Multiplying Logarithms With Different Bases ➕ Product Of 2 Log Terms With Argument & Base Flipped

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  • Опубликовано: 5 фев 2025

Комментарии • 13

  • @culater
    @culater Год назад +1

    SWEET ! 👍

  • @harrymatabal8448
    @harrymatabal8448 7 месяцев назад

    Excellent method. ❤

    • @nsomtc
      @nsomtc  7 месяцев назад

      Thank you 😊

  • @shamsudeenismail2917
    @shamsudeenismail2917 4 месяца назад

    Thanks ma

    • @nsomtc
      @nsomtc  4 месяца назад

      @@shamsudeenismail2917 Welcome

  • @SidneiMV
    @SidneiMV Месяц назад

    E = (log₉125)(log₂₅3)
    E = (3/2)(log₃5)(1/2)(log₅3)
    *E = 3/4*

  • @harrymatabal8448
    @harrymatabal8448 7 месяцев назад +1

    I don't know much maths but isn't terms separated by -+sign and factors by × sign

    • @nsomtc
      @nsomtc  7 месяцев назад

      I am sorry, I did not get you. Are you pointing towards the + sign that I have added in the title? That was done firstly to attract the attention of the viewers and secondly because I was having the restriction in the number of characters that I could use.

  • @adgf1x
    @adgf1x 4 месяца назад

    ?=3/4

  • @user-us4pk1oc2b
    @user-us4pk1oc2b 7 месяцев назад

    1:52 madre mía lo que habla

    • @nsomtc
      @nsomtc  7 месяцев назад

      Hi, could you please write in English? I don't understand your language.

    • @pspprabhat
      @pspprabhat Месяц назад

      =>>{3log(5)/2log(3)}
      {Log(3)/2Log(5)}
      =3

    • @nsomtc
      @nsomtc  Месяц назад

      @@pspprabhat Please check your final answer