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Very interesting!Thanks.
Glad you liked it! You're welcome 😊
What a mission.
(,log3-2)**2=(-2+log3)**2=(2-log3)**2. Knowing that 2>log3, we have 2-log3>0 therefore sqrt((2-log3)**2)= 2-log3.
W^{(x+3)(x ➖ 3)Log(3x+9)(3x ➖ 9)}^w=w^{9x2+9x^2}^w Logw^{9x^2+18}^w=w^{18x^4+27x^2}^w= 45x^6 3^15x^6 3^3^5x^3^2 1^1^1^x^3^2 x^3^2(w^{ x ➖ 3x+2}^w).10/3 =3.1 (x ➖ 3x+1).
Very interesting!Thanks.
Glad you liked it! You're welcome 😊
What a mission.
(,log3-2)**2=(-2+log3)**2=(2-log3)**2. Knowing that 2>log3, we have 2-log3>0 therefore sqrt((2-log3)**2)= 2-log3.
W^{(x+3)(x ➖ 3)Log(3x+9)(3x ➖ 9)}^w=w^{9x2+9x^2}^w Logw^{9x^2+18}^w=w^{18x^4+27x^2}^w= 45x^6 3^15x^6 3^3^5x^3^2 1^1^1^x^3^2 x^3^2(w^{ x ➖ 3x+2}^w).10/3 =3.1 (x ➖ 3x+1).