3 Class 12 Physics
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Behind
Sir, I am getting printed notes of this chapter
Sir next chapter kab upload karoge Sir app Sach mae bhoot achha padhate ho thank you sir for your efforts 😊😊😊
Sir number dijiye
Sir next chapter
Your teaching method is awesome 👍
Definitions at a glance
1)The rate of flow of electric charge in a definite direction within a cross section is called as Electric Current.
2)If 1 coulomb of charge flows through any area of crosssection within 1 second, then the current is said to be of 1 Ampere. 39:43 ans 1.12 x10^-3 , 41:31 ans 10.88 x 10^-4
3) Current density is defined as the current flowing per unit area when held perpendicular to the flow of charge.
* Absolute zero i.e -273 degree celsius mein electrons ki energy zero hogi.
4) Drift Velocity- The avg. velocity of all the electrons in a conductor with which they gets attracted towards the positive end of conductor. < Consistency is the key i.e. Kachue ki chal>
5) The time between two successive collision of electrons is k/a Relaxation time. Inversely proportional to thermal velocity.
*** COMPLETED TILL 1:21:07 ***
😍
6) The drift velocity for electric field is called as mobility, it is independent of potential difference.
7) According to ohm's law the current flowing in a conductor is directly proportional to the potential difference across the two ends of the conductor, provided that the physical condition like temperature length etc of the conductor remains constant.
8) The obstruction in the path of current due to the collision between two electrons & ions is k/a Resistance.
9)The resistance of 1 unit volume of a conductor is k/a Specific Resistance/ Resistivity. ** The reciprocal of Resistance is Conductance.
10) 1:32:27 important 2nd case
11) The max potential differernce between the two terrminals of a cell in an open circuit- EMF
12) The power that is rated on the devices at a given voltage i.e.220 volt- Rated Power
13) 4:04:02 ans - 82.64 watt
Completed till 4:04:18
14) Series- Resistance ⬆️ then bulb glow ⬆️
Iska ulta in parallel - R ⬇️ then bulb glow ⬆️
4:18:40
Finally Done 😂🎉🎉🎉
Dhanyawad @krishvi389 idhar se screenshot leli😂
Nice 👍
Arey bhai baki ke notes add nahi Krna h kya???
Jaldi pura karlo 2nd slot to Mera khatam bhi hogaya yaar.🤣
@@nandanisingh1027 tumhe sare notes mil gyi kya ?
Nhi unit tests ke wajah se nahi kar paye, in do-teen dinon mein pura bana lenge
5:00 start
18:30 electric current
31:20 basics for numericals
34:40 questions
45:30 current density
48:28 question
55:30 drift velocity
1:02:30 relaxation time
1:04:30 relation between current intensity and drift velocity
1:11:00 drift velocity derivation
1:21:15 mobility
1:23:20 OHM'S LAW
1:43:00 relation between free electron density and resistivity
1:50:09 effect of temperature on resistence of conductor
1:52:08 effect of temperature on alloys
1:57:10 thermal coefficient of resistence
2:12:50 electromotive force
2:25:35 internal resistence of cell
2:30:00 relation b/w emf terminal voltage and internal resistence
2:50:03 equivalent emf
3:04:15 condition for max and min current
3:20:50 kirchhoffs rule
3:41:00 wheatstone bridge
3:55:20 elctrical energy and power
Same name bro😂
Ye sa😊
@@technologycreations5790 our names are rare 🤪
😅😅
Thank you so much ❤
😍😍😍😍
ans of 2nd question-1.12*10^-3A
and
ans of 3rd question-10.88*10^-4A
bro ek baar 2:08:34 wala question karo r2 -r1/r1 (t2-t1) wale formula se tab answer patanhi alag kyun aa rha hai
bro pls help
How you find the ans of question 2nd.
Same brother
Answer toh same Aya Bhai but ye batao ki radius kya hua???
🤔
As a senior my advice follow him blindly you will get very good Marks in you exam but remember pratice is very important
@mokshisharma2942 yes but Question pratice is required after his one shorts,only with one shorts you can't even pass a board exam
@@ShivamRekhi is this lecture sufficient for jee mains concept clarity? Along with jee question practice??
@@melina7844😂😂😂😂😂
Insufficient h
@@ShivamRekhi mujhe confusion h ki munil sir ki video acchi h physics k liye ya abhishek sahu sir ki
@@ShivamRekhi can u please tell me which question bank should I use Oswal or educart??
Vote for next Chapter ❤❤❤❤❤ 👉👉👉👉👉
Yes sir we want next chapter
Oh hakim
@@kingu98678 I think you're Abhay
@@mdhakimansari369 yeah
4:04:08=(82.6 w)
Electric current - 6:30
Numerical hints - 31:45
Current density - 45:50
Drift velocity - 55:32
All the best for 2024-25 batch 📌
4:07:08
~60W bulb will glow brighter.
~In a series connection, the current is the same for all bulbs, but the voltage is divided among them. Since power consumption is directly proportional to the square of current (P ∝ I^2), and current is the same for all, the bulb with the highest wattage rating will have the highest resistance.
Using Ohm's Law: Resistance (R) = Voltage (V) / Current (I)
The bulb with the highest resistance will have the highest voltage drop across it, resulting in less voltage available for the other bulbs.
In this case:
- 20 W bulb will have the lowest resistance
- 60 W bulb will have the highest resistance
Since the 60 W bulb has the highest resistance, it will have the highest voltage drop, and therefore, it will glow brightest.
So, in a series connection:
- 60 W bulb will glow brightest
- 40 W bulb will glow dimmer
- 20 W bulb will glow dimmest
Note that this is assuming the same voltage rating for all bulbs. If the voltage ratings differ, the analysis would need to be adjusted accordingly.
Yeah exactly
39:39 1.1×10-³A
41:02 10.88 ×10-⁴A
4:04:01 82.6w
Correction 4:04:01 82.6w
@@Superhero235 yaaa yaa ya
Umm
41:02 10.88 × 10-⁴ A can be also be written as 1.1 × 10-³ A (approx ) right??
Same same
Yrr koi btado 40:04 par radius kha gyi
2:08:31
The resistance of tungsten at 500°C will be approximately
342.48 ohms.
2:12:43
249 degree Celsius
yes i got the same answer
@@art_of_aashutosh that's correct answer
same i was in doubt how can i be this much wrong even ai is giving same
@@wizlittleboyff146 sochne ki baat yeh h ki how sir is this wrong ?
Bro I got the same ans 342.5ohm but google pe 258ohm bta rha h sbhi website pe 😢
39:41 1.12× 10-³A
41:11 10.88×10-⁴A
04:03:56- 82.64 w
atendence for board 2024/25👋🤚😇😇😇😇give the presence😇😇
One shot is worth it for boards
Next chapter 4 votes
👇🏻
vote for moving charges and magnetism ♥♥♥♥👉👉👉👉👉
Iss chapter ko maine bohot sare you tube channel se padha but sir ne jo deep concept bataya hai wo koi bhi one short per apko nahin milega and sir ke teaching style amazing hai pura basic se padhate hain sir plz aise hi lecture late rahiye hamre hobot kam ka hai 🙏❤
39:02- the current is 1.12*10^-3 ampere
41:27- 1.088*10^-3 ampere
HELLO SIR. TARUSHI THIS SIDE. You always fulfill all our requests, you truly care so much about your students. Even tho having a separate paid batch, you are still helping your youtube student with the same energy. I am beyond grateful for your guidance and support. TO THE BEST TEACHER OUR BESTEST ABHISHEK SIR, your hardwork and dedication towards us is really commendable. Words can't express how much we love you and appreciate you. THANKYOU FOR EVERYTHING SIR. We all have a positive influence in our life's, we started believing on ourselves because of you. Thanks sir. I will never forget you💖💖💖💖
Tarushi, Thank you so much for your love and support. Students like you are true earning of a teacher ❤️🙏
❤
@@Abhisheksahusir sir at 2:08:31 ans is 342.475 ohm
Zyada ho gaya behen
@@GhazalzehraNaqvi ???????
The way he explains every chapter is just amazing!!!
You made the chapter so easy to understand!
Thank you sir!!!👏🏻🙏🏻
Can I prepare for neet from here
@@divyamveer8341 concept yha s clear kr lo baaki pyq solve kro is chapter s agr ho rhe h iss se to ye sufficient h otherwise you can find others
Sir I want that you will make all videos on class 12 chapters your teaching is undefined and I have no words to show gratitude to you ❤️
Yes..sir... plz..
Yes I will
Poz sir new chapter de do
(a) Ans- 1.12×10^-³
(b) Ans- 10.88×10^-⁴
Thank you sir ❤
Ahsec board main exam dene wallah like koro❤
Bro tum kaha s ho m tinsukia s hoon
39:45 :- ans) 1.12 * 10"-3 A
41:25 :- ans) 1.088 * 10"-3 A
Mera bhi yahi aya 1.12×10-³
Answer:
Second question : 0.112×10^-2 A
Third question : 10.88×10^-4 A
You always make all the concepts so easy. Thanks a lot sir.
Legends after purchasing offline batch still come here 😅
kal pt1 h 3 chapter ka aaj raat 10:30 padhne baitha hu....mere liye dua karu buddies... 8 august ko result reveal...
your result?
Bhai kya ayaa result 😅
aur buddy?? result kya hua?
Results kya aya😅
Result????😢😂😂
Hii friends 😄😁 kon kon is baar 95+ Lana chata hai jaldi batao 🎉🎉🎉❤❤❤
39:01 ans 1.12 × 10‐³ ampere
41:28 answer 1.09 × 10‐³ ampere
Vote for 4th chapter👇👇👇👇👇👇
2Q - 1.1 x 10^-3 A
3Q - 1.08 x 10^-3 A
4:04:15 - Pcon. = 82.6W
1:36:11 Correction ,slope of IV graph is conductance.
Usme inverse property batai h na.... Slope of IV graph is inverse of resistance....same meaning h uska
Oo
Btw u teach nyc sir❤❤
Please tell atleast the answer to confirm that Answer is right or wrong...
5:00 Start✨
Thanks for this video sir
❤❤❤❤❤❤❤
Very best explanation 👌
Question no 1 = ans 1.12×10^-3
Question no 2 = ans 108.8×10^-5A
Qus1,-1.12×10^-3
Qus2-1.09×10^-3
Thank you so much sir for this amazing 🤩 lecture ❤
Questions 2nd 1.09×10^-3
Answer of 2nd question-1.12*10^-3A
Answer of 3rd question-10.88*10^-4A
Answer of 1st question is 1.12*10^3 and 2nd answer is 1.1*10^-3
Answer of first question is 1.12*10^-3 A OR 0.00112 A
Answer of second question is 10.88*10^-4 A OR 0.001088 A 👍
1:22:55 how drift velocity does not depend on voltage??????🤔🤔🤔🤔
The flow of current is nothing but drift velocity of electrons. Since current is directly proportional to voltage applied, drift velocity of electrons will also be directly proportional to the voltage applied...............
Sir I am following your channel since last year. Though I studied physics by many teachers. And this is my fist comment and proudly I can say this now you are the best ❤❤
Question 3: At (41:10) Ans. 10.88× 10^-4
Sir pls jaldi jaldi de dia karo classes,
mere half yearly JULY mai h and 80% syllabus is coming & i am completely relying on you for physics.
Also if possible aap NEET ke jo extra topics hote h wo karwa skte ho in different playlist?
Vaii itne jaldi exam ho rahe hai tere😢
Power consumption=82.64W 4:03:56
Sir will u provide all chapters videos for us because in 11th class i used to study from different channels but they haven't uploaded all chapter's videos which raised too many issues but now i found your channel and watched your lectures which helped a lot ..... Thank you sir ✨
Yes I will
Thank you sir ✨
Ans of 2nd question=1.12×10^3A
Ans if 3rd question=10.88×10^-4A
Thanks sir i have studed 8 chapter from u last year and i got 80 marks in physics because papper level is📈but i am very happy thanks
Bss oneshot se pada ya kuch aur bhi
@@Himmu_edits bhai qns practice bhi bht karna hota hai tabhi itna ayega
One shot is worth it?
Is this lec enough for cbse class 12 pcm boards
Plz reply
Do pyq
Yes, do derivation practice and numericals
Sir maine abhi tak jitne bhi chapter aapse smjhe unsbhi ke ques jab maine sample paper mei solve krne ki koshish ki to i can't believe mujhse utne sab ho gye
Really don't tell lie
@@Nanami-gm5sj okkkk
41:28 - ans of 3rd ques - 10.88 × 10^(-4) A
Sir aap bhot hi acha padhate hai keep it up aapke class me agle chapter ka besabri se intjaar hai
And thnx for providing best content 💖
Alarm at 2:29:52 ruin my whole concentration
Vote for 4th chapter😂😂😂😂😂😂
😂🎉😢👇👇👇
First question answer 1.12 x 10^-3 Ampere
2:10:33
Sir why don't we can use the formula (alpha=R2-R1/R1*(T2-T1) directly to solve this question ?
Because the temperature is not 0°C . So the value of the resistance at this given temperature is not the base value so we cannot solve it by the formula alpha = R2-R1/R1*(T2-T1)
@@pranakshibarman1617 ok thanks 😊
2.11c answer aayega bhai
@@pranakshibarman1617 no we can still use that formula , alpha = change in resistance / original resistance x ΔT
it is not about temperature at 0 degree C
39:20
Ans:- 1.121×10-³ A
41:17
Ans:- 10.88 × 10-⁴ A
You are very nice teacher for physics.❤
Thank sir for this video 👍
41:30 (10.88×10^-4)
4:04:01 P = 82.644 W
sir please upload ch-4 moving charges for 2024-25 as well
thank you
Sir 2:12:05 par numerator me 235 ho kyuki 1+1/234= (234+1)/234= 235
3:34:21 sir +E1 ayega
Qyunki current ki direction -ve to +ve hai❤❤
39:43 ans 1.12*10^-3 and 41:31 ans 10.88*10^-4
Thank you sir aap ne to physics wallah ko bhi phiche chod diya you are good 👍😊
Yes bro
Chod Diya ya chor diya 😂
1st ans:- 1.12 x 10-³ Ampere
2nd ans:- 10.88 x 10-⁴ Ampere
Is this fully sufficient for cbse board because i m a jee aspirant?😊
Yes bro
6:07 lecture starts
Iam fail student 😢😢😢😢😢
Means
Me 2024 me fail hogaya 12th board
😂😂😂😂😂
😂😂😂😂
Kskssjsjj😂😅😂😂😅😅😂😅😂
39:22 1.1x10^-3
41:09 10.88x10^-4
Thank you sir for this amazing lecture 🙏
Sir time stamp laga dijiye 🥺🙏
39:09 1.1 x 10^-3 A
41:31 10.88 x 10^-4 A
sir please next chapter......
Ans of 2 question is 1.12 *10^-3A
Ans of 3 question is 10.88*10^-4A
Kya ye BIHAR BOARD ke liye sufficient hai ya nahi
Mera bhi yhi question h
@@AnamikaKumari-sj5opMera bhi
Mera bhi
More than sufficient hai ye
Ha but derivations ko achhe se revise kar lena......😊
45:14 that should be square instead of rectangle since all the sides are 5 cm
Sir plss question practice jada karaiye
Thx sir 🦋for your best explanation 🤴
One shot is worth it for boards?
@@Femalewarrior-k7b ha
@@bhumika-vn8ry kya aapne de diya 12th boards
@@Femalewarrior-k7b is saal dungi
@@bhumika-vn8ry ooh best of luck than
39:41 1.12×10^_3 A
41:30. 10.88×10^_4
Sir please 7baje dalo kal Mera exam hai class me please 🙏🥺❤
Aaj 7 bje hi to aayegi
1:22:55 how drift velocity does not depend on voltage??????🤔🤔🤔🤔
The flow of current is nothing but drift velocity of electrons. Since current is directly proportional to voltage applied, drift velocity of electrons will also be directly proportional to the voltage applied
I think he wanted to say mobility but he had a slip of tongue
@@seemasharma-fl7ue Yes you are right
Thank you sir 👍😊
Paper se 1 din pahle padne wale
Student ❌ legend ✅
39:39 = 1.121×10^-3 Ampere
41:16 = 10.88× 10^-4
41:33 1.088 * 10^-3 A
Anyone score 100 marks in physics
Answer of 2nd Ques ) 0.11×10^-2
39:38. 1.12 × 10-³ A
41:21.10.88× 10-⁴. A
1.12×10^-3
At 39:40
Answer:- 1.12× 10^-3 Ampere( 39:09)
Legendary line also by sir 😂😂😂
39:18 - 1.1×10-³ A
41:18- 10.88 ×10-⁴ A
Ques:1) I= 1.12×10*-3 A
2:12:51 electro motive force (EMF)
4:04:01 Pconsumed = 82.64 W
Is it is sufficient for neet too?
3️⃣9️⃣.40. Ans 1.12mA
16:38 i can't control my laugh😂😅
39:39 ans is 1.1* 10^-3
40:25 ans is 10.88*10^-4
Is this video is Enough for cbse board exam 2025🙏
Can bihar board students can watch this and is it sufficient for Bihar board exam plz reply