Mod-04 Lec-14 Tunneling through a Barrier

Поделиться
HTML-код
  • Опубликовано: 18 янв 2025

Комментарии • 40

  • @doutormanhattan5680
    @doutormanhattan5680 5 месяцев назад +2

    I spent a lot of time looking for a teacher like that. I'm glad I found you. I knew it was going to be an indian guy. I also watch For The Love of Physics videos.

  • @josephmcmahon4139
    @josephmcmahon4139 6 лет назад +18

    more helpful than my prof I have for Quantum Mechanics I at Georgia Tech. I'm studying for the final right now and you cleared up a lot of confusion. Thank You

    • @wankmaster69
      @wankmaster69 5 лет назад +1

      Don't forget to increase playback speed to 1.5 lol

    • @salu30000
      @salu30000 3 года назад

      @@wankmaster69 correction - 2x , he could actually complete the lecture in half the time he had taken , if he had wanted

  • @KasperKubica
    @KasperKubica 10 лет назад +3

    I love this guy. He makes everything so simple and lucid.

  • @tayyabanawaz5265
    @tayyabanawaz5265 6 лет назад +3

    Want such a teacher to teach quantum mechanics😢😢

  • @Khalil9497
    @Khalil9497 9 лет назад +5

    Thank you very much, i'm so thankful

  • @elamvaluthis7268
    @elamvaluthis7268 2 года назад

    Very nice explanation beyond doubt.

  • @zarinamingazheva482
    @zarinamingazheva482 4 года назад +1

    Thank you for the helpful lecture. Should be the equation at the time 27:34 A*(1-ik/kappa)+B(1+ik/kappa)=2C?

  • @Mohitmccall
    @Mohitmccall 4 года назад +2

    27:35 sir when we added up that two eq's then RHS should be 2C !?

    • @srijanraghunath4642
      @srijanraghunath4642 4 года назад

      No it should actually be 2D. After he divided by kappa u distribute negative and then when u add equations C cancels but the two Ds get added together

    • @salu30000
      @salu30000 3 года назад

      @@srijanraghunath4642 yes you are right

  • @sunnypala7629
    @sunnypala7629 6 лет назад

    Great respect for you sr.

  • @sunnypala7629
    @sunnypala7629 6 лет назад

    Sr brilliantly explained

  • @DeepikaGupta4721
    @DeepikaGupta4721 7 лет назад

    This Video is really helpful. Thank you so much Sir...

  • @shanmukarao7668
    @shanmukarao7668 4 года назад

    At 8:34 professor said last lecture can anyone tell me where is that last lecture plz send me the link

  • @TravelwithAmit-yy7rn
    @TravelwithAmit-yy7rn 5 лет назад

    there is a little mistake @28:01

  • @vinayrana610
    @vinayrana610 6 лет назад

    well explained ajoy sir

  • @juniedtazrian593
    @juniedtazrian593 4 года назад

    how the transmission probability changes with the change of a moving microscopic particle?

  • @surajpradhan8606
    @surajpradhan8606 6 лет назад +1

    So, quantum mechanics allows a particle to have negative kinetic energy ?

    • @entrainer6709
      @entrainer6709 6 лет назад

      No then eigenvalu of hamiltonian operator for kinetic energy will be - ve

    • @surajpradhan8606
      @surajpradhan8606 6 лет назад

      Jitendra Prajapat
      Yes, the total energy can be negative which refers to a bound state. Here, the kinetic energy is not negative but less than the potential barrier. And QM says it has some finite probability of tunneling through the barrier. How amazing !

    • @entrainer6709
      @entrainer6709 6 лет назад

      @@surajpradhan8606 thnx a lot of sir kaha se ho plz

    • @surajpradhan8606
      @surajpradhan8606 6 лет назад

      @@entrainer6709
      Sambalpur, Odisha

    • @kanhaiyalal-kv2vg
      @kanhaiyalal-kv2vg 5 лет назад

      even negative kinetic energy also allowed in qm

  • @ruchijha6162
    @ruchijha6162 6 лет назад +1

    if all the energy gets reflected from where does the energy for evanescent wave come from in ftir?

    • @PhysicsMath
      @PhysicsMath 6 лет назад

      E-t uncertainty for short time..

    • @kanhaiyalal-kv2vg
      @kanhaiyalal-kv2vg 5 лет назад

      @@PhysicsMath No,in classical mechanics uncertainty not allowed

  • @ashugoyal2231
    @ashugoyal2231 6 лет назад +1

    In the last lecture you have taken C constant with e to the power positive something and here you have taken constant C with e to the power of negative something.
    Pls explain this.
    Anyone??

    • @nicholeoneill4085
      @nicholeoneill4085 6 лет назад +1

      The positive and negative exponents reflect the direction of propagation or decay. Here he is using Ce^-kx to denote the decay of the wave once it's within the barrier. I don't know what the last lecture was or the equation, but I'm willing to bet it was describing a wave that propagated through a single wall and is now traveling in the positive x direction. If you go back to when he derives psi for region II (in this video) he explains why the exponent is negative (after he discusses evanescent waves).

  • @elamvaluthis7268
    @elamvaluthis7268 3 года назад

    Transcend/go beyond.

  • @ruby4244
    @ruby4244 7 лет назад

    Thankyou sir great

  • @Anonymous-do6ck
    @Anonymous-do6ck 6 лет назад

    sir how is this possible that v0 is greater than energy E?

    • @surajpradhan8606
      @surajpradhan8606 6 лет назад +2

      jarur Kandulna V0 greater than E is not surprising as it is possible. But, how quantum mechanics allows a particle to have a negative kinetic energy is amazing.

  • @ashkaralam845
    @ashkaralam845 7 лет назад

    Thanks you sir

  • @007acreed
    @007acreed 7 лет назад

    Thanks Sir