Find Probability of a Pair in Poker Hand of 5 Cards

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  • Опубликовано: 10 сен 2024
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Комментарии • 33

  • @ericatwood856
    @ericatwood856 4 года назад +1

    Great Video! I am doing my statistics class and I watched the lecture video on this and it didn't make any sense at all. Your explanation was so clear and understandalbe. Thank you!

  • @shivronsugrim3389
    @shivronsugrim3389 5 лет назад +8

    Great video! I have a question, Why after choosing the pair (13* 4C2) cant you multiply by 48C3 ? What makes the answers so different?

    • @alishehper1
      @alishehper1 2 года назад +1

      because the other 3 cards have to. be of different values; else it will not be "a pair" anymore.

  • @utpalkumar2770
    @utpalkumar2770 5 лет назад +4

    After one pair, there can three card of same type in that case ur answer is wrong

  • @shobhasundar8232
    @shobhasundar8232 3 года назад

    You have explained very well. Thank you
    A math teacher from Bangalore🙏

  • @XxNinjaLimeXX
    @XxNinjaLimeXX 4 года назад

    I can't find an answer :(. Can anyone tell me how the probability equation would change if we allowed for getting more aces? Like not excluding other better hands just the most basic what are the chances of getting 2 or greater of the same rank in a hand of 5

  • @RCLIP106
    @RCLIP106 4 года назад +1

    If we consider two pair as a subset of one pair, then this solution is correct. Otherwise this solution is wrong. Or am I missing something?

    • @MathematicsTutor
      @MathematicsTutor  4 года назад

      Here is correct solution: ruclips.net/video/sj6lbNEPI64/видео.html
      Thanks

  • @ddstar
    @ddstar 4 года назад

    Sir, I know these videos are old, but can you do a video of expected combinitions? You have a hand 9H, TH, JH, QC, AC. What is combinitions of drawing a straight?

  • @jiyang4602
    @jiyang4602 Год назад +1

    Where did 4^3 came from?

    • @MathematicsTutor
      @MathematicsTutor  Год назад +1

      3 of any 12 with 4 suits. Hope that helps. Thanks

    • @jiyang4602
      @jiyang4602 Год назад

      @@MathematicsTutor thank you. I understand it now

  • @lifestyles2482
    @lifestyles2482 5 лет назад +1

    Do u mean the flop containing a pair or in Texas Holdem where u are dealt 2 whole cards that make a pair on the flop (5cards)?

    • @MathematicsTutor
      @MathematicsTutor  5 лет назад +1

      Here we have 5 cards, 2 of them of same value like 2 Queens as explained. Thanks

    • @lifestyles2482
      @lifestyles2482 5 лет назад +1

      Anil Kumar this does not answer my question. I’m guessing it has less to do with cards in hand.

    • @MathematicsTutor
      @MathematicsTutor  5 лет назад +1

      @@lifestyles2482 I do not know the rules of Texas Holdem. In the video, we are talking about dealing 5 cards and we need to know the probability of getting exactly two of the same kind. So, if we have 2 Kings, then the other three can be any other card. Thanks

    • @lifestyles2482
      @lifestyles2482 5 лет назад +1

      Anil Kumar ok. It would be even more interesting if u did a video on probability regarding making a pair on the flop and also probability of improving the hand on the turn and the river.

    • @MathematicsTutor
      @MathematicsTutor  5 лет назад +1

      @@lifestyles2482 I will surely do. Thanks

  • @mbk928
    @mbk928 5 лет назад

    Thanks Clear and easy

  • @HankC9174
    @HankC9174 2 года назад

    but the ' other ' 3 cant be a pair also yes ?

  • @Rob_Lerch
    @Rob_Lerch 6 лет назад +1

    Silly question here... What does the "C" mean... Like when you type it into the calculator, what is the math behind the "C"?

    • @MathematicsTutor
      @MathematicsTutor  6 лет назад +2

      Thanks. C is for combinations. Hope this video can help ruclips.net/video/Mjwb5t6tW98/видео.html
      Thanks

  • @mehjamilabonny4160
    @mehjamilabonny4160 3 года назад +1

    wrong answer.

  • @gorkemcinar8600
    @gorkemcinar8600 Год назад +1

    Kumar means gamble in turkish😂

  • @jangbahadur8635
    @jangbahadur8635 4 года назад

    A card bara hota h y k card

  • @alvarolealjr
    @alvarolealjr 4 года назад +1

    Not to be racist or anything but *inserts racist comment about accent. jk excellent explanation

  • @shivronsugrim3389
    @shivronsugrim3389 5 лет назад +1

    Great video! I have a question, Why after choosing the pair (13* 4C2) cant you multiply by 48C3 ? What makes the answers so different?

    • @MathematicsTutor
      @MathematicsTutor  5 лет назад

      Can't answer your question. However, the approach which I have taken makes more sense.
      Thanks

    • @Amantri98
      @Amantri98 4 года назад

      I think his version prevents another pair from arising.

    • @joshuagarcia6767
      @joshuagarcia6767 2 года назад +2

      I think it is because if you multiplied it by 48C3 then there is a possibility that you get another card that is the same as the pair and if you do, then it would no longer be a single pair :)