How would you factor in a coefficient of friction of the bearing of the pulley? Would it be opposing alpha? Would you need the area of the bearing's surface?
sir you r just awesome..my basic has been made up by ur lectures..sir I have one question that is it possible to establish any law for equivalency of different types of liquids like resistance and capacitor equivalency?
can you help me with this professor? Two blocks with masses M1= 5 kg and M2= 15 kg are connected by a rope as shown. the horizontal surface has no friction and the pulley is weightless. If the block starts from rest , What is the speed of M2 if it has fallen 6 meters.
@@MichelvanBiezen Thank you so much professor how about this professor? A common swing 7 m high is designed for a static load of 1600 N which is the max tension in the rope at the lowest point. Two girls each weighs 450 N are swinging on it.How many degrees on each side of the vertical can it swing when the velocity is 2.2 m/s?
If the pulley has mass, the the tension on one side will be different than the tension on the others side, because it takes some force (torque) to turn the pulley.
What can be so satisfying for a physict than to solve one hack of an enormous problem and obtain a correct value because he was much scrupulous for the negative signs? Haha
@@MichelvanBiezen Wow thank you for responding. It wasn't because I thought you made a mistake, just trying to understand. So because you included the force of friction in the equation for f=ma, it is not necessary to include it in the torque equation for the pulley itself? I might be missing something though, but again thank you.
these were some of the more difficult ones for me. finally got it. thanks.
amazingg, i saw my professor do this so many times but he never explained it this well, first time actually understanding it thanks to you
Glad it helped!
How would you factor in a coefficient of friction of the bearing of the pulley? Would it be opposing alpha? Would you need the area of the bearing's surface?
In that case, it may be easier to use conservation of energy to solve the problem.
sir you r just awesome..my basic has been made up by ur lectures..sir I have one question that is it possible to establish any law for equivalency of different types of liquids like resistance and capacitor equivalency?
Even after 8 year it's best thanks ❤❤🎉🎉
Thank you. Glad you liked it.
can you help me with this professor?
Two blocks with masses M1= 5 kg and M2= 15 kg are connected by a rope as shown. the horizontal surface has no friction and the pulley is weightless. If the block starts from rest , What is the speed of M2 if it has fallen 6 meters.
The acceleration a = g (M2) / (M1 + M2) (assuming that the big block is hanging) Then find speed: v = sqrt ( 2 a h)
@@MichelvanBiezen Thank you so much professor how about this professor?
A common swing 7 m high is designed for a static load of 1600 N which is the max tension in the rope at the lowest point. Two girls each weighs 450 N are swinging on it.How many degrees on each side of the vertical can it swing when the velocity is 2.2 m/s?
At which point is the velocity = 2.2 m/sec?
Assuming the velocity 2.2 m/s is at the bottom, I found 15.264 degrees. Is that correct?
thank you a lot sir, this saved my weekly hand-in ;)
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Why there are two tensions in the rope?
If the pulley has mass, the the tension on one side will be different than the tension on the others side, because it takes some force (torque) to turn the pulley.
What can be so satisfying for a physict than to solve one hack of an enormous problem and obtain a correct value because he was much scrupulous for the negative signs? Haha
Excellent Sir . Regards
Doesn’t the force of friction contribute to the Torque of the pulley?
The friction force was included in the equation.
@@MichelvanBiezen Wow thank you for responding. It wasn't because I thought you made a mistake, just trying to understand.
So because you included the force of friction in the equation for f=ma, it is not necessary to include it in the torque equation for the pulley itself?
I might be missing something though, but again thank you.
Note that the torque is caused by the tension in the string and T1 = m1*a + m1*g*u That is why the friction was included.
@@MichelvanBiezen Oh yeah of course, I get it now.
Thank you for clearing it up for me.
Great explanation!
Glad it was helpful!
thanks so much, hugs from Brazil !
You're amazing
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I wish he was my teacher
Great video sir. Thank you
Thank you. You are welcome.