A Quick and Easy Sangaku Puzzle with Three Circles

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  • Опубликовано: 3 фев 2025

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  • @Qermaq
    @Qermaq Год назад +4

    BTW the general case of n circles arranged in a row under a semicircle is interesting. If you want to try that yourself stop reading. I found the answer to be this: if the semicircle's radius is R and the small circles' radii are all r, and there are n circles, R/r = sqrt(n^2-2n+2)+1.

  • @gauravraj3945
    @gauravraj3945 Год назад +1

    thanks sir

  • @Qermaq
    @Qermaq Год назад +2

    Rule of thumb: whenever you see two circles that are tangent, always draw a line passing through the centers. It always leads to something.

  • @vzaimo
    @vzaimo Год назад +4

    There's also (√5-1)x/4 in the first solution, not (√5-2)x/4 :)

    • @rlf4160
      @rlf4160 Год назад +2

      Possible that the 2 in the numerator was missed when reducing the fraction /8

  • @markkennedy9767
    @markkennedy9767 Год назад +1

    I think there's a mistake at 4:40 when dividing by 8

  • @Qermaq
    @Qermaq Год назад

    Oh hey not to be a pest, but this reminded me of another circle puzzle I don't think you've done. Dunno if you are making new geometry videos but if so this is a goodie and right up your alley.
    Two circles with radius 2 are tangent. Let's say one is on the left and one is on the right, Above them and tangent to both is a circle with radius 1. These three circles are all themselves tangent to a larger circle that encompasses them. There is a fourth circle at the bottom that is tangent to the circumcircle and the two r=2 circles. What's its radius?

    • @ShortsOfSyber
      @ShortsOfSyber  Год назад

      Hey Qermaq, you'll never be a pest! 😉
      I love your comments even though I'm unable to respond to all.
      I know you've been around for a long time and I hope to see you when we reach millions! Thank you for your support and amazing ideas! Please keep 'em coming. Looks good to me! I'll take a look at this idea. 💖🥰

    • @Qermaq
      @Qermaq Год назад

      @@ShortsOfSyber you bet. BTW it might be easier to start with the radius 1 circle being a radius 2 circle. Makes finding the circumradius a bit easier.