Lecture 5, Properties of Linear, Time-invariant Systems | MIT RES.6.007 Signals and Systems

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  • Опубликовано: 25 дек 2024
  • Lecture 5, Properties of Linear, Time-invariant Systems
    Instructor: Alan V. Oppenheim
    View the complete course: ocw.mit.edu/RES...
    License: Creative Commons BY-NC-SA
    More information at ocw.mit.edu/terms
    More courses at ocw.mit.edu

Комментарии • 55

  • @AshwinAashu
    @AshwinAashu 9 лет назад +65

    Alan is perhaps the best signals engineer ever. The way he teaches compels me to know more, understand and reason - with myself and others. I love the MIT courseware , thank you for this wonderful series.

    • @hoanganhnguyen795
      @hoanganhnguyen795 7 лет назад

      im vietnammese and i fell so hard to understand =))

  • @MrQwertymnb
    @MrQwertymnb 11 лет назад +6

    Prof. Oppenheim, RESPECT. Your teaching is an inspiration.

  • @deepakmecheri4668
    @deepakmecheri4668 7 лет назад +35

    I was so used to hearing the lectures at 2x speed now, when I play it in normal, it literally feels like the professor is talking in slow-mo

  • @lightspeed79
    @lightspeed79 12 лет назад +9

    I wish I had profesors like these from MIT when I was in college. Then again I wasn't at MIT.

  • @version191
    @version191 12 лет назад +29

    opening music is dope

    • @matthewjarvis7863
      @matthewjarvis7863 12 дней назад

      I think there's some Tron influence (1982 film)

  • @tiborszekeres
    @tiborszekeres 12 лет назад +10

    Time travel still possible!!! Thanks Utube!

  • @yougoog1
    @yougoog1 3 года назад +3

    It is easy to understand the property of linear system that if you put nothing in then you get nothing out. But I have trouble to understand why this property has anything to do with the causality property that the system cannot anticipate its input. Why and how are these two properties related? Another confusing part of causality of linear system is why causality means initial rest of initial conditions. Can a causal linear system have a non zero initial condition? Meaning for t < t0, its input is not zero, but can such system still be linear and causal? In another word, if you put something in, then you linearly get something out.

    • @sossupummi
      @sossupummi 2 месяца назад

      A linear system cannot produce an output without a corresponding input. Causality requires that the system cannot anticipate its future inputs. Zero input response (initial rest) is a consequence of causality and implies that the system's output is zero before the input is applied. A causal linear system can have non-zero initial conditions, but these conditions must not violate causality.

  • @MrQwertymnb
    @MrQwertymnb 11 лет назад +1

    Haha!
    In any case, I find that watching the video again helps a great deal. Good luck!

  • @osamaelzubair1203
    @osamaelzubair1203 Год назад

    At 39:00, when he was speaking about the invertibility of the accumulator, he first explained that an impulse is the difference between 2 unit steps and then wrote an expression for the inverse impulse response, why did he write delta(n)-delta(n-1)=h[n]^inverse instead of writing u[n]-u[n-1]=h[n]^inverse ?

    • @ayushkumar1539
      @ayushkumar1539 Год назад +1

      There is a reason for that,
      for accumulator, we need all the past values to determine the sum, but when it comes to difference we need the difference of only 2 consecutive values so we can simple multiply the coming input for the h(inverse) with impulses to get the required values and simple differentiate...
      for more insight integrator has limits from minus infinity to infinity but differentiator just needs it neighboring values....
      Hope you find it helpful : )

  • @aSeaofTroubles
    @aSeaofTroubles 8 лет назад +1

    In terms of Bounded Input, Bounded Output stability, I read the Wikipedia proof for discrete time systems and it makes perfect sense:
    |y| = |h*x|

  • @gadipuditushara7737
    @gadipuditushara7737 7 лет назад +1

    These videos are so helpful for me.Thank you sir.

  • @arnabthakuria2243
    @arnabthakuria2243 8 лет назад +4

    this man is amazing

  • @canned_heat1444
    @canned_heat1444 4 года назад +3

    at 22:11 it's a * not a + !!!

    • @OmarChida
      @OmarChida 3 года назад

      He said h1 convolved with h2. The * was written badly but its a *

  • @mohamedessam1397
    @mohamedessam1397 2 года назад

    Old but Gold

  • @maneymac
    @maneymac 12 лет назад +8

    little bit confusing......... :-(

  • @mnada72
    @mnada72 3 года назад

    Is the system in 19:00 has memory or memoryless?

    • @yougoog1
      @yougoog1 2 года назад

      No. It is not memoryless. It has memory.

  • @SubrahmanyamGorthi
    @SubrahmanyamGorthi 7 лет назад +3

    As usual. great Lecture by Prof. Oppenheim. I have a question, and I hope someone here will kindly answer that.
    Can there be a system which linear but non-causal?
    I could not think of any example where a linear system is non-causal. Please shed some light.

    • @SubrahmanyamGorthi
      @SubrahmanyamGorthi 7 лет назад +16

      Answering myself after some brainstorming ;-)
      "Moving Average Filter" is an example of linear non-causal system!

    • @Waleedwsd
      @Waleedwsd 5 лет назад +1

      A Classic example. (y)

    • @hoomansadlou5655
      @hoomansadlou5655 3 года назад +1

      simply y(t)=x(t+1) is linear and non-causal.

    • @barbossablink2969
      @barbossablink2969 4 месяца назад

      really wondering where are you rn :)

  • @jitendrasinghbhadoriya153
    @jitendrasinghbhadoriya153 7 лет назад +5

    I like the arrangement of white board ...sometime it never ends

  • @Chris-ob6es
    @Chris-ob6es 4 месяца назад

    Al is the real Howard Stark

  • @arv_sajeev
    @arv_sajeev 4 года назад

    Just to confirm, in the memory less case are we assuming that the signal is causal? Or is is being causal a property of memory less?

    • @crashraynor
      @crashraynor 4 года назад

      Memoryless means that the system does not depend on previous input to determine current output. Causal means that the system depends on only current and/or past input, specifically NOT future input. Example:
      y[n]= x[n-1] is causal and not memoryless
      y[n]= x[n+1] is not causal and is memoryless
      y[n]= 2x[n] is causal and memoryless
      x[n+1] is "in the future", n is the present, thus it can't be causal.

    • @pedromatias5927
      @pedromatias5927 4 года назад

      @@crashraynor "A system is said to be memory less if its output for each value of the independent variable
      at a given time is dependent only on the input at that same time." Taken straight from the course textbook. Thus, y[n]=x[n+1] is not memory less. I believe the instructor speaks about such cases in the lecture about system properties.

    • @arv_sajeev
      @arv_sajeev 4 года назад

      @@pedromatias5927 this is exactly my doubt, it seems like the examples shown by the professor hint to what you are saying. I'll check the textbook for your definition, thank you for your help.

    • @yougoog1
      @yougoog1 3 года назад

      For a LTI system, it is true that a memory less system is also causal. For a general system, the answer may not be true.

  • @khaledjofanee7294
    @khaledjofanee7294 8 лет назад +1

    please guys, i want the reference of this course

    • @mitocw
      @mitocw  8 лет назад +4

      The videotaped lectures are designed to be closely integrated with the text: Oppenheim, Alan V., and A. S. Willsky. Signals and Systems. Prentice Hall, 1982. ISBN: 9780138097318. (www.amazon.com/exec/obidos/ASIN/0138097313/ref=nosim/mitopencourse-20)

  • @CompilerHack
    @CompilerHack 11 лет назад +1

    didn't you watch the previous lectures' videos? :P

  • @byambajargallhagwaa2713
    @byambajargallhagwaa2713 9 лет назад +2

    Thank you

  • @Mojomatrix
    @Mojomatrix 12 лет назад +1

    Free Ivy League lectures ? Shit man, I'm all up in this !

  • @TheAdlcn
    @TheAdlcn 10 лет назад +8

    different shirt , same dude :)

  • @truthbheard9869
    @truthbheard9869 11 лет назад +1

    im reading oppenheim's book on signals and systems.

  • @ninjakid-hi9uw
    @ninjakid-hi9uw Месяц назад +3

    Anybody in 2024🤩

  • @ziqianzhang6192
    @ziqianzhang6192 11 лет назад

    ummmn. i dont get it yet..

  • @pedroernias
    @pedroernias 5 лет назад +1

    too slow... I needed to play this at 2x speed; other than that, nice lecture.

  • @storgerbenevolent5678
    @storgerbenevolent5678 4 года назад

    the later 3/4th of this lecture is very confusing

    • @yougoog1
      @yougoog1 3 года назад

      Because of the difficulties the impulse function has when it is defined as a value at each time like a normal function, it is defined as an operator function along with other operational symbol functions u_1(t), u_2(t), ....These symbol functions are no longer normal functions, i.e. they do not have values defined against time, but rather operators. You no longer ask them what they are, but what they do. They are just like the addition operator ‘+’. You do not know what value ‘+’ has, but you know what exactly ‘+’ does, i.e. 1+1=2.

    • @anmolkumar-lp3ox
      @anmolkumar-lp3ox 3 года назад

      LTI Systems: ruclips.net/p/PLU1h6AEhPu52EzX-KO5g5KNsbzId28Vz3

  • @igotbev1394
    @igotbev1394 4 года назад

    This is it

  • @ProxyDev
    @ProxyDev 4 года назад +1

    We have some Nintendo music :)

  • @anmolkumar-lp3ox
    @anmolkumar-lp3ox 3 года назад

    LTI Systems: ruclips.net/p/PLU1h6AEhPu52EzX-KO5g5KNsbzId28Vz3