Fault Analysis in Power Systems Part 3a

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  • Опубликовано: 18 ноя 2024

Комментарии • 43

  • @Generalpac
    @Generalpac  11 месяцев назад

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  • @nomanabuelgasim6213
    @nomanabuelgasim6213 3 года назад +1

    Thanks for high efforts
    finding the voltage at 13.8 bus you need to take the value of current with negative sign

    • @Generalpac
      @Generalpac  3 года назад +1

      Hi Noman,
      Thanks for your encouraging remarks, it boosts us to bring you more value via our content.
      Thank you for pointing this out. We have noted your concern and will make the required changes. We appreciate your help in this regard.
      GPAC Team

  • @useasucan6654
    @useasucan6654 Год назад +1

    7:25 why the IA value is 8367

    • @Generalpac
      @Generalpac  Год назад

      Hey, you are right. It is a typo there. Thanks for sharing.

  • @Dan47435
    @Dan47435 6 лет назад +3

    I'm a bit confused, at one instance you have the positive sequence current I_A(1) = 8367 A @ -90 deg. But later you have the same quantity = 8367 A @ 0 deg.? and then back to -90 deg. Which one is it?
    Can't wait for the next video! Love these.

    • @Generalpac
      @Generalpac  6 лет назад +7

      At instant 7:27 The value of Ia(1) is equal to 8367 angle -90 degrees and not 8367 angle 0 degrees.

    • @Dan47435
      @Dan47435 6 лет назад

      @@Generalpac Ok great thanks.

  • @nathan_falkon36
    @nathan_falkon36 2 месяца назад

    Hi, first of all, thank you for your lessons, they have been very helpful.
    So, as some people already pointed out, you used V_Base the same as V_Fault, shouldn't it be the same V_Base = 115kV? You could change the V_Base at your will, but the I_A = -j6,6667 pu was already calculated using the V_base= 115kV, if it were to change the V_base to 13.8kV, shouldnt we recalculate IA?
    And again, thank you very much for your effort, from the multiple courses/classes i've seen on youtube, yours has been the most intuitive and simple approaching this complex subject.

  • @tamjidkabir1543
    @tamjidkabir1543 2 года назад

    Your tutorials are awesome.

  • @ricardocorrea52
    @ricardocorrea52 6 лет назад +1

    We are very anxious for new videos...we are studying from Brazil...please carry on!

    • @Generalpac
      @Generalpac  6 лет назад

      Watch part 3b, 3c-1, and 3c-2 here: www.patreon.com/generalpac/posts?tag=fault%20anlaysis If you are not a patron, you are missing out! Only our patrons get access to the latest GPAC Video Tutorials. That will help us to carry on =)

  • @mindybillion888
    @mindybillion888 2 года назад

    Very good video, thank you so much for sharing and excellent explanation . I love this video.

    • @Generalpac
      @Generalpac  2 года назад

      Thank you for your positive feedback, its really encouraging for us :) We've a course for you which covers a variety of Power System concepts with detailed explanation and we're offering free 30-Days trial. You can have a look at it here: bit.ly/PSEVlog

  • @patsmocke1666
    @patsmocke1666 7 месяцев назад

    Love all your videos. One question though, at 7:44, why does the angle of IA1 change by -90 degrees for phase B and C? Shouldn't the "a" operator be the only thing changing the angles because this is a symmetrical fault? I would have thought they'd just be off by 120 degrees of each other.

  • @milanmakwana3883
    @milanmakwana3883 6 лет назад +1

    Very good sir but can you help me how to calculate or measure positive ,negative and zero sequence impedance please make one video about this topic.

  • @zhonglei3126
    @zhonglei3126 6 лет назад

    it is really useful video, eager to watch the next video.

  • @xmas432
    @xmas432 6 лет назад

    Excellent stuff, can’t wait until till the next video!!

  • @rejijoythoppil4019
    @rejijoythoppil4019 2 года назад

    In calculating the base current the units considered for power is in MVA and that for voltage is in KVA , Hence it seems the base current unit should be in KA rather than A , Kindly advise on the same .

    • @Generalpac
      @Generalpac  2 года назад

      Hi Thoppil, Yes you are right. The answer should be in kA, but here the provided answer is given directly after making all the conversion.
      You can verify the answer with the below mentioned calculation:
      Ibase = 30 MVA / √3*13.8kV
      Ibase = 30,000 kVA / √3*13.8kV (1 MVA= 1000 kVA)
      Ibase = 1255 Amp
      Thanks,
      GeneralPAC by AllumiaX

  • @曾芷喬-u9u
    @曾芷喬-u9u 6 лет назад +2

    Sir, why is the calculation of Base current = S_base / (sqrt 3 * V_fault)?
    Shouldn’t it be S_base / (sqrt 3 * V_base)?
    And u mentioned that the selected base voltage is 115kV as it is the generator bus voltage.
    Thanks.

    • @Generalpac
      @Generalpac  5 лет назад +1

      We used the 13.8Kv in the base calcs because we want to find the fualt current on the 13.8kV or LV side of the transformer.

    • @henokteshager4049
      @henokteshager4049 Год назад +1

      @@Generalpac So which does this mean that we are going to use 115kV if the fault was happed in the HV side?

  • @VivekSharma-ng6yk
    @VivekSharma-ng6yk 6 лет назад

    Thankyou very much sir, it was nicely explained by you. Waiting for next videos to come in fault analysis.

  • @apostolosmavropoulos177
    @apostolosmavropoulos177 5 лет назад +2

    At 5:22 why use the 13.8 kV to find I_base when we have selected 115 kV as V_base? And at 10:00 isn't the per unit +sequence current -j6.667p.u ? why use +j6.667p.u ? I suppose this is a rookie error as the result is 2,00005 p.u ....while with the -j6.667p.u the result is 0.00005

    • @Generalpac
      @Generalpac  5 лет назад +3

      We used the 13.8Kv b/c we are determining the fault current on the LV or 13.8KV side of the transformer. If wanted to find the same fault current on the HV or 115kV side, then we will use 115kV in the base current calcs. We actually determine the fault current on the HV side later in this series :)
      Yes at @10:00 the per unit + sequence should be -j6.667pu (i forgot the minus sign) -- this gives us the same result.
      V_A^((1) )=1∠0°-(j0.15)*(-j6.667)=0pu
      Thanks,

    • @apostolosmavropoulos177
      @apostolosmavropoulos177 5 лет назад

      @@Generalpac Thank you for answering! Your work is top class really! I managed to grasp these fundamental concepts easily! I wish you the best

  • @ThomasTurkington
    @ThomasTurkington 5 лет назад

    Excellent Videos... They are extremely helpful! I have a question at 10:40. It is stated previously that the -ve and zero sequence voltage values for Va are also 0 for a balanced system. But when the equations are evaluated, you use 1 angle 0 for the -ve and zero sequence Va values in equations Vb and Vc. Should it not be 0 angle 0 for the -ve and zero sequence Va values?

  • @Generalpac
    @Generalpac  4 года назад +1

    Support us by becoming our patron at ​patreon.com/generalpac ....Why?
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  • @shihabahmedalkatrani3050
    @shihabahmedalkatrani3050 3 года назад

    Thanks 🙏

  • @Nothing-bb6pu
    @Nothing-bb6pu 5 лет назад

    When you calculate the base current why did you but voltage =13.8Kv , instead of 115Kv Which is the Voltage base you used in the previous video?

    • @noukimi0582
      @noukimi0582 4 года назад

      I had the exact same question but I guess he never answered your question

  • @wonderbee100
    @wonderbee100 3 года назад +1

    At 7:26, the angle should have been -90 degrees....

  • @vividhansda4167
    @vividhansda4167 6 лет назад

    Thank you very much sir

  • @mgotovac
    @mgotovac 3 года назад +1

    Hope you realize there are no generators rated voltage 115 kV and rated power 600 MVA.
    Also for phase current Ib there should be a*inverse_component instead of a^2*inverse_inverse component.

    • @Generalpac
      @Generalpac  3 года назад

      This is more of an academic / intellectual exercise per the book example. Definitely not "real world application" as you suggested

    • @mgotovac
      @mgotovac 3 года назад +1

      @@Generalpac Of course if you switch base voltages to be more realistic, the calculation is the same in p.u. system. That is the beauty of it..

  • @josephlo6005
    @josephlo6005 6 лет назад

    Please can you upload Part 3b

  • @Generalpac
    @Generalpac  Год назад

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  • @shubhamvats3273
    @shubhamvats3273 6 лет назад

    Awesome sir very helpful
    Thank you
    Sir may we all students have a wahatsapp study group under ur guidance please sir make a group

  • @Generalpac
    @Generalpac  Год назад

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