Thanks for your efforts. One more option is there. We can short N and n. This way voltage will not be greater than applied voltage. Here R-r + r- (n/N) = R- (n/N), Y-y + y- (n/N) = Y- (n-N) and B-b + b- (n/N) = B- (n/N) (n/N ) is the same point as n and N are shorted.
I already knew the method of testing procedure. But your explanation is very practical and simple. Thank you.
You are most welcome
Very nice explain and very informative video's keep it up
thank you
well explained ezhumalai...
thank you vasanth
Very informative sir
Thanks for sharing
Most welcome
Thanks for your efforts. One more option is there. We can short N and n. This way voltage will not be greater than applied voltage. Here
R-r + r- (n/N) = R- (n/N),
Y-y + y- (n/N) = Y- (n-N) and
B-b + b- (n/N) = B- (n/N)
(n/N ) is the same point as n and N are shorted.
thank you for sharing
Very good explanation sir, thank you
You are welcome
Good explanation 👌👏
Thank you
thanks sir ji
welcome
sir its compulsary to use three phase power? is there any method we can use to do it using single phase power?
i don't know but i will try to check for you
@@baranitech it will be great sir, i am really stuck on this problem. thank you
Thank you
awesome
thank you
Very good 😭🙏🙏
your welcome
Can you explain for Dzn10 vector group testing
yes i will make
YNyn0D5 please video
i will try to make
Thanks
Welcome