Data-Driven Control: Change of Variables in Control Systems

Поделиться
HTML-код
  • Опубликовано: 28 окт 2024

Комментарии • 12

  • @DieselBoulder
    @DieselBoulder 3 года назад +2

    Sweet baby jesus!!! THIS LECTURE SERIES IS F*CKING AWESOME!!!!!!

  • @sounghwanhwang5422
    @sounghwanhwang5422 4 года назад +2

    Hi Steve! I think this video is the most interpretable and wonderful lecture that illustrates the entire concept of model reduction and balanced truncation and thank you for your dedicated efforts. I have a question about the balanced truncation method. Is this way still can be an applicable way when dealing with nonlinear systems? Thank you so much!!

  • @shengjianchen4231
    @shengjianchen4231 4 года назад +12

    Hi Steve, start from 11:45, I am still confused about why we can pop out the inv(T). You said we assume T is some eigenvectors or orthogonal... But how this assumption help us eliminate the exponential?

    • @Eigensteve
      @Eigensteve  4 года назад +16

      Really good question. In the definition of the matrix exponential, e^{B} = I + B + (1/2)B^2 + (1/3!)B^3 + ..., if we plug in invT * A * T, we get
      e^{invT * A * T} = I + invT*A*T + (1/2)(invT*A*T*invT*A*T) + (1/3!)*(invT*A*T*invT*A*T*invT*A*T) + ...
      you can write I=invT*T and then we get
      e^{invT * A * T} = invT*T + invT*A*T + (1/2)(invT*A*T*invT*A*T) + (1/3!)*(invT*A*T*invT*A*T*invT*A*T) + ...
      = invT* ( I + A + (1/2)*A^2 + (1/3!)*A^3 + ... ) * T
      = invT * (e^A) * T*
      See time 16:00 in the following video: ruclips.net/video/nyqJJdhReiA/видео.html

    • @shengjianchen4231
      @shengjianchen4231 4 года назад

      Almost forget this. Thanks for pointing out! As I watch the following video, another question pop out. At 2:50, you assume ~wo and ~wc are diagonal. But we don't have such assumption for original wo and wc. I can see this makes calculating T and scale it easier. Can we can also do that without this assumption ?

    • @Eigensteve
      @Eigensteve  4 года назад +6

      Yeah, here, we are assuming that we have performed the balancing transformation that makes these two Gramians equal and diagonal. It is not obvious that this is possible, but it is. I show how to derive this transform in ruclips.net/video/IlrnTjwujBk/видео.html

    • @mkelly66
      @mkelly66 3 года назад

      Wow! That was so unexpected. Amazing!

    • @ahmedkamiss7643
      @ahmedkamiss7643 3 года назад

      @@Eigensteve Thank you for the explanation and @shengjian thank you for the question !

  • @andremarcorin
    @andremarcorin 5 месяцев назад

    awesome videos, thanks a lot for sharing!

  • @adrianom
    @adrianom 3 года назад +3

    Hi! Very nice video, but I think there is a small mistake towards the end.
    hat(A)*= T* A* T-* (then T* and T-* cancel out correctly in the integral) :)

    • @adrianom
      @adrianom 3 года назад

      I've just seen you corrected that in the next video of the series. Keep up the good work!