@8:40 The mistake you did in y0 kmap is.. the 3rd row is not don't care. It was 1 in all the columns of 3rd row in y0 (2nd ) k map. It's because.. our fourth entry in truth table says.. i3 = 0 and i2=1 and don't care for i1 = x and i0 = x Which means it specifies entries only for 2nd row. While last entry in truth table specifies values for last 2 rows of y0 (2nd)kmap. Read it carefully.. you will understand. (For students) great video. Thanks for helping me understand it.
Thank you for this video sir. However, I think there are a couple of errors made in this video, one of which many others have already pointed out. 1) @ 5:49, only the 2nd row (0 1 X X) should have 1s, not including the 3rd row (1 1 X X), because the 3rd row does not correspond to the table value and function Y1(0, 1, X, X) = 1. However, the answer still works out in the end because the table values Y1(1, X, X, X) = 1 would have covered the last 2 rows ( 1 1 X X and 1 0 X X) with 1s. 2) @ 8:06, once again, only the second row should have been covered with 0s. The third row (1 1 X X) should not have been covered with 0s because it does not correspond to table values Y0( 0, 1, X, X) = 0. Therefore, Y1(1, X, X, X) will be able to nicely cover the last 2 rows (1 X X X) with 1s; there wasn't any contradiction (mentioned at 8:44) to begin with, I guess you accidentally covered the 3rd row with 0s to make you think that. 3) @ 10:17, it should be Y0 = I3 + I1 I2' instead of Y0 = Y3 + I1 I2'. Minor error, pretty sure many understood it as the former. Nonetheless, great work at making this series, haha you must be pretty tired while making this video. I can't imagine myself multitasking like this, explaining while working out the calculations simultaneously; I would definitely have made a plethora of errors!
In the last K map, You can't put 0 (initially) on the third row because notice the truth table, it is having I2 as 1 while I3 is 0. Those "don't cares" are not "don't cares" but they are simply 1.
Neso academy is the best RUclips channel in the world.I glad that is an Indian guy.Teaching style is awesome.Thank you very much for providing depth knowledge in electronics.
The hardest step in it is the solving of k map u explained it in short and not clear....I watched this only for k map solvation and I got it after I watched the video for 10th time
Because when I3 became 1 and rest(I2, I1, I0) are don't care. Then the third and fourth row in K-map having I3 as 1 and not caring for the value of I2 we just put 1 in third and fourth row.
I really amazing to see this channel because u do this lecture before 5 year but it is very clear we easily understood everything.......... 👏keep doing ur are a grate teacher 🙂
when we are considering [I3=0 I2=1 I1=x I0=x] It should only e the second row and for [3=1 I2=x I1=x I0=x] it will be last 2 rows. So Kmap of Y1 is correct in the end but in Kmap of Y0 the 3rd row and 4th row will be all 1s.
Thank you for posting this video and explaining all of this very clearly. I was having a hard time trying to understand what my book was putting across. Now this is all very clear to me. Thanks again.
I3I2 don't care (X) is to be grouped with other corners, because during previous lectures, we were explained that don't care is also to be grouped with largest possible. And doing that, it will add I2/I0/ to the Y2 equation. Please correct me if I am wrong.
but the fact we take don't cares 1 when we have to make pairs of 1 and one's are left . but in this case there is no 1's left so we will leave don't cares as such
The Priority Encoder solves the problems mentioned above by allocating a priority level to each input. The priority encoders output corresponds to the currently active input which has the highest priority. So when an input with a higher priority is present, all other inputs with a lower priority will be ignored. Interrupt processing. It is automatic improvisation. It is done logically which is unreally.
The 3rd and 4th row should be filled with 1, as for those rows I3 is 1 and rest all inputs have don't care condition. Also....... Equation for Y0 needs correction. Y0 = I3 + I2' I1. Thank you... Janhit me jaari.........jai maharashtra
00:05 Completing the priority encoder 01:25 Priority Encoder Logic 02:49 Priority of i determines output in boolean logic 04:11 Priority encoder and logical expression 05:36 Output is 1 when i2 is 1 07:00 A function y0 is defined based on the values of i0, i1, i2, and i3. 08:26 Minimized function y0 is equal to y3 for the first group and changes in the second group need to be analyzed 09:39 Simplification using K-map for y0 gives two functions.
5:42 I2 = 1 but I3 = 0 because you need to mark only second row than I3 = 1 you can mark remaining two rows.the rout is wrong but the result is correct.
that 2nd k-map error is not a big deal...as Y(o) remains the same... actually we dont need to put those 0's in the k-map...the 1's will do (to avoid mixing)... and those who hv problem they need to restart the video(and understand the concept).
In filling the k-map entries for I2=1 & I3=0 (when Y1=0 for 2nd time) u hv filled both 2nd & 3rd row of k-map as 1. But this should not be done! U should fill only 2nd row. (& That's why the contradiction happened while filling the 2nd k-map)
8:05 third row will not contain 0 . In third row I2 is 1 and I3 is also 1 but in the truth table (4th line) I3 is zero hence row 3 will be fill from the last condition of truth table where i3 is 1.
sir for Y1 Kmap, why didnt you use don't care as 1 because that is what we do ? please be a little clear as in some cases you use as 1 and rest you don't , plz explain your steps
there is no use of i0 in the final expressions, so doesnt it become a 3-2 encoder....you havent used the concept of valid bit and if you would have done so, there was an involvement of i0 in the circuit, what is really a 4-2 encoder not a 3-2....plz explain
see, its the binary represantation of the number...... like if priority is given to I3 then binary of 3 is 1 1..... similarly if priority is given to I2 then binary of 2 is 1 0 also for I1, 1= 0 1.......
Unfortunately , I think making output don't care in case of all inputs is zeros is a mistake if we don't have an output called validate (v) to be zero in case of all inputs is zeroes otherwise to be one
in 6:22 can anyone tell me why we can't group the X (don't care) at the top with the 3 ones below it? Shouldn't we treat don't cares as 1’s when can get a larger grouping
While solving the K-Map for Y2, why can't we make the 2nd group as a group of two 1s only instead of four (as is done in the video)? Doing it this way gives, Y2 = I3 + I1.I2'.I3' instead of Y2 = I3 + I1.I2'
actually while maiking the k-map , they are ignoring the don't care value , so for 01 xx , we just need to check row/column corresponding to I3I2 as 01 and ignore I1I0 as xx
From 2:33 to 4:30 I just couldn't understand the whole point for setting values for Y1 and Y0. You should have said in order to encode I0 we need to put Y1=Y0 = 0, to encode I1 we need to encode Y1 =0 and Y0=1 and so on
very beneficial lectures.....i salute you .....keep on ..... one question pls : Y1 and Y0 will have the value of 0 0 for two conditions , when I0=0 , I1=0 , I2=0 , I3=0 & when I0=1 , I1=0 , I2=0 , I3=0 ....so how we distinguish between those two sets of inputs ?.....Thx
At around 9:05 in the Video, you replace some of the zeroes with "don't cares". I was wondering why these weren't ones since I3 has priority over I2.
i had the same question here i got the ans
But don't care is the only way which satisfy both the condition of truth table that's why we have to use don't care...
Chandan Pandey Bhai i3 ka awkaat zyada Hai... uski chalegi
aise samaj
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neso academy please pin this...
Hey bro how are you ? I thought we will be missed. THank god you i could find u. Where are you now
@8:40
The mistake you did in y0 kmap is.. the 3rd row is not don't care. It was 1 in all the columns of 3rd row in y0 (2nd ) k map.
It's because.. our fourth entry in truth table says.. i3 = 0 and i2=1 and don't care for i1 = x and i0 = x Which means it specifies entries only for 2nd row. While last entry in truth table specifies values for last 2 rows of y0 (2nd)kmap.
Read it carefully.. you will understand. (For students) great video. Thanks for helping me understand it.
are u sure bro
because i also had the same confusion
please reply
@@animeshgautam6197 100 percent
Yep
Yepp .. right.. there is mistake
You are right Kandarp!
Thank you for this video sir. However, I think there are a couple of errors made in this video, one of which many others have already pointed out.
1) @ 5:49, only the 2nd row (0 1 X X) should have 1s, not including the 3rd row (1 1 X X), because the 3rd row does not correspond to the table value and function Y1(0, 1, X, X) = 1. However, the answer still works out in the end because the table values Y1(1, X, X, X) = 1 would have covered the last 2 rows ( 1 1 X X and 1 0 X X) with 1s.
2) @ 8:06, once again, only the second row should have been covered with 0s. The third row (1 1 X X) should not have been covered with 0s because it does not correspond to table values Y0( 0, 1, X, X) = 0. Therefore, Y1(1, X, X, X) will be able to nicely cover the last 2 rows (1 X X X) with 1s; there wasn't any contradiction (mentioned at 8:44) to begin with, I guess you accidentally covered the 3rd row with 0s to make you think that.
3) @ 10:17, it should be Y0 = I3 + I1 I2' instead of Y0 = Y3 + I1 I2'. Minor error, pretty sure many understood it as the former.
Nonetheless, great work at making this series, haha you must be pretty tired while making this video. I can't imagine myself multitasking like this, explaining while working out the calculations simultaneously; I would definitely have made a plethora of errors!
your patience and grit while writing this is appreciable. I couldn't care to write so much
Most loved comment 😘❤
Yes friend, there are some mistakes, but is human to make errors.....
Nice explanation with details ❤️
thanks, was going mad
In the last K map, You can't put 0 (initially) on the third row because notice the truth table, it is having I2 as 1 while I3 is 0. Those "don't cares" are not "don't cares" but they are simply 1.
exactly
It’s fine bro,everyone makes mistakes,uk ths teacher was my last hope for my digital exams
He’s really good at teaching
Yah you're correct actually
exactly, I have also same question for last k map it is clear that I3 and I0 are 0 and 1 so only second will be 0 not third.
My exam is tomorrow and I'm binge watching it today, very helpful bro!!!!!!!!!!!!!!!!
Yes really nice videos....
Neso academy is the best RUclips channel in the world.I glad that is an Indian guy.Teaching style is awesome.Thank you very much for providing depth knowledge in electronics.
Yes, Jeet you are right....
@@circuitsanalytica4348 the video is wrong though
Neso academy if it wasn't for u guys I would have failed in digital electronics .Thank you guys😚👏
The hardest step in it is the solving of k map u explained it in short and not clear....I watched this only for k map solvation and I got it after I watched the video for 10th time
Only if these lectures were available in the past when i was doing Engineering :( these are so useful for my interview preparation !!!!!!!!!!!
where are you now..??
for the second k-map (for y0), the third row must be all 1s, not DON'T CAREs.
also, the boolean function is Y0= I3 + I1.I2'.
As i3 is mentioned 0
Hence yasamin is correct
Yes bro, you are right....
same here
please never stop to teach as you explain so easily
When we considered I2 =1 and I3 =0 why are we filling 2nd and 3rd row , It should be only 2nd row?
i thought the same
You r right Lovish Arora
That's true. only the 2nd row should have been filled when I2 = 1. It ended up working because I3 cover the 3th and 4th row.
Because when I3 became 1 and rest(I2, I1, I0) are don't care. Then the third and fourth row in K-map having I3 as 1 and not caring for the value of I2 we just put 1 in third and fourth row.
if we will fill only 2nd row then I3' will also come. That's why?
In the last k' map, Y0 will be I3 + I1*I2 complement
U have a bright future 😂🤣
I3+Ī2I1
I really amazing to see this channel because u do this lecture before 5 year but it is very clear we easily understood everything.......... 👏keep doing ur are a grate teacher 🙂
great to see you are reviewing your videos before posting, appreciate your effort in pointing those mistakes.
In case of Y0, the 3rd row of K-Map should be all 1 and not X(don't care) due to the higher priorty of i3. So there is no contradiction at all
True
when we are considering [I3=0 I2=1 I1=x I0=x] It should only e the second row and for [3=1 I2=x I1=x I0=x] it will be last 2 rows. So Kmap of Y1 is correct in the end but in Kmap of Y0 the 3rd row and 4th row will be all 1s.
Everything becomes so easy when you explain it. I can just breeze through morris mano after seeing your videos. NESO= Khan Academy, India
Yes dear friend, you are right.....
Holy shit bro! They did ask us this question for exam.
yo = I3 + I1.I2bar you have wrriten asa y3. your lectrz are nice and clear. goodjob and keep it up. i watched most of your videos
yes
i too wondered why is it like that
@@kalindikumar4018 naming conventions can differ results are same
Yes I noticed that too
Why he wrote y3 ...i am still confused 😶😶
@@thefive.am.c human error
Thank you for posting this video and explaining all of this very clearly. I was having a hard time trying to understand what my book was putting across. Now this is all very clear to me. Thanks again.
The intro music is a straight vibe. Thanks for the video.
Btw.u r a very good tutorial i hav came across for digital electronics.
Ur way of teaching is just impressive😊
Yes friend you are right....
For Y1, why don't we take into consider "Don't care value" in 0000
I3I2 don't care (X) is to be grouped with other corners, because during previous lectures, we were explained that don't care is also to be grouped with largest possible. And doing that, it will add I2/I0/ to the Y2 equation. Please correct me if I am wrong.
The best lecture I have ever listened.
Really u r gr8..
I understand Ur concepts properly than that of teachers..this lectures will help me to score in DLDA thnx fr this videos..
i'm your best oudiance ...... because you are best. keep it up bro.
I guess he started to get dizzy at the end, me and you buddy LOL !
Shouldn't it be Y0= I3+I1I2' instead of Y0=*Y3+I1I2'?
That's the answer I am getting
Silly Mistake
It happens with every one
ignore buddy it's avoidable
Ohh yes silly mistake bro
This is good because you're the first Indian guy whose accent I can CLEARLY understand LOL. Good job.
uk........dễ hiểu thật
+luc1f3rs :D damn... i shouldn't laugh at your pun but i cant control myself :D :D
damn. chill mate!! he said what many foreigners face. you didnt have to act like a loser in there
Hearing issue I guess😉😉😉
@Swarnava Bannerjee haha you rrr funny from indian accent.
In the first k-map, the first column will also from a grp as it it has 3 1's and 1 don't care and there will be atotal of 3 terms in Y1 instead of 2.
The whole class of ELL201 (second year Digital Electronics course at IITD) watched neso videos for their exams :P
will it be of immense help for the semester...i need to know
reply asap...please...
+Shouvik Roy yes
thanks mate...my sem exam is due next week...
thanks for clearing that up..
Alankar Meshram 90
And us EE101 kids too (Electrical Engineering at IITG).
The explanation was very helpful. Thanks a lot. But you did a mistake at the end, Yo=I3+I1I2bar, you wrote Y3 instead of I3.
the kmap for y0 is wrong.
it's clearly visible that inplace of don't care condition, there should be 1.
True
but the fact we take don't cares 1 when we have to make pairs of 1 and one's are left . but in this case there is no 1's left so we will leave don't cares as such
omg bhai tum yeha ho. Luckily i found you Where are you now?
Sir you just saved my semester...Thank you so much
this is an Active High priority encoder, it should be labeled. I for instance am looking for a demonstration of an active low priority encoder.
you are a wonderful teacher, best ever in my life from school to college
Yes you are right bro....
friends reallyreally you are the best one on youtube ..... number one ..... thanks thanks thanks ......... 100000000 time
The Priority Encoder solves the problems mentioned above by allocating a priority level to each input. The priority encoders output corresponds to the currently active input which has the highest priority. So when an input with a higher priority is present, all other inputs with a lower priority will be ignored.
Interrupt processing. It is automatic improvisation. It is done logically which is unreally.
well explained... and i just spotted a small mistake which may create confusion .. so just consider ,its the expression for Yo. Replace of y3 by i3
Good presentation for priority encoder. Please check the output expression for y2 and correct it.
sir good afternoon how r u ?
My only reason to recharge my mobile is to watch neso academy in youtube
Nice one!
in the 4:18 truth table, y1 and y0 position is misplaced. if I1 has input 1 then y0=0 and y1=1 but there is y1=0 and y0=1
The 3rd and 4th row should be filled with 1, as for those rows I3 is 1 and rest all inputs have don't care condition.
Also.......
Equation for Y0 needs correction.
Y0 = I3 + I2' I1.
Thank you...
Janhit me jaari.........jai maharashtra
ok done ;p
Jai Maharashtra bhava.........🚩🚩🚩
good job!!!
your voice clearly audible , teaching method crystal clear!!
Yes you are right.....
for the 2nd K-map it should be Y0 = I3 + I2.I1 instead of Y1 = Y0 = Y3 + I2.I1
this is such a good god damn channel
at 10:30 it is not Y3 + i1i2bar it should be i3 + ili2bar
00:05 Completing the priority encoder
01:25 Priority Encoder Logic
02:49 Priority of i determines output in boolean logic
04:11 Priority encoder and logical expression
05:36 Output is 1 when i2 is 1
07:00 A function y0 is defined based on the values of i0, i1, i2, and i3.
08:26 Minimized function y0 is equal to y3 for the first group and changes in the second group need to be analyzed
09:39 Simplification using K-map for y0 gives two functions.
You are very speedy in explanation
I totally understood everything you have said. Excellent!
Yes, you are right.....
1M subscribers completed.... Suddenly i seen😎💥💥💥💥💥😁🎊🎊🎊🎊🎊🎊
thank you for explaining , but at 5:46 you put 1's at 01 and 11 , but the condition was 01xx not x1xx
5:42 I2 = 1 but I3 = 0 because you need to mark only second row than I3 = 1 you can mark remaining two rows.the rout is wrong but the result is correct.
if you say so.
that 2nd k-map error is not a big deal...as Y(o) remains the same...
actually we dont need to put those 0's in the k-map...the 1's will do (to avoid mixing)...
and those who hv problem they need to restart the video(and understand the concept).
For last k map can we say that I3 has higgest priority so the 3 row can be considered as 1
In filling the k-map entries for I2=1 & I3=0 (when Y1=0 for 2nd time) u hv filled both 2nd & 3rd row of k-map as 1.
But this should not be done!
U should fill only 2nd row.
(& That's why the contradiction happened while filling the 2nd k-map)
Outputs are Y1 and Y2 ....why u wrote Y0 in place of Y2 in truthtable sir
8:05 third row will not contain 0 . In third row I2 is 1 and I3 is also 1 but in the truth table (4th line) I3 is zero hence row 3 will be fill from the last condition of truth table where i3 is 1.
Thank u sir, I easily understood this.Now I am ready to write this question in exam
there is mistake in the output of Y 2.It should be
Y2 = I2(BAR)I1+I3
There should be a correction. I think,there should be 1 at the place of X in the K-map for Y0
9:30 sir here y0=i3+i1*i2bar but you wrote y0=y3+i1*i2bar am I correct or wrong sir
You are awesome !! Please simplify other subjects as well like signal & system & communication systems. :)
If I3 is protity and results of I3 and I2 are contradictory then , shouldn't we give priority to I3 instead of using "don't care" ?
Y0 is wrong, please correct it
Thanks a lot sir..You are awesome.. You explain all the videos nicely😇
Thanq sir. Nice explanation
Please don't make mistakes it will confuse us
Yo = I3 + I1+ I2(bar) . lesson is very helpful . please do correction so that other viewers are not misguided. Thankyou
ur answer is wrong check again using k map
vishal agrawal , i got thay too
vishal agrawal *that
There is also a correction in your logic i.e. Y○= I3 + I1*I2 (bar)
Dude you wrong ;)
sir for Y1 Kmap, why didnt you use don't care as 1 because that is what we do ? please be a little clear as in some cases you use as 1 and rest you don't , plz explain your steps
Awesome! You saved me in last minute prep.
Man......keep it Up and do also for Computer science Architechture
There's a mistake in the k map of Yo. 0 should be filled in only second row, not in the third row as I3=0 and I2=1. Please edit it to avoid confusion.
there is no use of i0 in the final expressions, so doesnt it become a 3-2 encoder....you havent used the concept of valid bit and if you would have done so, there was an involvement of i0 in the circuit, what is really a 4-2 encoder not a 3-2....plz explain
I can't understand that how the values of Y1 and Y2 are coming, help me sir🙏
see, its the binary represantation of the number...... like if priority is given to I3 then binary of 3 is 1 1.....
similarly if priority is given to I2 then binary of 2 is 1 0
also for I1, 1= 0 1.......
I hope you had understood the concept.....
Unfortunately , I think making output don't care in case of all inputs is zeros is a mistake if we don't have an output called validate (v) to be zero in case of all inputs is zeroes otherwise to be one
Very nice explanation 👍👌
While implementation of Y0 there's a small mistake. .. Y0= I 3+I 0 PLEASE CORRECT IT
at 10:25, Yo = i3* at the place of Y3
There is a technical mistake in this video. For the case when I3 = 0, I2 = 1, only one row will contain 1's.
in 6:22 can anyone tell me why we can't group the X (don't care) at the top with the 3 ones below it? Shouldn't we treat don't cares as 1’s when can get a larger grouping
The last equation will be Y = I3 + I1.I2
Thanku. lecture is goodplz maintain some picture clarity
While solving the K-Map for Y2, why can't we make the 2nd group as a group of two 1s only instead of four (as is done in the video)? Doing it this way gives, Y2 = I3 + I1.I2'.I3' instead of Y2 = I3 + I1.I2'
using property x + yx' = x + y
I think something wrong u hv done in k mapping for Yo output🤔🤔
I mean the ansr is ryt.but the cocept that u have used to fill k map is not satisying
actually while maiking the k-map , they are ignoring the don't care value , so for 01 xx , we just need to check row/column corresponding to I3I2 as 01 and ignore I1I0 as xx
Yes thereo is blunder in this video, mistaken
@Gowtham M prajwal wrong hai Bhai, kyon confuse kr raha hai
Why didn't you make the 3rd and 4th column as 1 since I1 is 1 in those columns just like you did for I3 in the Y1 K map
From 2:33 to 4:30 I just couldn't understand the whole point for setting values for Y1 and Y0. You should have said in order to encode I0 we need to put Y1=Y0 = 0, to encode I1 we need to encode Y1 =0 and Y0=1 and so on
i thing instead of Y3 in the eq Y0=Y3+I2'.I1 is I3
Thank you for the help, appreciate that
very beneficial lectures.....i salute you .....keep on .....
one question pls : Y1 and Y0 will have the value of 0 0 for two conditions , when I0=0 , I1=0 , I2=0 , I3=0 & when I0=1 , I1=0 , I2=0 , I3=0 ....so how we distinguish between those two sets of inputs ?.....Thx
yeah i also want to know the same
Hi, nice presentation!
I want to ask around 2:23 when I3=0, I2=0, I1=1, why Y1=0 and Y2=1?
+nickem7 Because the LSb is y1 MSb is y2 and the binary of 1 is 01 so y1=0 and y2 =1
Hi please for the logical expression of the second output, why did you AND the I1 and I2 compliment
9:31 wouldn't it be I3 in place of Y3.
Yes
There is slight mistake at the end in the K- map of Y2 ..but the answer is still right
in priority encoder how do you palce those output value i couldnt figure out..
There is a mistake in the k map for Yo. Row 3 is not don't care. It is 1. Please change it.
how did you made k map means how did you selected the variable
Mistake in second K-map - 3rd row should be all 1's and not don't cares. That way solving, the expression for Y0 = I3'.I2'