I only found your videos recently Jesse and I must say the quality is fantastic. Your ability to break down complex concepts, explain them simply and clearly is brilliant. Coming from a NSB, you're really helping my understanding of how to tackle a majority of questions I previously felt quite intimidated by. Appreciate all the time and effort you're putting into these for the assistance of others. Keep up the great work. Wishing you all the best for the next round of offers.
Hi Jesse, Thank you for your videos😊 just want to ask you from where we can practice section 1 questions? I am totally new to GAMSAT. Would be really appreciated. Thank you
Hey Jesse you are superb. I am from science background but still i was not able to solve these questions so quickly. But after watching your videos it seems like a game to me. Thanks
Another brilliant video, thanks Jesse. Its actually fun to watch! Quick question, so for question 44, I understand why option B is correct but I don't get why D is wrong?
Hey there! Yep so option D does look like a pretty good option initially, but you'll notice that there also needs to be a carbon atom in the middle of the two ring structures that the alcohol group attaches from. Option D doesn't have an extra Carbon to offer this as the MgBr will be removed and the C=O end doesn't have a carbon to use either. This then rules it out. Hopefully that clears things up! :)
Thanks Kristy! Yep I think in the case of most organic chemistry pathway questions you can apply this kind of reasoning. It is also really important to be able to work between IUPAC names and their structures and the 4-bond principle for carbon to help with this at times but there is no need to memorise random chemical pathways.
also pls how do you know where the reactants "glue" together? ( you mentioned where MgBr gets removed it gets glued there but not sure how to reason through that)
For question 45, shouldn’t the answer be C. Answer A has 6 Hydrogens in total whereas in the reaction there are 5. Also because it’s a ketone it should be a secondary alcohol.
Very close but the stem provides us with the pattern in the examples given including for ketones and cyclic ketones which it states produces tertiary alcohols. The reason why ketones produce tertiary alcohols in this instance is because we are also attaching another R group to that carbon as well. If it were just a plain hydration or reduction of a ketone group then this would produce a secondary alcohol but this wouldn't be required knowledge for a GAMSAT question. The stem examples show that the C=O becomes C-OH in each case so we can confirm that the alcohol group must be directly attached to the carbon ring and the other alkyl group attached to the same carbon. Realistically an ACER question would more than likely show the hydration step that accounts for the extra H attached in the product but this is where GASMAT questions can trick people if using outside knowledge or conventions. The pathway doesn't defy the theory of this reaction pathway but it also presents it in a way that takes away some of the usual methods of understanding what is happening and puts greater emphasis on picking up on patterns in the information and example pathways given.
I only found your videos recently Jesse and I must say the quality is fantastic. Your ability to break down complex concepts, explain them simply and clearly is brilliant. Coming from a NSB, you're really helping my understanding of how to tackle a majority of questions I previously felt quite intimidated by. Appreciate all the time and effort you're putting into these for the assistance of others. Keep up the great work. Wishing you all the best for the next round of offers.
This is so great to hear! Really happy to see that it's made the preparation a little easier
Best of luck to you!
So well explained, thanks man. Took this technique over to the Des O Neil q's and it worked!!
Fantastic! It feels like you're unlocking a new level to the exam when that happens, huh? haha
So helpful thank you Jesse! Organic chem makes me feel like I’m crazy so this is wonderful ✨👏🏻
Time to crack that 70 in s3! 💪
Absolutely amazing...you made my day Jesse. Feel much more confident in org chem now. Wish you could make similar video in general chem. Cheers
This is so great to hear! I'll see what I can do :)
Jess Your are God Sent! Thanks mate
You're very welcome Shaymaa! :)
Hi Jesse, Thank you for your videos😊 just want to ask you from where we can practice section 1 questions? I am totally new to GAMSAT. Would be really appreciated. Thank you
Amazing, thank you!
Hey Jesse you are superb. I am from science background but still i was not able to solve these questions so quickly. But after watching your videos it seems like a game to me. Thanks
lovely to hear!
Super helpful, thank you so much!
Glad it was helpful!
Another brilliant video, thanks Jesse. Its actually fun to watch! Quick question, so for question 44, I understand why option B is correct but I don't get why D is wrong?
Hey there! Yep so option D does look like a pretty good option initially, but you'll notice that there also needs to be a carbon atom in the middle of the two ring structures that the alcohol group attaches from. Option D doesn't have an extra Carbon to offer this as the MgBr will be removed and the C=O end doesn't have a carbon to use either. This then rules it out. Hopefully that clears things up! :)
@@jesseosbourne Thanks, I'll have another look through this evening :)
This was so well explained and the best part was you used no chemistry knowledge! Would you say you can approach every chem question like this?
Thanks Kristy! Yep I think in the case of most organic chemistry pathway questions you can apply this kind of reasoning. It is also really important to be able to work between IUPAC names and their structures and the 4-bond principle for carbon to help with this at times but there is no need to memorise random chemical pathways.
Thanks for your videos, id wish i got this kind of teaching in my uni degree.
No worries, man. Glad to see this one was helpful for you :)
Hi Jesse, (time stamp 13.19) - with C, why does the "CHO" on the end not match?
also pls how do you know where the reactants "glue" together? ( you mentioned where MgBr gets removed it gets glued there but not sure how to reason through that)
For question 45, shouldn’t the answer be C. Answer A has 6 Hydrogens in total whereas in the reaction there are 5. Also because it’s a ketone it should be a secondary alcohol.
Very close but the stem provides us with the pattern in the examples given including for ketones and cyclic ketones which it states produces tertiary alcohols. The reason why ketones produce tertiary alcohols in this instance is because we are also attaching another R group to that carbon as well. If it were just a plain hydration or reduction of a ketone group then this would produce a secondary alcohol but this wouldn't be required knowledge for a GAMSAT question.
The stem examples show that the C=O becomes C-OH in each case so we can confirm that the alcohol group must be directly attached to the carbon ring and the other alkyl group attached to the same carbon.
Realistically an ACER question would more than likely show the hydration step that accounts for the extra H attached in the product but this is where GASMAT questions can trick people if using outside knowledge or conventions. The pathway doesn't defy the theory of this reaction pathway but it also presents it in a way that takes away some of the usual methods of understanding what is happening and puts greater emphasis on picking up on patterns in the information and example pathways given.