Partial Fractions | Improper Fraction. Lesson 2
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- Опубликовано: 15 дек 2024
- #ImproperFractions
Sometimes the degree of the numerator of the fraction we wish to resolve into partial fractions may be equal or higher than the degree of the denominator. In this case, we first use long division to divide the numerator by the denominator before we proceed to resolve into partial fractions.
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You need to be given " World Best Solver"
No make my head big 😁
@Tambuwal Maths Class I am new here, and I need more of examples on this.
This exact question is in my textbook,newfurther mathematics project😁😁😁
Professor Tambuwal thank you for another solid explanation of Partial Fraction Decomposition which involves Improper Fraction. Students will encounter this material in Precalculus and Calculus II.
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I appreciate it
You are the best brother man 🙏
Thank you
thank you so much
Great
Can you solve it straight forward?
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How can we prove this?🙏
I used the other method and got different values for A n B (-10 n 25) respectively
The answer should not be different
Could you perhaps try solving it and point out where I could be going wrong
@@MMN3111 I can't point your error as I have no idea how you solved it
Sir please is this the type 4
Thank you very much sir, your really helped me..... May God bless you, you earned a subscriber 🥀
I appreciate it
Hello thanks for helping but I have a problem
Please answer what happens if [x-1] is given as [3x-2]
The question is not clear to me.
@@tambuwalmathsclass like in most of your examples the denominators[linear factors] are [x-1] and [x-2] am asking what if the [x-1] is [3x-2]
Ok, treat them exactly the same