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Sir, I agree 💯 with your approach. However, if the point load corresponds with a horizontal distance of 2m, then it is acting at 2.5m on the member/beam. Ay = 9kN; By = 6kN & Ax = 4.5kN
Why did not we just use the similar triangle also in solving Ay?
Can you please explain how how got by4.8 and bx 3.6
Hi dear...why cosine is used for x axis ( horizontal) and sine for y axis ( vertical).. Hope to clear this point as soon as possible!!!
I was wondering the same thing... if you find any related videos that clears this up please let me know
I think the perpendicular distance from A in case (1) is incorrectly shown
hello sir , how did it come up to have answers 3.6 KN and 4.8 KN?
I see .. I got it .. thank you for the video sir
Please explain
3.6 & 4.8 kn...explain please
did you figure it out?
explanation was very confusing
Sir, I agree 💯 with your approach. However, if the point load corresponds with a horizontal distance of 2m, then it is acting at 2.5m on the member/beam.
Ay = 9kN; By = 6kN & Ax = 4.5kN
Why did not we just use the similar triangle also in solving Ay?
Can you please explain how how got by4.8 and bx 3.6
Hi dear...why cosine is used for x axis ( horizontal) and sine for y axis ( vertical).. Hope to clear this point as soon as possible!!!
I was wondering the same thing... if you find any related videos that clears this up please let me know
I think the perpendicular distance from A in case (1) is incorrectly shown
hello sir , how did it come up to have answers 3.6 KN and 4.8 KN?
I see .. I got it .. thank you for the video sir
Please explain
3.6 & 4.8 kn...explain please
did you figure it out?
explanation was very confusing