Hi Mr can you solve this question please lesson number 5 : using the distributive property 5c^2 v-15 c^2 v^2 + 5c^2 v^3 You can find this in page number 665 question number 6 If you can do a Short video please this will help a lot
Please click on the link below to watch the explanation for the question you asked. Please Like👍, Share✅ & SUBSCRIBE 📌 @bestmathuae ruclips.net/video/OWy7_eGop6E/видео.html
If you have common terms that are multiples in both terms them you need to factor it out again. But if you cannot find any common terms in both the terms, then you will not be able to factor it further.
If any of the factors are in the form of identities then they can be factored again. Eg: If the factor is in the for of (a^2 - b^2) then it should be factored again where as if it is in the form of (a^2 + b^2) then you cannot because there is no identity when it is plus between the squares.
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Thank you bro
Hi Mr can you solve this question please lesson number 5 : using the distributive property
5c^2 v-15 c^2 v^2 + 5c^2 v^3
You can find this in page number 665 question number 6
If you can do a Short video please this will help a lot
I definitely will do a video explanation for this problem and send it tomorrow.
Please click on the link below to watch the explanation for the question you asked. Please Like👍, Share✅ & SUBSCRIBE 📌 @bestmathuae
ruclips.net/video/OWy7_eGop6E/видео.html
How we will know if the number need to factor again or not?
like question 29 in the book -16 + p^2
If you have common terms that are multiples in both terms them you need to factor it out again. But if you cannot find any common terms in both the terms, then you will not be able to factor it further.
How we will know if the number need to factor again or not?
If any of the factors are in the form of identities then they can be factored again. Eg: If the factor is in the for of (a^2 - b^2) then it should be factored again where as if it is in the form of (a^2 + b^2) then you cannot because there is no identity when it is plus between the squares.
@@bestmathuaeoh thank you
@@user-uk8yh6xh4g You are most welcome 😊