Increasing kVp does NOT increase the amount of scatter photons produced( 2:40). As kVp increases, the photons are more likely to pass through without interacting at all. If they do interact and scatter, they will scatter with greater retained energy and are more likely to reach the IR, thus causing worse scatter fog despite fewer raw numbers of scattered photons.
Sir i am so confused. According to what you explained and also as mentioned in Farr's physics ( increasing kV dose increase scatter, and decreasing kV does reduce scatter) The RCR put a sample of MCQS, one of them was : High energy radiation is scattered more than lower energy radiation. Then my answer was true, but when i went to revise my answer infound it false because there answer was false !! So i am so confused. Can you help please?
Lots of people find this confusing. Increasing kV results in less attenuation and less scatter radiation (more of the x-rays are transmitted and less are attenuated via photoelectric effect and scattered via compton). It is the photoelectric effect and compton scatter that contribute to anatomic detail and spatial resolution. At higher kVs compton scatter is proportionally more than photoelectric effect despite both being reduced at higher kVs. At lower kVs photoelectric effect predominates - therefore, there is proportionally less scatter. I hope this makes some sense. At low kVs there is technically more scatter but proportionally there is more scatter at higher kVs.
As you knock electrons out of their inner shells you produce secondary radiation in the form of Characteristic radiation, rather than Brem, which can then continue the process of scatter as the secondary radiation interacts with tissue/matter around it.
Increasing kVp does NOT increase the amount of scatter photons produced( 2:40). As kVp increases, the photons are more likely to pass through without interacting at all. If they do interact and scatter, they will scatter with greater retained energy and are more likely to reach the IR, thus causing worse scatter fog despite fewer raw numbers of scattered photons.
Your explanation makes so much sense. Please make more Radiography related videos.
So helpful! Thank you !
More matter - more scatter
Sir i am so confused.
According to what you explained and also as mentioned in Farr's physics ( increasing kV dose increase scatter, and decreasing kV does reduce scatter)
The RCR put a sample of MCQS, one of them was :
High energy radiation is scattered more than lower energy radiation. Then my answer was true, but when i went to revise my answer infound it false because there answer was false !!
So i am so confused.
Can you help please?
Lots of people find this confusing. Increasing kV results in less attenuation and less scatter radiation (more of the x-rays are transmitted and less are attenuated via photoelectric effect and scattered via compton). It is the photoelectric effect and compton scatter that contribute to anatomic detail and spatial resolution. At higher kVs compton scatter is proportionally more than photoelectric effect despite both being reduced at higher kVs. At lower kVs photoelectric effect predominates - therefore, there is proportionally less scatter.
I hope this makes some sense. At low kVs there is technically more scatter but proportionally there is more scatter at higher kVs.
@@michael_nel thank you for your interaction, you can say that i started to understand it but not completely however I'm still searching for it
What happens after with an electric photon ?? Is it possible to produce bremsstrahlung inside the human body through this interaction ??
As you knock electrons out of their inner shells you produce secondary radiation in the form of Characteristic radiation, rather than Brem, which can then continue the process of scatter as the secondary radiation interacts with tissue/matter around it.
@@KuumaTheBronzeit can even cause inverse Compton scattering.