Harvard University Logarithms Admission Exam || Ivy League Schools Math || Exponential Aptitude Test

[@shrikrishnagokhale3557]

Very interesting!Thanks.

[@superacademy247]

Glad you liked it! You're welcome 😊

[@neilmccafferty5886]

What a mission.

[@yuriandropov9462]

(,log3-2)**2=(-2+log3)**2=(2-log3)**2. Knowing that 2>log3, we have 2-log3>0 therefore sqrt((2-log3)**2)= 2-log3.

[@RealQinnMalloryu4]

W^{(x+3)(x ➖ 3)Log(3x+9)(3x ➖ 9)}^w=w^{9x2+9x^2}^w Logw^{9x^2+18}^w=w^{18x^4+27x^2}^w= 45x^6 3^15x^6 3^3^5x^3^2 1^1^1^x^3^2 x^3^2(w^{ x ➖ 3x+2}^w).10/3 =3.1 (x ➖ 3x+1).