Man, you are seriously underrated. I am an A* scoring student but because I was unwell, I missed some crucial physics lessons. Your video truly enhanced my conceptual understanding.
at 21:50, how is the heat used only to break the bonds but the kinetic energy/heat doesn't increase? in order to break the bonds, the kinetic energy or temperature need to increase in order for collisions to occur and the particles to become spread out. I don't understand how the bonds would get broken if the kinetic energy isn't increasing. thank you for the great video btw!
i was honestly thinking the same thing, fellow learner (i dunno what i said it like that, ignore it) but ig the reason would be that, the temperature could be constant, but the substance is still gaining energy from it... like for example, you're heating... ehh something? and you put it on the stove on minimum (constant, it doesnt change through out the period), and you leave it for... like 4 hours! the thing you would be heating would be burning hot, or turned into liquid/gas! even doe the heat was constant. A constant heat is enough to break the attractive forces/bond of the substance! i have no idea if this is correct... lemme know if you know the correct answer. :,,,)
As far as I recall, I think during the bond breaking phase, energy is only being used for that particular process. And once all the bonds are broken then the k.e. should start increasing. again not too sure (also a fellow learner), but if someone could confirm if this is the case - that’ll be appreciated
see energy is 21000 and mass is 0.50 with the tempurature of 10* now the formula is E divided by tempurature multiplied by mass first you should do multiplication that is (0.50) (10) this gives you 5 now divide 21000 with 5 the answer is 4200 hope it help.
![IGCSE Physics [Syllabus 2.3] Thermal processes](http://i.ytimg.com/vi/pbiHeIH_AZI/mqdefault.jpg)
![IGCSE Physics [Syllabus 2.3] Thermal processes](/img/tr.png)
![IGCSE Physics [Syllabus 2.1] Kinetic molecular model of matter](http://i.ytimg.com/vi/kVKBM53U8oY/mqdefault.jpg)
![IGCSE Physics [Syllabus 5.1 - 5.2] Atomic physics](http://i.ytimg.com/vi/dMSWsLD-Zig/mqdefault.jpg)
![IGCSE Physics [Syllabus 3.1] Wave properties](/img/1.gif)
Man, you are seriously underrated. I am an A* scoring student but because I was unwell, I missed some crucial physics lessons. Your video truly enhanced my conceptual understanding.
Error correction:
24:50 The slide should say liquid -> gas instead
yeah i had doubt in it
understood
Your make concepts very easy to understand unlike our teachers back in Asia.
Pliz do a video like this for space physics also .it’s very helpful
32.44 min of Cambridge
😂😂😂😂😂❤❤relatable
Nice boy
This really helps a lot when revising or studying
It's explained in a way I can understand it better
Thank you
Happy to have found this channel 😊💕
At 24:50, it should be liquid to gas
I have a test on thermal physics tomorrow and this helps allt. Keep it up
@@kareemwail4495oh ok.
@@kareemwail4495 where are you from???
@@kareemwail4495 sameeeee
Same
@@kareemwail4495 same
can you publish a video for space physics unit for us.
best physics teacher right here
at 21:50, how is the heat used only to break the bonds but the kinetic energy/heat doesn't increase? in order to break the bonds, the kinetic energy or temperature need to increase in order for collisions to occur and the particles to become spread out. I don't understand how the bonds would get broken if the kinetic energy isn't increasing. thank you for the great video btw!
i was honestly thinking the same thing, fellow learner (i dunno what i said it like that, ignore it) but ig the reason would be that, the temperature could be constant, but the substance is still gaining energy from it... like for example, you're heating... ehh something? and you put it on the stove on minimum (constant, it doesnt change through out the period), and you leave it for... like 4 hours! the thing you would be heating would be burning hot, or turned into liquid/gas! even doe the heat was constant. A constant heat is enough to break the attractive forces/bond of the substance! i have no idea if this is correct... lemme know if you know the correct answer. :,,,)
As far as I recall, I think during the bond breaking phase, energy is only being used for that particular process. And once all the bonds are broken then the k.e. should start increasing. again not too sure (also a fellow learner), but if someone could confirm if this is the case - that’ll be appreciated
@@akhilkommuru that is correct :)
13:42 it should be 1jouls per gram
THANK YOU FOR THIS
this is so helpful. thank you.
At 7:30 is it freezing or melting point?
it is both the freezing and the melting point . it will alway be the same through out the world not in the space !
THANK YOU
Can u plz explain how a thermometer works
The liquid in the bulb expands uniformly as temperature rises causing it to travel up the capillary tube.
youre the best amigo
I did the formula at 19:06 and I get 42000j not 4200j so is it correct and if not so what have i done wrong
see energy is 21000 and mass is 0.50 with the tempurature of 10* now the formula is E divided by tempurature multiplied by mass first you should do multiplication that is (0.50) (10) this gives you 5 now divide 21000 with 5 the answer is 4200 hope it help.
Video not match name of channel
Indian?
This Channel Indian not British
@@abhinav2530 What do you mean by this
THANKYOU SOOOOOOOOOOOOO F MUCHHHHHHHHHHHHHHHHHHH
Hey first of all thank you for video. Please how can we download these presentations from you?
I'm not sure if you need it now but he has a website with all of the notes
you are a god
Nice
Where is ur first vid for thermal physics?
check his channel, the thumbnail is also thermal physics but look at the title carefully.
❤
Hello 👋👋👋👋👋
I found no confidence in your voice. This video was helpful but off.
Well it's been up to 3yrs n I hope you've improved