Trajectory of a Projectile | Motion in a Plane Class 11 Physics | Kinematics 2d | NEET

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  • Опубликовано: 2 авг 2024
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    Learn about the trajectory of a projectile in Motion in a Plane for Class 11 Physics. Essential for NEET exam preparation. Join NEETx by Vedantu for more!
    0:00 Motion in a Plane
    0:47 Motion in a Plane | Kinematics 2D
    2:16 Trajectory of a Projectile
    11:07 Trajectory of a Projectile in 'R' Form
    16:18 Tatva Book Questions
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Комментарии • 31

  • @NEETXbyVedantu
    @NEETXbyVedantu  Месяц назад

    Hey everyone! 🌟 Thank you for watching. If you're serious about your NEET preparation, don't miss out on these essential playlists:
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  • @user-od8jf5mr2x
    @user-od8jf5mr2x 23 дня назад +1

    Equation of trajectory :-
    xtantheta - gx²/2u²cos²theta
    OR
    xtantheta(1-x/R)
    Thankyou very much sir
    Your sessions are one stop solution for all our worries and "fear of topics"
    A request :- I'm not able to solve oblique angle projections of projectile from a height *please bring a short session for this topic too*
    Thankyou

  • @PritamMurmu-rp8go
    @PritamMurmu-rp8go 17 дней назад +1

    Trajectory of a motion =
    y=xtan(theta)-gx^2/2u^2cos^2(theta)
    Trajectory of a projectile in R direction
    y=xtan(theta)-[1-x/R]

  • @ishikaaggarwal8569
    @ishikaaggarwal8569 7 дней назад

    Eqn of trajectory = y= xtantheta - gx²/2u²cis²theta
    Trajectory in range = y= xtantheta(1-x/R)

  • @samarthduryodhan791
    @samarthduryodhan791 2 дня назад

    Y=xtan theta-gx^2/2u^2cos^2theta
    Y=xtan theta(1-x/R)

  • @BishwaThisSide
    @BishwaThisSide Месяц назад +4

    Thank u bhaiya! Pta hai main aapko bahut Miss kr rhi thi needed ur assurance ki sab acha ho🥺❤️ and congrats for India's win!! ✨⭐

  • @PDF_FILE12
    @PDF_FILE12 12 дней назад

    Y= xtantheta -gx2/2u2cos2theta and also y= xtantheta(1-x/r)

  • @tauqeerraza6103
    @tauqeerraza6103 22 дня назад

    Equation of trajectory of a projectile :
    Y= xtanA - gx²/2u²cos²A
    Equation of trajectory of projectile in R form :
    Y= xtanA[1-x/R]
    Thank you sir for this amazing session ❤

  • @Rithika_2008
    @Rithika_2008 13 дней назад

    xtantheta(1-gx/u²sintheta)
    xtantheta(1-x/R)

  • @Dedeepya_
    @Dedeepya_ Месяц назад +1

    thank u sm for making this daravna looking derivation super easy 🥹
    ab confidence aa gaya!
    balle balle✌🏻❤

  • @rajkumarbarman8836
    @rajkumarbarman8836 26 дней назад +1

    Sir in the first lecture you said tatva neet contains 27 book

  • @ritadsouza3961
    @ritadsouza3961 29 дней назад +1

    TRAJECTORY OF A PROJECTILE:- y=x/tan@-gx²/u²cos²@
    TRAJECTORY OF A PROJECTILE IN 'R' FORM:- y=xtan@[1-x/R]

  • @Samy._.y720
    @Samy._.y720 29 дней назад

    1.Trajectory of projectile:- y= x tant theta --gx²/2u²Cos²theta.
    2. Trajectory of range:- y = x tan theta(1--x/R)
    Lots of love sir ji....❤

  • @Pooja_G_845
    @Pooja_G_845 Месяц назад +1

    Sir what about Chemistry and biology lecture, vo kabhi start honge?? Sir ❤❤❤

  • @dulichandkaushal3019
    @dulichandkaushal3019 10 дней назад

    Y=xtanQ (1-x)/r

  • @NikitaParida-oy4vi
    @NikitaParida-oy4vi 19 дней назад

    Equation of trajectory of projectile --- y = x tan theta - gx^2÷ 2u^2 cos^2 theta
    Equation of trajectory of projectile in R form ----- y = x tan theta [ 1 - x/R ]

  • @Ryzen001
    @Ryzen001 22 дня назад

    Formula video banao

  • @vargabkalita2895
    @vargabkalita2895 11 дней назад

    y=xtantheta -gx2/2u2cos2theta
    y=xtantheta -x/r

  • @YouTubee__shortz
    @YouTubee__shortz Месяц назад +1

    Bhaiya bio me physioliogy kb kar vao ge😢

  • @babloorajpoot8774
    @babloorajpoot8774 28 дней назад +2

    Sir lec. 2 nhi mil. Rha

  • @Arnav-db2ek
    @Arnav-db2ek Месяц назад +1

    Sir best physics book?

    • @shourya__gupta
      @shourya__gupta Месяц назад

      Notes and practice book like ncert mtg, pyqs book and teachers lecture dpps , assignment

  • @ryuk.1_
    @ryuk.1_ 28 дней назад

    Sir motion in plane L2 video kaha hai?

  • @Kakyoin69812
    @Kakyoin69812 Месяц назад

    sir kya ye videos school exams ke liye theek hai (cbse)

  • @user-gq1fq5uj8i
    @user-gq1fq5uj8i 29 дней назад

    y=xtan@-gx2/2u2cos2@ equation of trajectory
    y=xtan@(1-x/R) equation of trajectory in form of R
    sir apki rehte hue life thoda easy hogayi hai 11th mai....