Timestamps 00:00 - Introduction 09:22 - Location of the object: Reference point 14:31 - Physical quantities 19:43 - Rest and Motion 26:02 - Distance and displacement 49:02 - Uniform and Non-Uniform motion 57:34 - Speed and velocity 1:05:25 - Average speed and velocity 1:27:26 - Acceleration/Retardation 1:43:34 - Equations of motion 2:14:22 - Graphs: Area and Slope under graph 3:08:27 - Uniform circular motion 3:19:02 - Thank You
Timestamps 00:00 - Introduction 09:22 - Location of the object: Reference point 14:31 - Physical quantities 19:43 - Rest and Motion 26:02 - Distance and displacement 49:02 - Uniform and Non-Uniform motion 57:34 - Speed and velocity 1:05:25 - Average speed and velocity 1:27:26 - Acceleration/Retardation 1:43:34 - Equations of motion 2:14:22 - Graphs: Area and Slope under graph 3:08:27 - Uniform circular motion 3:19:02 - Thank You Bachhon
2:13:16 Sir if we do the sum using equation 3 , the answer is 20√6m/s. v²-u²=2as Or v²-0²=2(-10)(-120) Or v²=2400 Or v=√2×2×2×3×2×5×2×5 Or v=2×2×5√3×2 Orv=20√6
00:00 - Introduction 09:22 - Location of the object: Reference point 14:31 - Physical quantities 19:43 - Rest and Motion 26:02 - Distance and displacement 49:02 - Uniform and Non-Uniform motion 57:34 - Speed and velocity 1:05:25 - Average speed and velocity 1:27:26 - Acceleration/Retardation 1:43:34 - Equations of motion 2:14:22 - Graphs: Area and Slope under graph 3:08:27 - Uniform circular motion 3:19:02 - Thank You Bachhon
Neev op nahi maha op he sir he hamare future ko Etna aage badne ka sahas deta he sir realy me sir neev Is op ........sir ko support karne wale like kare
Hoho helllo dosto❤ Like if you know the answer reply to check answer 1) (2)⁵×(5)⁵= 2) 2×2+2 = 3)v=10 mps U=0 mps A=5s Find t By using equation of motion Oh my god only 2 people know the answer
46:44- Yes,if the body has travelled certain distance then also it can have zero displacement.ex- i - if the body complete one round in circular path ii - if body moves in the straight path and again returns at the initial pasition
Yes, its possible to have displacement as 0. Only if the object starts and returns to it initial position after covering some distance. I HOPE THAT'S CORRECT :)
1:10:46 Average Speed= Total Distance/ Total time ~ 30m+40m/20sec ~70/20=3.5m/sec And, Average Velocity=Total displacement/Total time ~ Displacement = s²=h²+b² =s²=(40)²+(30)² =s²=1600+900 = s = √2500 =s=50 meter Hence ~ Average Velocity = Total displacement/Total time ~ 50/20 =2.5 m/s ..........
46:21 sir i think this trick does not always work because instead of taking 10 m as the final foint if the farmer had stoppee at the half of the side on which you had taken then it will stip at 5m which mean after calulating displacement will be 5√5 , so concluaion is that this tricks inly work when the displacement is aligned with any of the diagonal of the square......... Althougu tis was good trick thank you sir 🙏🙏
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Now it's ok after editing thankyou I understand which button I should tap it's the like button
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Timestamps
00:00 - Introduction
09:22 - Location of the object: Reference point
14:31 - Physical quantities
19:43 - Rest and Motion
26:02 - Distance and displacement
49:02 - Uniform and Non-Uniform motion
57:34 - Speed and velocity
1:05:25 - Average speed and velocity
1:27:26 - Acceleration/Retardation
1:43:34 - Equations of motion
2:14:22 - Graphs: Area and Slope under graph
3:08:27 - Uniform circular motion
Like❤ nhi kiya tho exam mai fail
This helps so much to find the topic we want to revise ✨
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@@YashRajRai-il5de ohh okk....
@@gitagyani2694 bro better study free fall (acceleration due to gravity) from this chapter carefully cuz this topic is given in chapter 3
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Timestamps
00:00 - Introduction
09:22 - Location of the object: Reference point
14:31 - Physical quantities
19:43 - Rest and Motion
26:02 - Distance and displacement
49:02 - Uniform and Non-Uniform motion
57:34 - Speed and velocity
1:05:25 - Average speed and velocity
1:27:26 - Acceleration/Retardation
1:43:34 - Equations of motion
2:14:22 - Graphs: Area and Slope under graph
3:08:27 - Uniform circular motion
3:19:02 - Thank You
One like = 99%
0:02 introduction
9:15 reference point
14:31 physical quantity
19:44 Motion and rest
26:07 distence and displacement
48:59 uniform and non uniform
57:42 speed and velocity
1:27:26 acceleration and retardation
1:43:30 3 equation of motion
2:14:25 Graph
3:08:32 uniform circular motion
3:19:03 thankyou
😊
Timestamps
00:00 - Introduction
09:22 - Location of the object: Reference point
14:31 - Physical quantities
19:43 - Rest and Motion
26:02 - Distance and displacement
49:02 - Uniform and Non-Uniform motion
57:34 - Speed and velocity
1:05:25 - Average speed and velocity
1:27:26 - Acceleration/Retardation
1:43:34 - Equations of motion
2:14:22 - Graphs: Area and Slope under graph
3:08:27 - Uniform circular motion
3:19:02 - Thank You Bachhon
Best teacher in the world 🌎🌎 of physics
2:13:16 Sir if we do the sum using equation 3 , the answer is 20√6m/s.
v²-u²=2as
Or v²-0²=2(-10)(-120)
Or v²=2400
Or v=√2×2×2×3×2×5×2×5
Or v=2×2×5√3×2
Orv=20√6
same doubt
Yes I am also stuck at this that why there is no negative sign in this.
Neev op❤️ 3:36
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Pahlai Sai hai😅
fff
OA=accelerated motion
AB=uniform motion
BC=retardated motion 2:54:38
Non uniform motion...
Happy teachers day to all teachers
sir it is my grant request to you to make video on chap gravitation
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Yes, It's Displacement can be zero, if the object's initial and final postion is same . 🔥🔥🔥
Happy teachers day sir
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1 like 99.9% in next year board. 😁
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33:48 distance 30 m
Displacement 30 m
Thank you sir 😊 motion chapter lane ke liye ....pr aap se padhne me maja aata hai 😊😊😊
You 🤡 your profile pic ❤
@@AviralPathak69why?
00:00 - Introduction
09:22 - Location of the object: Reference point
14:31 - Physical quantities
19:43 - Rest and Motion
26:02 - Distance and displacement
49:02 - Uniform and Non-Uniform motion
57:34 - Speed and velocity
1:05:25 - Average speed and velocity
1:27:26 - Acceleration/Retardation
1:43:34 - Equations of motion
2:14:22 - Graphs: Area and Slope under graph
3:08:27 - Uniform circular motion
3:19:02 - Thank You Bachhon
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Yes ❤
46:47 Maybe...
Whose exams are from 18 September 🙃
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Mera bhi hai
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Bro tel me your school name if it's lps/c then tell me your room no
U made physics easier for me thanks sir for these wonderful sessions 🙏🏻😊❤
oa= non uniform motion , ab=uniform motion and bc= uniform motion in opposite direction ( negative accelertion)
1:11:00 Savg=35m/s
Vavg=25m/s
.*
🔥🔥🔥🔥🔥🔥neev op🔥🔥🔥🔥🔥🔥 3:36
Neev op op op ............😊
46:24 yes if the object again come on its initial position
Please vote:for force and law and motion
2:49:52 SIR AANAND(PLEASURE)HI AA GAYA😂😂
2:54:19 OA=Non-Uniform Motion
AB=Uniform Motion
BC=Non-Uniform Motion(Decreasing Velocity)
Fr :)
Hloo sirr प्लीज force and laww of motion padha dijiye 0:44 0:45 0:45
Padha rakha hai previously😂
@@AviralPathak69 Areep
@@AviralPathak69 aree murkh (pagal) maii isss year padhane ki battt kar raha tha samjhii
Yes ,it can have zero displacement when an object starting from initial point covers a distance and comes back to starting point.
46:57 yes, But only if the object has traveled back towards the initial point.
46.43
Yes it can have if the body travels back to its original position.
Kaun-kaun bacche is sar Ko pasand karte
*sir*
2:54:23 OA= accelerated motion
AB = uniform motion
BC=retardation
Kon kon neev 2025 batch sa ho like koro
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46:49 yes, it can be if a body move from its their position and again come tothat position only
Legend know it's re-uploaded 😄
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Bhai tune concept clear kr diya mere dimag ka wahi mai Sochu abhi toh lecture dekha tha achanak gayab kaise hogya 😅😅😂😂
I like u sir
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Neev op nahi maha op he sir he hamare future ko Etna aage badne ka sahas deta he sir realy me sir neev Is op ........sir ko support karne wale like kare
Yes, it have 0 displacement if the object start moving From a Point then come back on same Point.
Whose exam 21september🎉
46:50 yes, An object can have zero displacement if the object's initial and final position was the same...😺
Sir you are the best teacher in the world ❤️❤️❤️❤️🌍🌍
Hoho helllo dosto❤
Like if you know the answer reply to check answer
1) (2)⁵×(5)⁵=
2) 2×2+2 =
3)v=10 mps
U=0 mps
A=5s
Find t
By using equation of motion
Oh my god only 2 people know the answer
1:59:29 Yes sir maine re attempt Kiya...☄️
hello sir mere school me derivation aayega lekin
muje link me video nahi mila 😢
please sir youtube pe video upload Kar dijiye please sir please
Hello sir mujhe mil gaya thanks sir ❤❤
Happy teacher’s day sir 🔥🔥✨✨
46:47 Yes, If the Intial position or point of a object clashes with its final position or point then we can say the Displacement of an object is 0.
You are best teacher❤❤
Yes, it have zero displacement if the object starts moving from a point and then comes and stop to that point .
Sir aapne aannand ka utsav manvya diya humse❤ 2:49:56
46:46 yes sir
47:43 yes it can have zero displacement if it's initial and final point are same
46:44- Yes,if the body has travelled certain distance then also it can have zero displacement.ex- i - if the body complete one round in circular path
ii - if body moves in the straight path and again returns at the initial pasition
Areee bhaiya Dil se thank u pura graph smjh me a gaya I Love you Sir ❤❤❤❤❤❤❤
Neev op❤❤❤ 1:59:52
46:45 = yes😊
1:58:10= did it🎉
2:49:55 = yes sir ekdam crystal clear ho rahe he concepts❤
46:55 is yes
2:51:00 OA=linear graph, OB= rest, Oc= retardation
NEEV OP
Love from neev 2025 batch sir
46:47 yes it can have 0 displacement though it has covered a distance if its initial and final position are same.
Yes, its possible to have displacement as 0. Only if the object starts and returns to it initial position after covering some distance. I HOPE THAT'S CORRECT :)
Thank you sir for this one shot revision video❤
Mai neev batch me bhi hu , Mera revision hogya❤
3:08:03 ye question mere paper mei aaya tha school exam
Sir parso board ka paper hai!
NEP ke karan 9th me hu boards ho gaya hai or ek topic padh kar doosra topic me bhool Jaa Rahi hu!!😢
46:48 obvesely yes
Yes an object can have zero displacement if the objects initial position and final position are the same
2:18:20 is funny movement
2:45:18 New confusion unlocked 💀💀
Na bhai speed badhte jaa rahi h😂😂
@@c.ssurya19 to curve 〰 line ka bhi to ho sakta hai 📈
2:49:54 yes sir
it can have zero displacement
47:38 yes can be displacement zero
🔥🔥🔥🔥
1:33:01 Thala for a reason 😂
BIG STEPPERS UNDERGROUND METHODS
1:05:25
Happy teacher's day sir and all teachers 🎉🎉🎉
😊😊
46:46 yes sir object ki displacement
Sir Maine exercise Star Kari ye wali equation of motion
1=100000now=300000samajgaya 2:19:34 2:19:34 2:19:34 2:19:34 2:19:34 2:19:34
1:16:12 How relestic voice 😮😮
1:59:21 yes sir mene kiya exercise 🎉
me also i thought this chapter was very hard but of sir he make very easy
@@ayushanwitashukla9764 yess thats why i love Rakhask sir❤️❤️
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@@AdityaKumar-x2p9u 2 hour ka video huya question practice ke sath aj force and laws bhi kar lunga ho payga ya nahi
38:41 d option
35:54 distance 40 m
Displacement 20 m
Not equal
46:46 Yes!
1:59:49 1:59:51 🎉
D , 38:37 😊
Happy teacher's dAy🎉🎉🎉🎉to the best teacher 💓
Thankyou sir for this video this is very help ful for mid term exam
1:10:46
Average Speed= Total Distance/ Total time
~ 30m+40m/20sec
~70/20=3.5m/sec
And, Average Velocity=Total displacement/Total time
~ Displacement = s²=h²+b²
=s²=(40)²+(30)²
=s²=1600+900
= s = √2500
=s=50 meter
Hence ~ Average Velocity = Total displacement/Total time
~ 50/20 =2.5 m/s ..........
46:21 sir i think this trick does not always work because instead of taking 10 m as the final foint if the farmer had stoppee at the half of the side on which you had taken then it will stip at 5m which mean after calulating displacement will be 5√5 , so concluaion is that this tricks inly work when the displacement is aligned with any of the diagonal of the square.........
Althougu tis was good trick thank you sir 🙏🙏
Thank you❤❤❤ god...
For giving me the teacher..
Yaar ye kitne osam h yaar..... ❤❤❤❤❤
Love you sir by us
Concept clear h sir😊✅
1:59:30 🥰🥰