Java Streams Interview Question - 06 - Print Duplicate Numbers using Streams

[@vanishreeism]

Actual filtering is happening due to the feature of set and due to Collections.frequency operation. To prove this try collecting it to a list instead of set

[@amritapriyadarshini511]

Thanks Naveen...One of my friend suggested me..to watch your videos which is so helpful for me.I got job.todY as automation engineer..thank you so much.

[@AnilSharma-fb3ze]

Thank you Naveen, it is greatful to use Streams

[@mohammedsufi4649]

Thank you so much for the video. Very useful. Please keep it up

[@priyaranjan1973]

Set all=l.stream().filter(
n-> l.stream().filter(x->x==n).count()>1
).collect(Collectors.toSet());

[@spider-maniac300]

This was good !

[@prasantaweekends]

Thanks Naveen. It's very helpful

[@deepanshurathore9661]

I think Set method is optimised take O(n) time . freq method might be take O(n2) time

[@vengateshm2122]

Very useful. Thank you.

[@muthikinaveen2195]

Can you please explain using stream how find out highest occurrence number in array

[@arunsinghrajpoot5363]

Thanks bro

[@smsms8522]

We have distinct functionality in streams. numbers.stream().distinct();

[@ankarigaripriyanka8306]

never heard we could do it this way also

[@sanoopk8847]

Waiting for more videos

[@mastermind6269]

second solution would not work if we have accourence more than two times, we have to use distinct() method there!

[@madarauchiha-dr5ws]

No need to use collectors.toset(), collectors.toList() will work. Can someone please correct me if I am wrong

[@ruishizhang1159]

List won't work if there is a tripled number

[@karamjitsinghsehdev3451]

How to get duplicates with their counts and return map?

[@priyansusekhar6123]

your teaching is very helpful but i think sir u don't know about distinct() method......

[@vinayfartyal3666]

Set set = new HashSet();
return list.stream().filter(num -> !set.add(num)) // Keep only duplicates
.distinct() // to ensure unique duplicates
.toList();