Slip in single crystals due to resolved shear stress (Schmid's Law) example problem
HTML-код
- Опубликовано: 20 окт 2024
- Tutorial of worked example solution to slip in single crystals. Resolved shear stress vs critical resolved shear stress. This is known as Schmid's Law.
Got an idea for another example problem tutorial you'd like to see worked out? Leave a comment below and I'll get to it right away!
Also, subscribe to see new tutorials I upload and to help me grow my channel.
Straight to the point... such a rarity in RUclips now. 10/10.
Thank you for sharing your wisdom sir. Much appreciated!
my pleasure!
Thank you sir !!!you are the only reason because of which I was able to solve one of my problem in assignment .keep doing this works
Thank you so much! Right to the point explanations, simple and easy to understand! Wish you teaches me instead of my prof...
I was trying for a couple hours to figure out how to get the direction for the normal to the plane and when this guy reminded me of the special rule for cubic systems I lost it
Lol. Glad you've got it now :)
You are a god amongst men
xD
Thanks a lot for sharing this with us, sir!
Helped a lot!!!
Glad to help!
Thanks a lot! This solution really helped me!
Thank you so much! Very clear and straight to the point :)
YES!! Again I understand. Thank you
my professor absolutly blows, went to his office house many many times and all he could say is figure it out, this isnt high school im not going to spoon feed you. Like Prof. i know this isnt highschool i have been out of high school for 4 years now. Im paying this institution 85K a year and you are going to tell me to figure it out! i can figure it out by myself at home for free, or watching youtube videos. Anyways thats my rant becuase of how furious i am. THANK YOU FOR THE HELP SPARKS !!
Dude that sucks. So sorry. Glad RUclips university came to rescue 😎
great video!
Thank you it is great ....
Thanks man appreciate you help 🙌
Great! Thanks for the video.
Can resolved shear stress negative value?
Very useful Taylor, thanks
Glad to help!
Thank you so much
all 24 possible slip systems of {110} is wanted from me, but i need to know the combinations, what are they?
Thank you so much ☺️ 👌🏻
Bros boutta take flight
Lol. Pour one out for that old lappy putting in work.
In a problem where the slip plane direction and the load direction are both known, how can you figure out the slip direction?
when multiplying the bar value do you consider the negative sign?
Yes. Bar means negative. You use this in the cross product multiplication.
Ty,good sir
thanks
Thank you so much omg
glad it helped! Let me know if other problems would be helpful.
IT'S GONNA BLOW!!!!!!
😂
thanks man
When you say the resolved shear stress would just be the applied stress if those angles were zero, that seems strange cause I thought the normal stress would be 100% but the shear stress when you're just pulling on something would be 0 (and at a max on 45 degree planes). Thanks for the example, not sure im explaining what I mean. I get the math (cos(0) = 1 for both)
I found a derivation that makes the math make sense to me - no wonder I was having issues, here it is for others - www.uobabylon.edu.iq/eprints/publication_12_24106_1037.pdf
I'm not totally sure that I follow you. When the angles are 90 degrees then the applied stress is totally perpendicular to the slip plane and direction. Therefore the shear stress component is zero. If they line up exactly (0 degrees) then have pure shear.
However, you can't have both direction and normal 0 degrees to the applied because direction and normal themselves are 90 degrees from one another. The best case scenario is when we have applied 45 degrees from normal and 45 degrees for slip direction. Or in other words, exactly between the two. This is why max shear occurs at 45degree planes
@@TaylorSparks Thanks for the replies, I was confused about the derivation of the formula given what I know about vectors, stress and projections. I couldn't see how they came up with it in my head. The link I gave derives the formula thoroughly and in it you can see how the area is used and actually cancels out in the equation to give you the formula.
Computer is about to go to space
Lol. Pre microphone days
Greetings, dear teacher. I deformed a plate by CGP and only have the traction data, is it possible to determine the density of dislocations knowing Schmid's effort from the traction data? I’m a mechanical engineering student from Colombia.
I'm afraid I'm out of my league with this question. Sorry amigo!
@@TaylorSparks O.K., I understand. Pd: Excellent video 🙌🏻
You are god
Nah bro, there's only one God in heaven ;)
Instead, I'll settle for the Ron Burgundy of materials science.
Hi Taylor, could you do a special one involving calculation of angles between planes from XRD data for the various crystal systems.
stanley yes. That gets hard. I'll do one though.
there are many examples of the cubic system. Maybe, you could try the hexagonal and trigonal system.
here is a link to a tutorial, I'll make a video soon. www.mse.mtu.edu/~drjohn/my3200/stereo/sg5.html
try to excercise these kinda problem in hcp system
If Trss > Tcrss, does it not exhibit slip?
Correct.
@@TaylorSparks Ahh, nice! I think I will Get an A from todays exam, thanks to your videos!
@@ikerez7367 good luck on your exam!
why the [111] is not [011]? I don't understnad
I think the resulting shear stress is bigger than the critical one ?
5.593
What does bar 1 mean?
Bar 1 just means negative 1. Just convention.
hi sir, i got stuck finding the schmid factor between slip system {112} and coarse grain orientation {100}, can you help me? what is the end result?
vishal mishra what is the loading direction?
Taylor Sparks sir loading direction is not mentioned, only coarse grain orientation and slip system is given, i think we have to assume the coarse grain orientation as loading direction..
ok, in that case, since families rather than specific planes/directions are given I will select specific values. If the exact plane is (112) then the direction needs to be [-1 -1 1] and the loading direction [001]. Calculating cos(theta)*cos(lambda) we get=((0*1+0*1+2*1)/(sqrt(1^2)*sqrt(1^2+1^2+2^2))*((0*-1+0*-1+1*1)/(sqrt(3^2)*sqrt(1^2))=sqrt(2)/3
thank you.
In germany we say ich küss dein Auge ❤
Vielen dank! Es macht much glücklich zu dienen.