Canada | Math Olympiad | A Very Nice Algebra Problem

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  • Опубликовано: 8 сен 2024

Комментарии • 11

  • @Haijwsyz51846
    @Haijwsyz51846 Месяц назад +4

    It is unnecessarily made complicated. This question doesn’t need to write down. You got 3^x=3 by taking 3*6=18 and 3*3=9.

  • @user-sj2ro3bf7b
    @user-sj2ro3bf7b Месяц назад

    18^x-9^x=3^x(6^x-3^x); (6^x-3^x) cancels with itself, because exactly the same expression is in the denominator; or 6^x-3^x=t
    18^x-9^x/t
    18^x-9^x=3^x(6^x-3^x)
    3^x * t / t = 3^x =3; x=1

  • @rustysm8080
    @rustysm8080 Месяц назад +1

    X = 1.
    Doesn't seem hard. Did it in my head. 😊

  • @prollysine
    @prollysine Месяц назад +1

    9^x(2^x-1)=3*3^x(2^x-1) , 9^x=3*3^x , 3^2x=3*3^x , -> 3^x=3 , 3=3^1 , x=1 , test , x=1 , (18-9)/(6-3)=9/3 , 9/3=3 , same , OK ,

  • @ZeroGravityDog
    @ZeroGravityDog Месяц назад

    Isn't this a one-liner? 18^x - 9^x = (3^x) (6^x - 3^x); cancel (6^x - 3^x) top and bottom, leaving 3^x = 3, so => x=1

  • @mrinaldas9614
    @mrinaldas9614 Месяц назад

    3^x (6^x-3^x)/(6^x-3^x)=3
    3^x=3
    X=1; as simple as this

  • @user-lh7yp7vz7j
    @user-lh7yp7vz7j Месяц назад +1

    Х=1

  • @VoteScientist
    @VoteScientist Месяц назад +1

    (18^x - 9^x) / (6^x - 3^x) = 3
    -------------------------------------------------------------------------------------------------------
    9^x(2^x - 1) / 3^x(2^x-1)) factor out 9^x on top and 3^x on bot
    9^x / 3^x cancel out (2^x-1)/(2^x-1)) = 1
    (9/3)^x property: a^x/b^x -> (a/b)^x
    3^x = 3 9/3 = 3
    x = 1 property: a^b = a -> a=1
    done in 1 minute with no music

  • @DrBenway97
    @DrBenway97 Месяц назад +1

    I'm sorry but there is NO WAY that this is a math Olympiad question !!!
    I solved it using basic algebra rules in about 23 seconds... CLICKBAIT NONSENSE>>>!

    • @mathshunter
      @mathshunter  Месяц назад

      Math Olympiad exam is conducted for every grade of students. So, this is actually a math olympiad problem. This channel is dedicated to math olympiads for grade 10 or lower. On my second channel math booster, i cover math olympiad problems for grade 12 students.

  • @alexeyevgenevich9821
    @alexeyevgenevich9821 Месяц назад

    Х = 1