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the method in this video is a trial and error one.my methodfrom (n - 2)! = n + 1 => n - 2 divides n + 1 = 1 + 3/(n - 2)so n - 2 should be 1 or 3. only 3 (n = 5) meets the given condition.
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the method in this video is a trial and error one.
my method
from (n - 2)! = n + 1 => n - 2 divides n + 1 = 1 + 3/(n - 2)
so n - 2 should be 1 or 3. only 3 (n = 5) meets the given condition.