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I’ve seen this little cascading double angle trick about 98 times by now
same lol
Where do you find content like this? Looks kinda interesting.
@ I found it doing some training for the hardest national university entrance exams in Brazil
sin(n)~n for small n this is the fundamental theorem of engineering
LMAO I DO MATH OLYMPIADS AND DID EXACTLY WHAT U SAID AT THE START
Can you solve this:integral(from 0 to pi) of x^2/(asin^2x+bcos^2x) wrt x pls?
i shall try XD
Thank you 😊
Please take some good integral from indian engineering entrence exam jee advanced
Can you teach feynman rule of integration or has it been already covered?
it has already been cover
Its too easy try some of good jee advanced integral problem
that good jee dick 😫😫😫💦💦💦💦
sin(x)=2sin(x/2)cos(x/2)=4sin(x/4)cos(x/4)cos(x/2)=...=2^n•sin(x/2^n)prod[k=1,n](cos(x/2^k)P(x)=lim[n->♾️](sin(x)csc(x/2^n)/(2^n))u=2^-nP(x)=sin(x)lim[u->0](u/sin(ux))P(x)=sin(x)/x•lim[u->0](sec(ux))sec(0)=1P(x)=sin(x)/xI=int[0,pi/4](sin(x))dxI=cos(0)-cos(pi/4)I=1-sqrt(1/2)
Integral Insanity!!!
I’ve seen this little cascading double angle trick about 98 times by now
same lol
Where do you find content like this? Looks kinda interesting.
@ I found it doing some training for the hardest national university entrance exams in Brazil
sin(n)~n for small n this is the fundamental theorem of engineering
LMAO I DO MATH OLYMPIADS AND DID EXACTLY WHAT U SAID AT THE START
Can you solve this:
integral(from 0 to pi) of x^2/(asin^2x+bcos^2x) wrt x pls?
i shall try XD
Thank you 😊
Please take some good integral from indian engineering entrence exam jee advanced
Can you teach feynman rule of integration or has it been already covered?
it has already been cover
Its too easy try some of good jee advanced integral problem
that good jee dick 😫😫😫💦💦💦💦
sin(x)=2sin(x/2)cos(x/2)
=4sin(x/4)cos(x/4)cos(x/2)
=...
=2^n•sin(x/2^n)prod[k=1,n](cos(x/2^k)
P(x)=lim[n->♾️](sin(x)csc(x/2^n)/(2^n))
u=2^-n
P(x)=sin(x)lim[u->0](u/sin(ux))
P(x)=sin(x)/x•lim[u->0](sec(ux))
sec(0)=1
P(x)=sin(x)/x
I=int[0,pi/4](sin(x))dx
I=cos(0)-cos(pi/4)
I=1-sqrt(1/2)
Integral Insanity!!!