Really u explain in a very easy way sir Thanku so much sir ♥️ Pura diode ka concept ik hi ques m clear ho gya sir Once again thank you so much sir ♥️😊😊
Splendid explanation! I have a doubt, how do we know when to split the current? Like, why doesn't the current split at the point on the left where the two wires with the 10 ohm resistors are joined together?
Even if we split the current on the left junction still you would see a wrong orientation of D2 since at left side of battery in this diagram potential would be low.
Yes, I had the same doubt, but sometimes, it's better to look at the potential difference across the diodes. If you look at the left part of the diode D2, we can assume the potential to be 0. and on the right part, the potential will definitely be higher. Hence, it would be reverse biased.
Fabulous explanation this is what an student expect 🙏 🙏 🙏 ❤😊
Noob tu yaha chapter padhne aua hai a solution dekhne
Behad must explanation hai
fab explantion tq very much sir
Increadible 🎉
Great 🎉 Explanation
Thankss a lott sirrr..u explainedd VERY VERY VERYY NICELY
king explanation
Really u explain in a very easy way sir
Thanku so much sir ♥️
Pura diode ka concept ik hi ques m clear ho gya sir
Once again thank you so much sir ♥️😊😊
😊
Splendid explanation! I have a doubt, how do we know when to split the current? Like, why doesn't the current split at the point on the left where the two wires with the 10 ohm resistors are joined together?
Even if we split the current on the left junction still you would see a wrong orientation of D2 since at left side of battery in this diagram potential would be low.
Yes, I had the same doubt, but sometimes, it's better to look at the potential difference across the diodes. If you look at the left part of the diode D2, we can assume the potential to be 0. and on the right part, the potential will definitely be higher. Hence, it would be reverse biased.
Why we will not solve parallel resistor first