12 physics I Rotational Dynamics I Solved Example 1.6 I VIDEO-2 /A tiny stone of mass 20 g is tied
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- Опубликовано: 29 сен 2024
- VIDEO-2 / A tiny stone of mass 20 g is tied to a practically massless, inextensible, flexible string and whirled along vertical circles. Speed of the stone is 8 m/s when the centripetal force is exactly equal to the force due to tension. Calculate minimum and maximum kinetic energies of the stone during the entire circle. Let theta = 0 degree be the angular position of the string, when the stone is at the lowermost position. Determine the angular position of the string when the force due to tension is numerically equal to weight of the stone. [ Use g =10 m/s2 and Length of the sting = 1.8 m ]
Thank you sir
Thanks sir
Don't worry sir we will help you to grow our channel just keep uploading vedio
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Hope our channel will grow..
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Thanks for your valuable support bro..🙏
Sir your videos are very helpful
Will u explain exercise numericals too?
Yes I will..
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Sir why did you take 179°60'
Bcoz, 1°= 60'
& 180° = 179° + 1° = 179° + 60' = 179° 60'
Sir please make videos on numerical from exercise... your explanation is awesome 😇
can you show the solving of the last part- cos theta, log and all?It would be more helpful. Thank you:)
See video on Oscillation example 5.2, where I solved cos inverse it would help you to clear your doubt upto certain extant..
Watch some more videos where I have solved log and antilog too.
Sir plz all chapters ke numerical upload kijiye
Aap bhot aacha pdate ho
Yes absolutely, I will make videos on all chapter..thanks for watching the video 🙏
Please make video on last part
Ok👍
very good sir nicely explained minute details of the question that were not given in tb thank u very much
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Watch my latest videos it is in animated form..
This type not in mhtcet come??
This is a state board numerical...
But the concept of these numerical will definitely help in mhtcet.
Kup chan explain kelat sir thank you
Bhot sahi Sirji
Keep making such videos.
You made it very simple to understand.
All the best❤️
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Thank you so much sir 😊
You r legend 😍🥰
Outstanding ♥️
Sir plz keep going it helps a lot ❤
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Sir T ki jagah mg kaise liya...?
12:08
Qki question me hi deya huva hai
"When force due to tension (T=F) is numerically equal to weight (mg) of the stone.
Therefore T=F=mg
@@swapnilkipathshala9560 thanks sir...
Sir aap great physics teacher ho
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