The PA = LU factorization with row exchanges

[@Rishun]

I followed along with a matrix for my homework and it seemed so much easier than what I remember doing while looking purely at class notes. Thanks!!

[@kevinebedi5257]

Honestly there was a particular segment i was looking for for days and you just absolutely breezed it well . Thank you very very much
. God bless you

[@rianferreira]

not every hero wears a cape

[@jaredtweed7826]

To generalize what she said:
Use Gaussian Elimination to find U (the diagonal values do not have to be 1).
PA is the matrix found after row swapping (but before row subtraction) during the Gaussian Elimination. P is the diagonal matrix after row swapping.
The L matrix has 1s along the diagonal, and the other lower triangular values are the values at their location with the value they had when eliminated to zero during Gaussian elimination divided by the pivot value of that column (at that same time).
Gaussian elimination eliminates the top, to the bottom, then to the right

[@bella-rp2rw]

Hi,i am an Italian student at the first year of computer science engineering.You did in 5 minutes what my teacher has done in more than 1 hour(teaching it very bad),i want to say you thanks.

[@ALIALI-k8w2l]

Hi , I am a s student at the first year in computer science at the university of HIT China also our teacher take two hours to explain it in a very boring way. thank you to share your story

[@slash.9882]

straight to the point, thank you

[@deepanshuchaudhary9875]

Thank You so much, you explained it really well.

[@Florent04]

Great video, thank you.

[@granthuang577]

The explanation really helps!!! Thanks a lot.

[@jaromatt3747]

good quality of sound and image! perfect information! But i scipped the first minute.

[@pauste2459]

Thank you for that great explanation!

[@jonasasare5775]

Wow perfectly explained. Thank you for such a clear explanation

[@ThuyTran-bw7dq]

Amazing, thank you!

[@dachirukhadze3848]

Thanks!

[@El_prof86]

Thanks !!

[@halilibrahimkocak267]

hello, I think there is a problem with the matrix L. it should be 1 0 0 / 0 1 0 / -2 -3 1. Is it true?

[@vlahuizabela]

Hi Halil, thanks for the question. The forward operations shown in pink take us from PA to the matrix U. The matrix L should take us back from U to the matrix PA. So, the way we obtain L is by applying the green operations, in the reverse order, to the identity matrix (1's along the diagonal, 0's everywhere else). To convince yourself why your answer would not work, you can simply multiply L times U and see what you get. You should get the matrix PA (the matrix obtained after exchanging the first two rows of A). The matrix L in the video is correct.

[@halilibrahimkocak267]

@@vlahuizabela I get it now thank you so much

[@vlahuizabela]

@@halilibrahimkocak267 any time

[@richmondanaman3819]

@@vlahuizabela Great answer 👍

[@happyhappypakistan1439]

@@vlahuizabela if I have any question then how can concern you other than this comment box
Because many times I have lost this comment box discussion

[@dexterngalati847]

thank you

[@yaswanth7856]

Thanks

[@akeemolowolayemo6176]

Izy Pls, which software did you use to write the presentation? Thanks

[@matthewwebb69]

It’s GoodNotes on iOS 🤝

[@aleksailic6231]

i love you

[@murathanbakr1268]

malum aile herkesin aklında geziniyor soruyu çözerken

[@uzivatel123]

thank you

[@tim-duncan2137]

thanks