5a)July-2019-Qp-Initial condition

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  • Опубликовано: 1 окт 2024
  • Numerical on Initial conditions.

Комментарии • 6

  • @laxmiswonderland
    @laxmiswonderland 5 месяцев назад +2

    I didn't understand anything sir
    What are u trying to explain

    • @VBDclasses
      @VBDclasses  Месяц назад

      @@laxmiswonderland ok try to understand

  • @user56940
    @user56940 Месяц назад

    for finding i) v1 and v2 at t=0+
    u took v2=i2 R2 directly and got v2 at t=0+ as 0
    why did u not directly take v1 as L di2/dt ? why did u take it from that equation 2 of kvl?

  • @user56940
    @user56940 Месяц назад

    sir i think i1(inf) and i2(inf) are swapped.. cuz how can i2(inf) be non zero? when theres open ckt